Chapter 5
Laplace Transform and Continuous-Time System Analysis
Post Graduate Program in Electrical Engineering
Signal & System
•
Post Graduate
Laplace Transform and Continuous-Time System Analysis
Introduction and context
The Laplace transform is a central analytical tool for continuous-time signals and systems. It converts differential equations and convolution integrals in the time domain into algebraic relations in the complex-frequency domain. Unlike the Fourier transform, it can represent a broad class of growing, decaying, and transient signals through the region of convergence (ROC). The transform therefore provides not only an algebraic expression but also essential information about signal sidedness, causality, stability, and realizability.
For postgraduate electrical engineering, the Laplace transform should be regarded as a pair consisting of an algebraic expression and its ROC. The same rational expression can correspond to different time-domain signals when different ROCs are assigned.
Learning objectives
After completing this chapter, the reader should be able to:
Define unilateral and bilateral Laplace transforms and explain their domains of validity.
Determine ROCs and infer causality and stability from pole locations and ROC information.
Use transform properties to solve differential equations and analyze LTI systems.
Apply initial- and final-value theorems with their exact hypotheses.
Recover time-domain signals using Bromwich inversion, partial fractions, and residues.
Analyze transfer functions, frequency response, poles, zeros, stability, and realizations.
Evaluate a practical continuous-time control or circuit problem using Laplace-domain methods.
1. Definitions and interpretation
For a signal x(t), the bilateral Laplace transform is
X(s) = ∫−∞∞ x(t)e−stdt, s = σ + jω
where σ and ω are real, j² = −1, and s has units of inverse time. The ROC is the set of complex values s for which the integral converges. Thus, the complete transform description is X(s) together with its ROC.
The unilateral (one-sided) transform is
X_+(s) = ∫0^-∞ x(t)e−stdt
It is especially useful for initial-value problems because impulses and initial conditions at t = 0 can be represented directly. Unless explicitly stated otherwise, system transfer functions are normally defined using zero initial conditions.
The exponential e^{−st} weights the signal by e^{−σt} and analyzes oscillatory behavior at angular frequency ω. The transform may therefore be interpreted as a generalized frequency-domain representation that includes exponential growth or decay.
Common signal transforms
Signal x(t)
Laplace transform
ROC
δ(t)
1
Entire s-plane
u(t)
1/s
Re(s) > 0
e^{−at}u(t)
1/(s+a)
Re(s) > −a
−e^{−at}u(−t)
1/(s+a)
Re(s) < −a
cos(ω₀t)u(t)
s/(s²+ω₀²)
Re(s) > 0
The same expression 1/(s+a) has two possible inverse transforms depending on the ROC. This is one reason that omitting the ROC can lead to an incomplete or incorrect answer.
2. Region of convergence
For rational transforms, the ROC is bounded by poles and cannot contain a pole. Typical forms are:
Right-sided signal: ROC lies to the right of the rightmost pole.
Left-sided signal: ROC lies to the left of the leftmost pole.
Two-sided signal: ROC is a vertical strip between poles.
Finite-duration signal: often the ROC is the entire s-plane, except possible behavior associated with impulses or transform singularities.
Consider
X(s) = 1/[(s+1)(s+3)]
For a causal right-sided interpretation, the ROC is Re(s) > −1. Partial fractions give
X(s) = 1/2·1/(s+1) − 1/2·1/(s+3)
and therefore
x(t) = [1/2 e−t − 1/2 e−3t]u(t)
For the ROC −3 < Re(s) < −1, the first term is right-sided and the second is left-sided:
x(t) = 1/2 e−tu(t) + 1/2 e−3tu(−t)
The algebraic expression is identical, but the signal is two-sided. For the ROC Re(s) < −3, both terms are left-sided and the signs change according to the left-sided pair.
For a rational transform, a stable signal requires that the ROC include the jω-axis. A causal rational system is BIBO stable precisely when all its poles lie strictly in the open left half-plane. A pole on the jω-axis prevents absolute integrability for a causal rational impulse response; repeated imaginary-axis poles are even more problematic.
3. Important transform properties
Linearity is
𝓛{a x(t) + b y(t)} = aX(s) + bY(s)
where a and b are constants and the common ROC is considered.
Time differentiation, for the bilateral transform under vanishing boundary terms, is
𝓛{dx(t)/dt} = sX(s)
For the unilateral transform, the initial value must be included:
provided the integral and ROC conditions are satisfied. For a causal signal and unilateral analysis, the same relation applies when the lower-limit convention is consistent.
