Structural Analysis

Chapter 9
Statically Indeterminate Structures: Force Methods

Bachelors Program in Construction Technology
Structural Analysis   •   Bachelor

Statically Indeterminate Structures: Force Methods

Introduction

A structure is statically indeterminate when the unknown reactions and internal forces exceed the number of independent equilibrium equations available. Equilibrium alone cannot determine its response. The additional information comes from compatibility of deformation and from constitutive relations such as Hooke’s law. Force methods, also called flexibility methods or consistent-deformation methods, exploit this fact by selecting a limited number of redundant forces, removing them temporarily, and enforcing the required displacement conditions.

Force methods are especially useful for indeterminate beams, trusses, and frames. They provide a direct physical interpretation of support settlement, temperature change, fabrication error, and imposed deformation. Although matrix stiffness methods are often preferred for large structures, force methods remain important because they clarify structural behaviour and provide valuable hand-calculation procedures for small and moderately complex systems.

Learning Objectives

After studying this chapter, the reader should be able to:

  1. distinguish statically determinate and indeterminate structures;
  2. calculate the degree of static indeterminacy of common structures;
  3. select suitable redundants and construct primary determinate structures;
  4. derive and apply flexibility and consistent-deformation equations;
  5. use unit-load and virtual-work methods to calculate deflections;
  6. include support settlement, temperature change, and fabrication errors;
  7. analyse indeterminate beams, trusses, and frames;
  8. interpret results, check equilibrium and compatibility, and identify limitations of the force method.

1. Fundamental Concepts

1.1 Equilibrium, compatibility, and material behaviour

Structural analysis rests on three complementary requirements:

  • Equilibrium: forces and moments balance at every joint and for the structure as a whole.
  • Compatibility: connected points deform consistently; supports impose prescribed displacement conditions.
  • Constitutive behaviour: stress and strain are related through material and section properties.

For a linearly elastic member, the basic relation is σ = Eε, where σ is normal stress, E is Young’s modulus, and ε is normal strain. For bending, curvature is related to bending moment by κ = M/(EI), where M is bending moment, E is the elastic modulus, and I is the second moment of area. For an axially loaded prismatic member, extension is governed by δ = PL/(AE), where P is axial force, L is length, A is cross-sectional area, and E is Young’s modulus.

These relations assume small deformation, linear elasticity, sufficiently rigid connections as idealized, and known member properties. Units must be consistent; for example, if P is in kN, L in m, and AE in kN, the resulting axial displacement is in metres.

1.2 Static indeterminacy

The degree of static indeterminacy is the number of force quantities that cannot be found from equilibrium alone. It is not the same as the number of redundant members or reactions in every possible formulation, because a different set of independent redundants may be selected.

For a stable planar truss, a commonly used relation is

Ds = m + r − 2j

where m is the number of members, r is the number of support-reaction components, and j is the number of joints. A value of Ds = 0 indicates a statically determinate truss if the structure is stable and properly arranged; a positive value indicates static indeterminacy, and a negative value indicates a mechanism or an unstable configuration. This relation applies to pin-jointed, planar, internally stable trusses.

For a planar rigid-jointed frame or beam, a useful count is

Ds = 3m + r − 3j

where m is the number of members, r is the number of external reaction components, and j is the number of joints. This count must be interpreted with care where releases, internal hinges, or special geometric conditions exist. A stable structure can also be geometrically indeterminate or unstable despite an apparently appropriate numerical count.

1.3 Redundants and the primary structure

A redundant is an unknown force or moment selected as an additional generalized force. To apply the force method:

  1. determine the degree of indeterminacy;
  2. select that number of redundants;
  3. remove the redundants to create a stable, statically determinate primary structure;
  4. calculate displacements caused by the applied loading;
  5. calculate flexibility coefficients caused by unit redundants;
  6. impose compatibility and solve for the redundants;
  7. superpose the redundant effects and recover reactions and member forces.

The primary structure must be stable and capable of carrying the real loading and unit-load cases. A poor choice may produce a mechanism, a very ill-conditioned flexibility equation, or unnecessary algebra.