Time shifting requires care. If x(t) is causal, then for T ≥ 0,
𝓛{x(t−T)u(t−T)} = e−sTX(s)
Without causality, x(t−T)u(t−T) is a truncated shifted signal and cannot generally be transformed by simply multiplying X(s) by e^{−sT}.
The frequency-shift property is
𝓛{eatx(t)} = X(s−a)
and convolution is
𝓛{x(t)*h(t)} = X(s)H(s)
where (x*h)(t) = ∫_{−∞}^{∞}x(τ)h(t−τ)dτ. The ROC of the product must be determined from the individual transforms; it is not always merely the intersection if pole-zero cancellations or special convergence behavior occur.
4. Initial- and final-value theorems
The initial-value theorem, in its commonly used causal/unilateral form, is
x(0^+) = lims→∞ sX_+(s)
provided x(t) has a finite right-hand initial value and no inappropriate impulsive component invalidates the interpretation. For a causal signal with a suitable bilateral transform, the corresponding result may be used, but it is not a general theorem for an arbitrary bilateral signal. An impulse at t = 0, for example, is not represented by an ordinary finite initial sample.
The final-value theorem is
limt→∞x(t) = lims→0sX(s or X_+(s))
only when all poles of sX(s) lie in the open left half-plane. Equivalently, X(s) may have at most a simple pole at the origin, and all other poles of sX(s) must have strictly negative real parts. The theorem must not be used when persistent oscillations or right-half-plane poles are present.
Example: for X(s) = 5/[s(s+2)], all poles of sX(s) consist of −2, so
limt→∞x(t) = lims→0 5/(s+2) = 5/2
Indeed, x(t) = (5/2)(1−e^{−2t})u(t), whose final value is 2.5.
5. Inversion methods
Bromwich inversion
For a transform X(s) with a valid ROC and a vertical inversion line Re(s) = γ inside the ROC,
x(t) = 1/(2πj) ∫γ−j∞γ+j∞ X(s)estds
This is the Bromwich integral. For t > 0, the contour is generally closed to the left when the signal is right-sided; for t < 0, it is closed to the right. The selected poles and hence the result depend on the ROC.
Residue method
If X(s)e^{st} is meromorphic and the contour can be closed with vanishing arc contribution, the residue theorem gives
x(t) = ∑ residues of X(s)est at enclosed poles
with orientation and sidedness determined by the contour. For a simple pole at s = p,
Res[X(s)est,p] = lims→p(s−p)X(s)est
For repeated poles, derivatives are required. Residue inversion is particularly useful for high-order systems and asymptotic analysis, while partial fractions are usually more efficient for simple rational transforms.
6. Continuous-time LTI systems
For an LTI system with impulse response h(t),
y(t) = x(t)*h(t)
and under compatible ROC conditions,
Y(s) = H(s)X(s)
The transfer function is defined under zero initial conditions as
H(s) = Y(s)/X(s)
A causal rational system has h(t) = 0 for t < 0, so its ROC lies to the right of the rightmost pole. BIBO stability requires h(t) to be absolutely integrable:
∫−∞∞|h(t)|dt < ∞
For a causal rational system this is equivalent to all poles being strictly in the open left half-plane.
Differential-equation model
Consider
y''(t)+3y'(t)+2y(t)=x(t)
With zero initial conditions,
(s²+3s+2)Y(s)=X(s)
Thus,
H(s)=1/[(s+1)(s+2)]
The poles −1 and −2 imply causal stability. A realization in controllable canonical form is possible with state vector z = [z₁ z₂]ᵀ:
ż = [[0,1], [−2,−3]]z + [0,1]ᵀx
y = [1,0]z
The eigenvalues of the state matrix are −1 and −2, matching the poles. Different state-space realizations can have different internal modes if pole-zero cancellations occur; therefore input-output stability alone does not automatically guarantee internal stability in a nonminimal realization.
7. Frequency response and pole-zero geometry
If the ROC includes the jω-axis, the frequency response is obtained by evaluating
H(jω)=H(s)|s=jω
The magnitude and phase are |H(jω)| and ∠H(jω). Poles near the jω-axis produce large response magnitude and long transients; zeros suppress response near their locations. Pole-zero plots use crosses for all poles and circles for all zeros, irrespective of whether poles are stable or unstable.
Pole-zero diagram with stable left-half-plane poles and an unstable right-half-plane pole
Figure: Pole-zero diagram with stable left-half-plane poles and an unstable right-half-plane pole
Figure: Standard pole-zero notation: crosses denote every pole, while circles denote zeros; location determines stability implications.
8. Worked application: second-order sensor interface
Consider an illustrative temperature-sensor interface modeled by
0.01y''(t)+0.3y'(t)+y(t)=x(t)
where x is the scaled input and y is the output. The coefficients have units selected so that each term has the same physical units. Under zero initial conditions,
H(s)=1/[0.01s²+0.3s+1]
Dividing by 0.01 gives
H(s)=100/(s²+30s+100)
The poles are
s = [−30 ± √(900−400)]/2 = [−30 ± √500]/2
Hence s ≈ −3.8205 and −26.1795 s⁻¹. Both poles are in the open left half-plane, so the causal interface is stable. For a unit-step input X(s)=1/s,
Y(s)=100/[s(s²+30s+100)]
The final-value theorem applies because the poles of sY(s) are strictly in the open left half-plane:
limt→∞y(t)=lims→0100/(s²+30s+100)=1
The interface has unit static gain and a two-time-scale transient. The slow pole, approximately −3.82 s⁻¹, dominates the late response, giving a dominant time constant of approximately 0.262 s. This model illustrates how pole location supports design decisions: faster poles contribute short transients, while a pole close to the imaginary axis limits settling speed.
9. Realization, cancellation, and robustness
A transfer function is an input-output description, not a unique physical implementation. A minimal realization has no uncontrollable or unobservable states and has order equal to the McMillan degree of the transfer function. Exact pole-zero cancellation reduces the transfer-function order, but a canceled unstable pole may remain as an unobservable or uncontrollable internal mode. Such a realization can be internally unstable even though its external transfer function appears stable.
In practical systems, exact cancellation is fragile because component tolerances, quantization, unmodeled dynamics, and parameter drift destroy the cancellation. Robust design therefore avoids relying on unstable pole-zero cancellation and examines both transfer-function stability and state-space internal stability.
10. Computational and contemporary practice
Symbolic algebra systems can perform partial fractions, solve characteristic equations, and evaluate residues. Numerical tools can compute poles, zeros, frequency responses, and state-space realizations. However, software output must be checked for ROC assumptions, pole-zero cancellations, numerical conditioning, and sign conventions. Near pole-zero cancellation, finite precision can produce misleading conclusions about stability or transient behavior.
In data-driven and AI-assisted system identification, a fitted rational model should be validated using independent data, residual analysis, physical constraints, and stability checks. An apparently accurate fit is not sufficient if it violates causality, passivity, known bandwidth, or safety requirements. For safety-critical control, model uncertainty and worst-case stability margins must be addressed explicitly.
11. Limitations and best practices
The Laplace transform is less informative than specialized tools for some tasks. Fourier analysis is often preferable for stationary spectral interpretation; the z-transform is natural for sampled-data systems; and state-space methods are superior for multivariable systems, constraints, and modern control synthesis. Nonlinear systems generally cannot be represented by a single transfer function, although local linearization may produce one near an operating point.
Best practice is to:
State whether the transform is bilateral or unilateral.
State the ROC whenever signal identity or stability matters.
Specify causality and initial-condition assumptions.
Check theorem conditions before using initial- or final-value limits.
Verify poles independently and distinguish internal from input-output stability.
Preserve units and identify the physical meaning of model parameters.
Use residues or numerical inversion when partial fractions are unsuitable.
Chapter Summary
The Laplace transform maps continuous-time signals and systems into the complex s-plane. Its complete interpretation requires both the transform expression and its ROC. Right-sided, left-sided, and two-sided signals correspond to different ROC geometries, and the ROC determines whether a rational representation is causal or stable. Transform properties convert differentiation, integration, shifting, and convolution into algebraic operations, while the unilateral transform incorporates initial conditions naturally.
The initial-value theorem requires a suitable causal/right-hand or unilateral setting. The final-value theorem requires every pole of sX(s) to lie in the open left half-plane, allowing at most a simple pole of X(s) at the origin. Bromwich inversion and residue calculus provide rigorous inverse-transform methods. For LTI systems, transfer functions, poles, zeros, frequency response, and state-space realizations support analysis and design. Finally, minimality, internal stability, model uncertainty, and robust validation are essential when moving from mathematical transfer functions to physical implementations.
Key Terms
Laplace transform: Integral mapping from time domain to complex-frequency domain.
Bilateral transform: Transform integrated over −∞ < t < ∞.
Unilateral transform: Transform integrated from 0⁻ to ∞.
Region of convergence: Set of s-values for which the transform integral converges.