2. The General Flexibility Method

Let the selected redundants be X₁, X₂, …, Xₙ. Let Δᵢ⁰ be the displacement at the coordinate of redundant i caused by the actual loads acting on the primary structure. Let fᵢⱼ be the displacement at coordinate i caused by a unit value of redundant j. Let Δᵢᵖ represent a prescribed displacement or an imposed deformation contribution at coordinate i. Compatibility requires

∑(j=1 to n) fᵢⱼXⱼ = Δᵢᵖ − Δᵢ⁰

or, in matrix form,

[f]{X} = {Δᵖ} − {Δ⁰}

Here [f] is the flexibility matrix, {X} is the vector of redundants, {Δ⁰} is the displacement vector due to applied loading on the primary structure, and {Δᵖ} is the prescribed compatibility displacement vector. The sign convention must be maintained consistently.

For a single redundant,

X = (Δᵖ − Δ⁰)/f

If the redundant is a removed support reaction and the support does not settle, Δᵖ = 0, giving X = −Δ⁰/f. If the support settles downward by a specified amount s, the signed value of Δᵖ must be used according to the selected positive displacement direction.

2.1 Flexibility coefficients and reciprocal relationships

The coefficient fᵢⱼ has units of displacement per unit force, or rotation per unit moment when the coordinate is rotational. For a prismatic beam in bending, the unit-load or virtual-work expression is

fᵢⱼ = ∫₀ᴸ (mᵢmⱼ)/(EI) dx

and the displacement due to actual bending moments is

Δᵢ⁰ = ∫₀ᴸ (Mmᵢ)/(EI) dx

where M is the bending-moment diagram from actual loads on the primary structure, mᵢ is the bending moment from a unit force or unit moment applied at coordinate i, x is the member coordinate, L is the member length, E is Young’s modulus, and I is the second moment of area. These equations assume small, linear-elastic deformation and bending deformation as the dominant contribution.

For axial trusses,

fᵢⱼ = ∑(k=1 to m) (nᵢₖ nⱼₖ Lₖ)/(AₖEₖ)

and

Δᵢ⁰ = ∑(k=1 to m) (Nₖ nᵢₖ Lₖ)/(AₖEₖ)

where Nₖ is the actual axial force in member k, nᵢₖ is the axial force in member k caused by a unit redundant i, Lₖ is member length, Aₖ is area, and Eₖ is modulus. Tension is conventionally positive, but any consistent sign system is acceptable.

For frames, axial, bending, and sometimes shear deformation may contribute:

Δᵢ⁰ = ∫ (Mmᵢ)/(EI) dx + ∫ (Nnᵢ)/(AE) dx + ∫ (Vvᵢ)/(κGA) dx

where V and vᵢ are actual and unit shear forces, G is shear modulus, and κ is the shear-correction factor. The shear term may be neglected for slender members but can be important in deep beams, short members, and some industrial frames.

The Maxwell–Betti reciprocal theorem gives fᵢⱼ = fⱼᵢ for a linear elastic structure under compatible loading. This provides both a conceptual result and a useful calculation check.

3. Consistent-Deformation Procedure

A reliable hand-analysis sequence is as follows.

Step 1: Idealize the structure

Identify supports, releases, member properties, loadings, and possible symmetry. Define positive directions for forces, moments, translations, and rotations.

Step 2: Determine indeterminacy

Use equilibrium and structural counts, then inspect stability and internal releases. Do not rely solely on a numerical count.

Step 3: Choose redundants

Select reaction components or internal forces whose removal leaves a stable determinate structure. A redundant should correspond to a clear displacement or rotation compatibility condition.

Step 4: Analyse the primary structure

Remove the redundants and apply the real loads. Determine internal force diagrams or member forces.

Step 5: Apply unit redundants

Apply a unit force or unit moment at each redundant coordinate, one at a time. Determine the corresponding unit internal-force diagrams.

Step 6: Evaluate flexibility quantities

Use virtual work, integration, tables, or numerical integration to obtain Δ⁰ and fᵢⱼ.

Step 7: Impose compatibility

Write the flexibility equations, including support movement, temperature effects, and fabrication errors where relevant.

Step 8: Recover the complete response

Superpose the primary-structure response and redundant effects. Calculate reactions, shear, bending moment, axial force, and deflection as required.

Step 9: Check the result

Check global equilibrium, boundary conditions, symmetry, units, signs, and whether the redundant actually produces the required compatibility condition.

4. Worked Example: Propped Cantilever Beam

Consider a prismatic beam of length L fixed at A and vertically supported by a prop at B. A downward point load P acts at a distance a from A. The vertical reaction at B, R_B, is selected as the redundant. Removing B leaves a cantilever, which is the primary structure. Assume constant EI, small deflections, and a downward-positive displacement convention for this example.

The downward deflection at B caused by P on a cantilever is

ΔB⁰ = P a²(3L − a)/(6EI)

The downward deflection at B caused by an upward unit force at B has magnitude

fBB = L³/(3EI)

Because the actual reaction R_B acts upward and the required displacement at B is zero,

ΔB⁰ − RB fBB = 0

Therefore,

RB = P a²(3L − a)/(2L³)

The sign is upward for a downward applied load. The fixed-end vertical reaction is then obtained from vertical equilibrium:

RA = P − RB

The fixed-end moment follows from moment equilibrium about A:

MA + RB L − Pa = 0

so

MA = Pa − RB L

For example, if P = 20 kN, L = 6 m, and a = 4 m,

RB = 20 × 4² × (3×6 − 4)/(2×6³) = 9.63 kN

Thus R_A = 10.37 kN. The fixed-end moment is M_A = 20×4 − 9.63×6 = 22.22 kN·m in the sign convention stated. Substitution into equilibrium verifies the result. Notice that EI cancels because both the load displacement and the flexibility contain the same factor 1/EI. This cancellation occurs only because the member is prismatic with constant EI and the same deformation mode governs both terms.

If the prop settles by a known amount, the compatibility equation becomes

ΔB⁰ − RB fBB = s

where s is the signed prescribed displacement. Settlement therefore changes the reaction even when the applied loading is unchanged. In an indeterminate structure, imposed displacement generally produces internal forces; in a determinate structure, it usually produces movement without force, provided no secondary restraint prevents it.

5. Beams and Frames

5.1 Beams

For continuous beams, common redundants include an intermediate support reaction or an internal bending moment. A removed support produces a translational compatibility condition; a released internal moment produces a rotational compatibility condition. At an ordinary continuous beam joint, the rotation is continuous unless a hinge is present. At a fixed support, both translation and rotation are prescribed, usually zero unless settlement or rotation is specified.

The bending flexibility equation can be assembled from piecewise moment functions. If E and I vary along the beam, they must remain inside the integrals:

Δᵢ⁰ = ∫₀ᴸ Mmᵢ/(E(x)I(x)) dx

Using a constant EI when stiffness varies can produce incorrect force distribution even when equilibrium is satisfied.

5.2 Rigid frames

Frame analysis requires attention to axial deformation, bending deformation, and joint kinematics. For a rigid joint, connected members share the same joint translation and rotation. For a hinge, moment transmission is zero, but translations remain compatible. A selected redundant may be a horizontal reaction, vertical reaction, or joint moment.

In a portal frame, temperature differences between the two faces of a member can cause curvature and joint displacement. Frame flexibility calculations should include these effects when they are significant. The force method is particularly transparent for a small frame with one or two redundants, but becomes algebraically cumbersome as the number of redundants increases.

6. Trusses and Axial Deformation

For a truss, members are idealized as pin-connected and carry axial force only. The unit-load method is especially efficient. To find a displacement at a joint, apply a unit load in the desired direction and use

δ = ∑ (Nₖ nₖ Lₖ)/(AₖEₖ)

where Nₖ is the actual member force and nₖ is the member force due to the unit load. The product Nₖnₖ automatically accounts for compression and tension signs.

For an indeterminate truss with one redundant member force X,

δ⁰ + fX = δᵖ

where δ⁰ is the redundant-coordinate displacement caused by real loads, f is the flexibility coefficient, and δᵖ includes any prescribed joint displacement. If the redundant is a member that was cut, the compatibility condition usually requires the relative displacement between its cut ends to equal the extension associated with fabrication error or temperature change.

Fabrication error in a truss

Suppose a removed member has an initial length error e, positive when it is too long according to the adopted convention. The compatibility equation becomes

δ⁰ + fX = e

The resulting force is present even without external loading. This is a characteristic feature of indeterminate structures: forcing an incorrectly fabricated member into position creates self-equilibrated stress.

7. Support Settlement, Temperature, and Lack of Fit

7.1 Support settlement

A support settlement is a prescribed displacement, not an applied external force. It must be introduced on the compatibility side of the flexibility equation. For multiple redundants, the vector {Δᵖ} contains the displacement prescribed at each redundant coordinate. Settlement should be entered with a sign consistent with the positive coordinate direction.

7.2 Uniform temperature change

A freely expanding prismatic member experiences thermal extension

ΔT = αΔT L

where α is the coefficient of thermal expansion, ΔT is the temperature change, and L is member length. If the member is fully restrained axially, the elastic stress in a simple uniform member is approximately

σT = −EαΔT

for heating under complete restraint, ignoring creep, relaxation, and temperature-dependent properties. The corresponding force is NT = −EAαΔT. In a structural system, the actual force depends on the flexibility and restraint configuration, so the free expansion must be included as an imposed deformation rather than automatically applying the fully restrained formula.

A temperature gradient through a member depth produces curvature. If the temperature difference between two faces is ΔT_g across depth h, an idealized curvature is approximately

κT = αΔTg/h

The sign depends on which face is hotter. Real members may require consideration of nonuniform temperature fields and composite action.

7.3 General compatibility including imposed effects

A useful conceptual form is

{Δ⁰} + [f]{X} + {Δᵢₘₚ} = {Δᵖ}

where {Δᵢₘₚ} represents free deformation from temperature, lack of fit, support movement internal to a released member, or other imposed effects. Rearrangement gives the redundant forces. This equation emphasizes that force methods are not restricted to gravity loading.

8. Detailed Applied Case: Continuous Floor Beam with Support Settlement

The following is an illustrative case. A reinforced-concrete floor beam spans continuously over three supports. The central support settles 8 mm because of consolidation of a recently constructed foundation. The beam carries service-level gravity loading and has approximately constant EI over the relevant spans.

Background

The beam was designed as continuous, so its support reactions and bending moments are indeterminate. The settlement occurs after construction and is not adequately represented by simply reducing an applied load.

Problem

The engineer must estimate the additional support reaction changes and bending moments caused by the settlement, then determine whether cracking, reinforcement demand, or serviceability limits are affected.

Analysis

The middle support reaction is selected as a redundant, and the middle support is removed to form a determinate primary structure. The displacement at the removed-support coordinate is calculated from gravity loads using virtual work. A unit upward force at that coordinate gives the flexibility coefficient. The settlement is entered as the prescribed displacement in the compatibility equation:

Δ⁰ + fR = s

The sign of s is negative if downward settlement is opposite to the selected positive upward coordinate. If the beam has several spans or variable stiffness, the integrals are evaluated span by span using the actual EI values.

Approach and solution

The engineer solves the gravity-load case and settlement-only case separately, then superposes them. The settlement-only case is important because it isolates secondary effects and allows the project team to understand whether a support movement, rather than increased gravity loading, controls design.

The final bending-moment diagram is checked for equilibrium and for continuity of beam rotation and displacement. A nonlinear concrete model may subsequently be required because cracking changes EI and therefore changes the flexibility coefficients. If cracking is significant, an iterative analysis using effective stiffness is more realistic than a single constant-EI calculation.

Outcome

The analysis identifies increased negative moment near the settling support and compensating changes in adjacent spans. The foundation engineer is advised that reducing settlement is structurally beneficial, while the structural engineer reviews top reinforcement, crack widths, and construction-stage restraint. The calculated forces are not treated as exact if the settlement prediction itself has substantial uncertainty; sensitivity analysis is recommended.

Learning points

  1. Settlement is introduced through compatibility, not as an ordinary applied load.
  2. The stiffness distribution controls the force redistribution.
  3. Construction sequence and cracking can materially affect the response.
  4. Structural and geotechnical information must be coordinated.
  5. Equilibrium checks alone cannot verify an indeterminate analysis; compatibility must also be checked.

9. Computational Practice and Contemporary Tools

For one to three redundants, hand calculation with diagrams and virtual work is often the clearest method. Spreadsheets can automate piecewise integration, unit checking, and sensitivity studies. Finite-element software generally uses a displacement or stiffness formulation, but the same physical requirements remain: equilibrium, compatibility, and constitutive behaviour.

AI-assisted tools may help identify load paths, generate preliminary unit-load cases, or check algebra, but they do not replace engineering judgment. A professional must verify support idealizations, units, stiffness assumptions, sign conventions, releases, and boundary conditions. Software output should be checked against simplified calculations, limiting cases, symmetry, and conservation of equilibrium. Automated results are unsafe when the model contains unintended restraints or disconnected members.

10. Limitations, Errors, and Best Practices

The classical force method commonly assumes linear elasticity, small displacements, known geometry, and stable supports. It may require modification when there is yielding, cracking, large displacement, contact, slack cables, support uplift, frictional slip, or changing boundary conditions. In these situations, compatibility may be nonlinear and flexibility coefficients may depend on the unknown force.

Common errors include:

  • selecting a primary structure that is unstable;
  • removing a force but failing to define its displacement coordinate;
  • using inconsistent signs between real-load and unit-load diagrams;
  • omitting axial deformation in a frame where it matters;
  • treating settlement or temperature as an applied force;
  • using gross section stiffness after cracking without justification;
  • forgetting fabrication error in a cut-member compatibility condition;
  • ignoring internal hinges or releases;
  • accepting a result without checking equilibrium and boundary conditions.

Best practice is to draw the primary structure and every unit-load case, label positive directions, keep a table of internal-force functions, use consistent units, and perform independent checks. Symmetry can reduce the number of unknowns, while reciprocity provides a strong check on the flexibility matrix.

Chapter Summary

Force methods analyse statically indeterminate structures by combining equilibrium with compatibility and constitutive behaviour. The analyst selects redundants, removes them to create a stable determinate primary structure, calculates actual-load displacements and flexibility coefficients, and solves compatibility equations for the redundants. Virtual work provides efficient displacement calculations for beams, frames, and trusses. The general flexibility equation is [f]{X} = {Δᵖ} − {Δ⁰}, with additional imposed-deformation terms when temperature, fabrication error, or internal lack of fit is present.

For beams and frames, bending flexibility is commonly evaluated from ∫Mm/(EI) dx; for trusses, axial flexibility is obtained from member summations involving NL/(AE). Support settlement, thermal expansion, temperature gradients, and fabrication errors create forces in indeterminate structures because compatibility prevents free deformation. Reliable analysis requires stable primary structures, consistent signs and units, realistic stiffness, and checks of both equilibrium and compatibility. Force methods remain valuable for hand analysis, interpretation, verification of computer models, and professional diagnosis of restraint-related structural effects.

Key Terms

Static indeterminacy: The number of force quantities not obtainable from equilibrium alone.

Redundant: An additional force or moment selected as an unknown generalized force.

Primary structure: The determinate structure obtained after removing redundants.

Compatibility: The requirement that structural displacements and rotations remain geometrically consistent.

Flexibility coefficient: Displacement at one coordinate caused by a unit force or moment at another coordinate.

Consistent deformation: A force-method procedure that enforces prescribed displacement conditions.

Unit-load method: A virtual-work method for calculating displacement using an actual-load diagram and a unit-load diagram.

Virtual work: A work-based relation used to calculate structural displacements.

Flexibility matrix: The matrix containing all flexibility coefficients.

Maxwell–Betti theorem: The reciprocal relation fᵢⱼ = fⱼᵢ for linear elastic structures.

Prescribed displacement: A specified translation or rotation, such as settlement.

Support settlement: Movement of a support from its original position.

Thermal strain: Free strain produced by temperature change, commonly αΔT.

Fabrication error: An initial dimensional mismatch or lack of fit in a member or connection.

Axial deformation: Extension or shortening caused by axial force.

Bending flexibility: Deformation response governed primarily by 1/(EI).

Compatibility equation: An equation relating load-induced, redundant-induced, and prescribed displacements.

Geometric stability: The ability of a structure to retain its shape under load without becoming a mechanism.

Superposition: Addition of responses from separate load or imposed-deformation cases under linear assumptions.

Effective stiffness: The stiffness adopted to represent actual behaviour, including effects such as cracking.

Review Questions

5 Short Answer Questions

  1. Why can equilibrium alone not solve a statically indeterminate structure?
  2. What conditions must a primary structure satisfy?
  3. Define a flexibility coefficient and state its units for a translational coordinate.
  4. Why can support settlement produce forces in an indeterminate structure?
  5. State one assumption underlying the unit-load method.

5 Long Answer Questions

  1. Explain the complete consistent-deformation procedure for a beam with one redundant, including the role of the primary structure.
  2. Derive the flexibility equation for several redundants and explain each term.
  3. Compare the application of virtual work to a bending beam and an axial truss.
  4. Explain how temperature change and fabrication error are incorporated into compatibility equations.
  5. Discuss the limitations of force methods for cracked, nonlinear, or large-displacement structures.

3 Analytical / Application Questions

  1. A propped cantilever has length L and carries a point load P at distance a from the fixed end. Select the prop reaction as redundant and derive its value using the cantilever deflection and flexibility.
  2. An indeterminate truss contains a member that is 3 mm too long. Describe the primary structure, unit-load case, compatibility equation, and sign convention required to calculate the induced member force.
  3. A continuous beam experiences a predicted support settlement while its flexural stiffness varies from span to span. Develop an analysis plan that includes virtual work, variable EI, settlement compatibility, equilibrium checks, and sensitivity to uncertain stiffness.

Multiple Choice Questions with Answers

Question 1

Which additional requirement is needed, together with equilibrium, to solve a statically indeterminate structure?

A. Compatibility of deformation

B. A larger load factor

C. A second coordinate system

D. A zero-displacement assumption everywhere

Correct Answer: A. Compatibility of deformation

Question 2

What is the purpose of removing redundants in the force method?

A. To eliminate all applied loads

B. To create a stable determinate primary structure

C. To make every member carry zero force

D. To change the material properties

Correct Answer: B. To create a stable determinate primary structure

Question 3

For a one-redundant structure with zero prescribed displacement, which relation is correct?

A. X = Δ⁰f

B. X = f/Δ⁰

C. X = −Δ⁰/f

D. X = Δ⁰ + f

Correct Answer: C. X = −Δ⁰/f

Question 4

For a bending beam under the stated linear-elastic assumptions, which expression gives a flexibility coefficient?

A. ∫Mm/(EI) dx

B. ∫EI/(Mm) dx

C. ∫M + m + EI dx

D. ∫(EI)²Mm dx

Correct Answer: A. ∫Mm/(EI) dx

Question 5

Which quantity is normally included in the axial truss unit-load equation?

A. Member torsional stiffness only

B. NₖnₖLₖ/(AₖEₖ)

C. MₖmₖLₖ/(GJₖ) only

D. Load intensity divided by joint count

Correct Answer: B. NₖnₖLₖ/(AₖEₖ)

Question 6

The Maxwell–Betti reciprocal theorem implies, for a linear elastic structure, that:

A. fᵢⱼ = 0 for all i and j

B. fᵢⱼ = fⱼᵢ

C. all reactions are equal

D. all member forces are tensile

Correct Answer: B. fᵢⱼ = fⱼᵢ

Question 7

A uniform freely expanding member subjected to a temperature change has idealized thermal extension:

A. αΔT/L

B. EAαΔT

C. αΔTL

D. EαΔT/L

Correct Answer: C. αΔTL

Question 8

Why can a fabrication error create force without external loading in an indeterminate structure?

A. Equilibrium is violated

B. The structure is forced to satisfy compatibility despite the initial mismatch

C. The modulus becomes zero

D. The member becomes statically determinate

Correct Answer: B. The structure is forced to satisfy compatibility despite the initial mismatch

Question 9

Which check is essential after solving a flexibility analysis?

A. Check only the largest reaction

B. Check equilibrium and compatibility

C. Check that every displacement is zero

D. Check that every member has identical force

Correct Answer: B. Check equilibrium and compatibility

Question 10

For a truss displacement calculated by virtual work, the product Nₖnₖ primarily represents:

A. The interaction of actual and unit-load member forces

B. The member’s temperature only

C. The support reaction count

D. The number of joints squared

Correct Answer: A. The interaction of actual and unit-load member forces

Structural Analysis
Chapter 9 of 15