ROC: Abbreviation for region of convergence.
Pole: Value of s at which a rational transform becomes unbounded.
Zero: Value of s at which a transform numerator becomes zero.
Causal signal: Signal that is zero for t < 0.
Right-sided signal: Signal supported toward positive time.
Left-sided signal: Signal supported toward negative time.
Transfer function: Zero-initial-condition ratio Y(s)/X(s).
Impulse response: Output of an LTI system to δ(t).
Bromwich integral: Contour integral used for inverse Laplace transformation.
Residue: Coefficient used to evaluate contour integrals at isolated singularities.
Frequency response: Transfer function evaluated on the jω-axis when permitted by the ROC.
Minimal realization: Realization with no redundant controllable or observable states.
Internal stability: Stability of all modes in a state-space realization.
Pole-zero cancellation: Algebraic removal of a common pole and zero.
Dominant pole: Pole whose decay rate most strongly controls late-time behavior.
Review Questions
Short Answer Questions
Why must the ROC be specified along with a rational Laplace transform?
State the unilateral transform of the first derivative, including the initial condition.
What is the difference between causal stability and internal stability?
State the exact pole condition for the final-value theorem.
Why is the time-delay property restricted when the original signal is not causal?
Long Answer Questions
Derive the ROC classifications for right-sided, left-sided, and two-sided rational signals, using examples.
Explain Bromwich inversion and show how contour selection depends on the ROC and the sign of time.
Derive the transfer function of a second-order differential-equation system and relate its poles to transient behavior.
Compare bilateral and unilateral Laplace transforms in signal representation and initial-value analysis.
Discuss minimal realization, pole-zero cancellation, and the distinction between external and internal stability.
Analytical / Application Questions
For X(s)=1/[(s+2)(s+5)], determine the causal inverse and its final value, if applicable.
Analyze the stability and dominant time constant of H(s)=25/(s²+8s+25) for a causal realization.
A measured system exhibits a right-half-plane pole in an identified transfer function. Explain the possible implications for causality, stability, model validation, and controller design.
Multiple Choice Questions with Answers
Question 1
For a causal rational system, which pole condition is equivalent to BIBO stability?
A. All poles are in the closed right half-plane
B. All poles lie strictly in the open left half-plane
C. At least one pole lies on the imaginary axis
D. Zeros and poles must both lie on the imaginary axis
Correct Answer: B. All poles lie strictly in the open left half-plane
Question 2
What additional information is essential to identify the inverse of a rational bilateral Laplace transform?
A. Only the numerator degree
B. Only the denominator degree
C. The region of convergence
D. The sampling frequency
Correct Answer: C. The region of convergence
Question 3
For a causal signal x(t), the transform of x(t−T)u(t−T), T≥0, is:
A. e^{sT}X(s)
B. X(s−T)
C. e^{−sT}X(s)
D. X(s)+T
Correct Answer: C. e^{−sT}X(s)
Question 4
The unilateral transform of dx(t)/dt is:
A. sX_+(s)
B. sX_+(s)−x(0⁻)
C. X_+(s)/s
D. sX_+(s)+x(0⁺)
Correct Answer: B. sX_+(s)−x(0⁻)
Question 5
The final-value theorem is valid when:
A. All poles of sX(s) lie in the open left half-plane
B. Any pole may lie in the right half-plane
C. All poles of X(s) lie on the imaginary axis
D. X(s) has a repeated pole at the origin
Correct Answer: A. All poles of sX(s) lie in the open left half-plane
Question 6
For X(s)=5/[s(s+2)], the final value of the corresponding causal signal is:
A. 0
B. 2
C. 2.5
D. 5
Correct Answer: C. 2.5
Question 7
In standard pole-zero notation, a cross represents:
A. A zero
B. A pole
C. The ROC boundary only
D. A state variable
Correct Answer: B. A pole
Question 8
The inverse Laplace transform using a vertical contour inside the ROC is called:
A. Fourier synthesis
B. Bromwich inversion
C. Euler integration
D. Nyquist sampling
Correct Answer: B. Bromwich inversion
Question 9
For H(s)=1/[(s+1)(s+2)] with a causal ROC, the impulse response is:
A. (e^{−t}+e^{−2t})u(t)
B. (e^{−t}−e^{−2t})u(t)
C. (2e^{−t}−e^{−2t})u(t)
D. e^{−3t}u(t)
Correct Answer: B. (e^{−t}−e^{−2t})u(t)
Question 10
A pole at s=−3 has an associated exponential mode whose time constant is: