Mechanical Systems Design

Chapter 9
Springs, Flywheels and Energy-Storage Elements

Bachelors Program in Machine Technology
Mechanical Systems Design   •   Bachelor

Springs, Flywheels and Energy-Storage Elements

Introduction and Context

Mechanical systems frequently experience varying loads rather than steady loads. A clutch engages suddenly, a valve must close without impact, a reciprocating engine produces fluctuating torque, and a vehicle suspension must absorb road irregularities. Springs and flywheels provide two different but complementary solutions. A spring stores energy through elastic deformation and can return that energy as force or motion. A flywheel stores kinetic energy in rotation and reduces speed variation caused by cyclic torque fluctuations. Other storage elements—including torsion bars, elastomeric components, pneumatic accumulators and disc springs—are selected when space, response time, durability or force characteristics impose special requirements.

The designer must satisfy four principal requirements: adequate strength, suitable stiffness, acceptable fatigue life and geometric stability. A component that does not yield may nevertheless be unsuitable if it is too stiff, resonates, buckles, bottoms out, loses preload or fails after repeated cycles. This chapter develops the governing mechanics and a practical design procedure.

Learning Objectives

By the end of this chapter, the reader should be able to:

  1. Explain how springs and flywheels store and release energy.
  2. Design helical compression, extension and torsion springs for load, deflection and stress.
  3. Analyse leaf, disc and torsion springs, including fatigue and stability considerations.
  4. Determine flywheel energy fluctuation and required rotational inertia.
  5. Select an energy-storage element for shock absorption, force control or cyclic operation.
  6. Recognize manufacturing, fatigue, resonance, temperature, inspection and safety constraints.

1. Fundamental Concepts of Elastic Energy Storage

For a linearly elastic element, the external work stored as strain energy is

U = ∫₀^δ F dδ = ½Fδ = ½kδ²

where U is strain energy in joules, F is force in newtons, δ is deflection in metres and k is stiffness in newtons per metre. The final two forms apply only to a linear force–deflection relationship, F = kδ. For a nonlinear spring, the area under the actual force–deflection curve must be integrated.

Rotational elastic elements are described similarly:

U = ∫₀^θ T dθ = ½Tθ = ½kθ²

for a linear torsional spring, where T is torque in newton-metres, θ is angular deflection in radians and k is torsional stiffness in newton-metres per radian.

Energy capacity is not the same as force capacity. A small spring may carry a high force over a short stroke but store less energy than a larger spring carrying a moderate force over a long stroke. Selection therefore begins with the required force or torque, displacement, cycle rate and stored energy—not with a spring type chosen in isolation.

Important terminology includes free length, solid height, installed length, preload, spring index, active coils, pitch, surge, permanent set, spring rate and fatigue life. The active coils deform substantially; inactive end coils primarily transmit load.

2. Helical Springs

2.1 Compression springs

A close-coiled helical compression spring is commonly made from round wire of diameter d, wound to mean coil diameter D. The spring index is

C = D/d

where C is dimensionless. A moderate index, commonly about 4 to 12 in practical designs, supports manufacturability and reduces stress concentration. Very low index springs are difficult to form and have high curvature stress; very high index springs are prone to instability and may be difficult to control dimensionally.

For a helical spring with n active coils, shear modulus G, wire diameter d and mean diameter D, the axial stiffness is

k = Gd⁴/(8D³n)

This assumes a close-coiled spring, small deflection, circular wire, linear elastic material and negligible effects from end geometry and friction. Units must be consistent; for example, N and mm require G in N/mm², producing k in N/mm.

The corresponding deflection under axial force F is

δ = 8FD³n/(Gd⁴)

The principal wire shear stress is corrected for direct shear and curvature by the Wahl factor:

Kw = (4C − 1)/(4C − 4) + 0.615/C

and

τmax = Kw(8FD/(πd³))

Here τ_max is the maximum shear stress. The formula applies to round-wire helical springs under axial loading; end effects and residual stresses may require additional consideration.

The spring must also satisfy geometric constraints. If δ_max is the maximum operating deflection, the coil clash condition is approximately

Ls + δmax ≤ Li

where L_s is solid height and L_i is the minimum installed length. A clearance margin is normally added because manufacturing tolerances and dynamic overshoot can cause contact. Solid height is approximately the number of total coils multiplied by wire diameter, with the exact value depending on end construction.

The pitch p for a compression spring with free length L_f and n_t total coils is approximately related to the available axial spacing. Designers must distinguish total coils from active coils; squared and ground ends alter this relationship.

2.2 Compression-spring design procedure

A practical sequence is:

  1. Specify minimum and maximum force, working deflection, cycle life, environment and allowable outside diameter.
  2. Select material and an initial spring index C.
  3. Choose a trial wire diameter and calculate D = Cd.
  4. Determine active coils from the stiffness requirement.
  5. Check corrected shear stress at minimum and maximum load.
  6. Check solid height, pitch, buckling, surge frequency and installation clearance.
  7. Assess fatigue using the stress range and mean stress.
  8. Recalculate with tolerances, surface finish, corrosion allowance and manufacturing limits.

Worked Example 1: Compression spring

A spring must exert 180 N at a deflection of 30 mm. Use wire diameter d = 6 mm, mean diameter D = 48 mm, active coils n = 8 and shear modulus G = 79,000 N/mm². Determine stiffness, force consistency and maximum corrected shear stress.

The stiffness is

k = (79,000 × 6⁴)/(8 × 48³ × 8) = 3.214 N/mm

At 30 mm deflection, the predicted force is

F = kδ = 3.214 × 30 = 96.4 N

Thus the proposed spring is too soft for 180 N at 30 mm. To achieve the required stiffness without changing diameter or mean diameter, the active-coil count would need to be approximately

nnew = 8 × 96.4/180 = 4.28 coils

A practical design might use about four active coils, subject to end construction and stability checks. For the original geometry, C = 48/6 = 8. The Wahl factor is

Kw = (4×8 − 1)/(4×8 − 4) + 0.615/8 = 1.184

At 96.4 N, the corrected shear stress is

τmax = 1.184[8×96.4×48/(π×6³)] ≈ 48.5 MPa

The example illustrates an essential design principle: a stress check cannot compensate for an incorrect stiffness. Load, deflection and geometry must be satisfied simultaneously.

2.3 Extension springs

Extension springs normally include hooks or loops and may be initially tensioned. If F_i is initial tension and k is spring rate, the force during extension is approximately

F = Fi + kδ

where δ is extension beyond the initial position. Hook geometry often governs failure because bending and torsional stresses are concentrated at the hook transition. The hook must therefore be analysed separately, and the spring should not be designed solely from the body-coil equation.

2.4 Helical torsion springs

A helical torsion spring stores energy through bending of its wire rather than primarily through torsion of the wire. For a round-wire spring with mean diameter D, wire diameter d, active turns n, Young’s modulus E and angular deflection θ in radians, a commonly used small-deflection relation is

k_θ = Ed⁴/(10.8Dn)

where k_θ is torque per radian. The numerical coefficient depends on the adopted geometry and correction assumptions; manufacturer data should be used for final design. The torque is T = k_θθ.

The bending stress is estimated from

σ = Ki(32M/(πd³))

where M is applied torque and K_i is an index-dependent stress factor. Legs must be supported so that the applied moment is correctly transmitted; incorrect leg loading can cause local yielding or rubbing.

2.5 Torsion bars

A straight circular torsion bar is a useful energy-storage element in suspension and actuation. For length L, polar second moment J and shear modulus G,

θ = TL/(GJ)

For a solid circular bar,

J = πd⁴/32

and the maximum shear stress is

τmax = 16T/(πd³)

These equations assume a prismatic circular bar, elastic material and Saint-Venant torsion away from stress concentrations. Splines, shoulders and surface defects can dominate fatigue performance.

3. Leaf Springs

A leaf spring is a beam made from one or more plates, commonly used for vehicle suspension and vibration isolation. It combines energy storage, load guidance and axle location. A semi-elliptic spring has a curved stack supported at its ends and loaded near the centre.

For an idealized rectangular leaf of width b, thickness t and span L, the bending stress under central loading P depends on the support and load arrangement. For a simple simply supported beam with a central point load,

σmax = 3PL/(2bt²)

and the central deflection is

δ = PL³/(4Ebt³)

These expressions are beam idealizations and should not be applied uncritically to a multi-leaf automotive spring, where load sharing, interleaf friction, curvature and clips alter the response.

For a semi-elliptic multi-leaf spring, standard design equations are often expressed in terms of effective length, number of plates and whether the leaves are full-length or graduated. The designer must use a consistent convention for span and load. Stress concentrations occur at eyes, centre bolts, rebound clips and abrupt changes in leaf length. Shot peening, correct camber, controlled surface finish and corrosion protection are important for fatigue life.

Leaf springs exhibit hysteresis due to interleaf friction. This can dissipate vibration energy, but it also makes the force–deflection curve path-dependent and may reduce predictable ride performance. Composite glass-fibre or carbon-fibre leaf springs reduce mass and corrosion but require attention to delamination, environmental degradation and joining details.

4. Disc or Belleville Springs

A disc spring is a conical washer that deflects axially under load. It provides high force in a small axial space and is useful for preload, thermal compensation, clamping and overload protection. Disc springs may be stacked in parallel to increase force or in series to increase deflection.

For a disc spring, force and deflection depend on outer diameter, inner diameter, thickness, free cone height, material modulus and Poisson’s ratio. Because the exact relation includes geometric coefficients and nonlinear terms, validated manufacturer equations or standards such as DIN EN 16983 and DIN EN 16984 should be used for production design. A simple linear spring approximation is often inadequate, particularly near flattening.

Stacking rules are conceptually straightforward. Identical discs nested in the same direction act in parallel: force approximately multiplies by the number of parallel discs while deflection remains approximately that of one disc. Groups arranged in opposition act in series: deflection multiplies while force remains approximately that of one group. Friction between contacting discs causes hysteresis and means that actual loading and unloading curves differ.

Disc springs must be checked for edge yielding, permanent set, fatigue at the inner and outer rims, stress concentration, guidance and flattening. A guide mandrel or housing is frequently required to prevent lateral movement.

5. Fatigue, Stability and Dynamic Behaviour

5.1 Fatigue

Most springs operate for many thousands or millions of cycles. The alternating and mean components of stress are

τa = (τmax − τmin)/2

and

τm = (τmax + τmin)/2

For a preliminary assessment, a modified Goodman-type relation may be written as

τa/τe + τm/τu ≤ 1/ns

where τ_e is the corrected endurance strength in shear, τ_u is ultimate shear strength and n_s is the desired fatigue factor of safety. This is an approximation, not a universal spring standard. Surface finish, size, residual stress, corrosion, temperature, reliability and manufacturing process must be included when obtaining allowable values. For compression springs with fluctuating loads, torsional fatigue data are particularly important.

Shot peening introduces beneficial compressive residual stress at the surface. Presetting or scragging can remove permanent set, but it consumes part of the available elastic range and must not be confused with unlimited fatigue improvement.

5.2 Buckling

A long, slender compression spring can buckle before reaching its intended deflection. Buckling risk increases with free length-to-mean-diameter ratio and decreases when the spring is guided. A practical design should use a guide rod or sleeve where the geometry is slender, the spring is laterally unsupported or the compressed length is large. Manufacturer charts and validated empirical limits are preferred to a single universal critical ratio because end conditions strongly affect stability.

5.3 Surge and natural frequency

A spring has distributed mass and therefore natural modes. During rapid cycling, wave motion can cause surge: coils alternately compress and separate, producing high local stress. The operating frequency should be well separated from the spring’s natural frequency. A simplified estimate for the fundamental frequency of a compression spring is

fn ≈ (d/(πnD²))√(G/(2ρ))

where ρ is material density and the result is in hertz when coherent SI units are used. This estimate assumes an ideal spring and should be checked against detailed analysis or supplier data. Damping, end conditions and attached masses modify the actual response.

6. Flywheels and Energy Fluctuation

A flywheel stores rotational kinetic energy:

E = ½Iω²

where E is energy in joules, I is mass moment of inertia in kg·m² and ω is angular speed in rad/s. A rim-type flywheel stores energy efficiently because much of its mass lies at large radius. However, stresses in the rim rise with speed, and overspeed protection is essential.

In a cyclic machine, the driving torque and resisting torque vary with crank angle. The difference between input and output work produces fluctuation in flywheel energy. If E_max and E_min are the maximum and minimum energies during a cycle, the maximum fluctuation is

∆E = Emax − Emin

The coefficient of fluctuation of speed is

Cs = (ωmax − ωmin)/ωmean

For small speed fluctuations, the required inertia is approximately

I = ∆E/(ωmean²Cs)

This follows by linearizing E = ½Iω² about mean speed. It is valid when the speed fluctuation is small and when ∆E is obtained from the cumulative torque–angle diagram, not merely from the difference between peak torques.

The mean torque over a complete cycle must equal the mean resisting torque in steady operation. If the torque is T(θ), work over one cycle is

W = ∫₀2π T(θ)dθ

The fluctuation is determined from the maximum and minimum of cumulative work relative to the mean work line.

Worked Example 2: Flywheel inertia

A machine has maximum energy fluctuation ∆E = 1,200 J and runs at 600 rev/min. The permitted coefficient of speed fluctuation is C_s = 0.02. Convert speed to angular velocity:

ωmean = 2πN/60 = 2π×600/60 = 62.83 rad/s

Then

I = 1,200/(62.83²×0.02) = 15.20 kg·m²

The result is the minimum ideal inertia under the stated assumptions. A practical design adds allowance for manufacturing tolerances, speed-control interaction, transient loads and uncertainties in the torque diagram. The flywheel rim, hub and key or interference fit must then be checked for centrifugal stress and fatigue.

7. Selecting Energy-Storage Elements

Selection should follow the function required, not simply the available catalogue name.

RequirementSuitable elementsMain design concern
Axial preload in limited spaceDisc springNonlinear force, flattening, fatigue
Long axial travelHelical compression springBuckling, surge, solid height
Rotational return forceTorsion springLeg stress, angular travel, fatigue
Vehicle suspension and guidanceLeaf springBeam stress, friction, eyes, corrosion
Large cyclic torque smoothingFlywheelInertia, rim stress, containment
High-energy short-duration absorptionElastomer, hydraulic or pneumatic accumulatorTemperature, damping, leakage, ageing
Repeated torsional suspension motionTorsion barSurface fatigue, splines, stress concentration

For shock absorption, the designer must distinguish energy absorption from energy return. A steel spring returns most elastic energy, whereas a damper or hysteretic elastomer dissipates it. A system containing only a spring may rebound violently. For force control, disc springs can maintain preload over thermal movement, but their nonlinear characteristic may require a force–deflection calculation. For cyclic operation, fatigue life, natural frequency and heat generation can dominate static strength.

A useful selection checklist includes required energy, peak force, stroke, frequency, available envelope, temperature, corrosion, noise, maintenance, failure consequence, manufacturability and cost. Standards, supplier curves and test data should supplement analytical equations.

8. Illustrative Case: Flywheel and Spring System for a Press

Background

Consider an illustrative mechanical press driven by an electric motor through a shaft. The press requires high torque during a short forming portion of each revolution and much less torque during return. Direct motor sizing for the peak torque would increase motor mass and cost, while a flywheel can supply part of the short-duration energy demand.

Problem

Torque measurements and integration of the torque–angle diagram indicate that the maximum energy fluctuation per cycle is 2,400 J. The shaft speed is 300 rev/min, and the allowable coefficient of speed fluctuation is 0.015. The clutch also requires a spring-loaded engagement mechanism capable of 900 N over a 12 mm working stroke.

Analysis and solution

The mean angular speed is

ω = 2π×300/60 = 31.42 rad/s

The required ideal flywheel inertia is

I = 2,400/(31.42²×0.015) = 16.22 kg·m²

The design team selects a rim flywheel and verifies rim stress at the maximum overspeed, key or interference-fit capacity, shaft torsional strength, guarding and balancing. The inertia is increased modestly to accommodate uncertainty and wear.

For the clutch spring, the required average stiffness is

k = F/δ = 900/0.012 = 75,000 N/m

A disc-spring stack is selected because the available axial space is only 25 mm and high preload is required. Several discs in parallel provide the force, while series groups provide the 12 mm travel. The supplier’s nonlinear force–deflection curve is used rather than a linear approximation. The stack is guided, checked for flattening and fatigue, and tested through the specified engagement cycles.

Outcome

The combined solution reduces motor peak demand, maintains acceptable speed uniformity and provides controlled clutch force within the restricted envelope. The main risks are not captured by the first calculations: flywheel containment in an overspeed event, disc-stack friction and tolerance accumulation, clutch heating, and fatigue at the spring interfaces.

Learning points

  1. Flywheel inertia is determined by energy fluctuation and allowable speed variation.
  2. Spring selection must include force, travel, cycle life and envelope.
  3. Catalogue curves and standards are essential when spring behaviour is nonlinear.
  4. Guarding and containment are part of mechanical design, not optional accessories.

9. Manufacturing, Inspection and Safety

Spring performance depends strongly on process control. Wire diameter, coil diameter, pitch, free length, end squareness and surface condition should be inspected. Critical springs may require load testing, magnetic-particle or other nondestructive inspection, hardness verification and traceable material certification.

Springs should not be operated beyond their intended deflection, temperature or corrosion environment. A compression spring that reaches solid height can experience severe impact and permanent set. An extension spring with a damaged hook can fail without warning. Flywheels require guarding, balancing, overspeed assessment and a containment strategy because stored kinetic energy increases with the square of speed.

Designers must identify failure consequences. In safety-critical applications, a redundant load path, positive retention, fail-safe preload or scheduled replacement may be required. Standards and regulations vary by industry; applicable pressure-vessel, machinery, vehicle, lifting or occupational-safety requirements must be consulted.

10. Contemporary Developments and Engineering Practice

Computer-aided engineering permits nonlinear finite-element analysis of disc springs, leaf eyes, hooks and flywheel hubs. Multibody simulation can predict spring loads and resonance in complete mechanisms. Digital manufacturing enables variable-pitch springs, composite leaf springs and topology-optimized flywheel hubs. Sensors can monitor spring displacement, temperature, vibration and preload, supporting condition-based maintenance.

Artificial intelligence can assist with design-space exploration, surrogate modelling and anomaly detection, but it does not replace physical validation. Training data may omit rare failures, and an apparently optimal geometry may be unmanufacturable or unsafe. Engineering judgement, traceable assumptions, validated material data and independent verification remain necessary.

Best-Practice Design Sequence

  1. Define the load, displacement, speed, energy, temperature and life requirements.
  2. Select the storage principle: elastic, kinetic, pneumatic, hydraulic or dissipative.
  3. Establish a first-order model and check units.
  4. Select material, geometry and manufacturing process together.
  5. Check static strength, stiffness, fatigue, stability, resonance and interfaces.
  6. Include tolerances, corrosion, temperature, residual stress and installation effects.
  7. Validate with supplier data, prototype testing or qualified simulation.
  8. Provide guarding, retention, inspection criteria and maintenance instructions.
  9. Document assumptions and identify the governing failure mode.

Chapter Summary

Springs store elastic strain energy and provide force, displacement control, preload and shock response. Helical spring stiffness depends strongly on wire diameter, mean coil diameter and active coil count; corrected shear stress must be checked using an appropriate curvature factor. Extension hooks, torsion-spring legs, leaf-spring eyes and disc-spring rims often govern practical failure. Fatigue, buckling, surge, solid height, friction and temperature are as important as static strength.

Flywheels store rotational kinetic energy and smooth cyclic torque. Their required inertia is obtained from the maximum energy fluctuation and permissible speed fluctuation, while the torque–angle work diagram supplies the energy data. Selection among helical, torsion, leaf, disc, torsion-bar and flywheel elements depends on force, travel, energy, frequency, space, fatigue life, environment and safety consequence. Reliable design combines analytical equations with standards, manufacturing control, testing and protective measures.

Key Terms

Strain energy: Elastic energy stored by deformation.

Spring rate: Force per unit deflection, or torque per unit angular deflection.

Preload: Initial force or torque applied before service loading.

Free length: Length of a spring when unloaded.

Solid height: Length of a compression spring when coils are fully closed.

Spring index: Ratio of mean coil diameter to wire diameter.

Active coils: Coils that deform substantially under load.

Wahl factor: Stress-correction factor for curvature and direct shear in helical springs.

Surge: Dynamic oscillation or wave motion in a spring during rapid cycling.

Permanent set: Irrecoverable deformation after unloading.

Leaf spring: A beam-like spring made from one or more strips or plates.

Disc spring: Conical washer spring producing axial force and deflection.

Torsion bar: Straight bar storing energy through elastic twist.

Flywheel: Rotating element that stores kinetic energy and smooths speed variation.

Energy fluctuation: Difference between maximum and minimum stored energy in a cycle.

Coefficient of fluctuation of speed: Relative difference between maximum and minimum speed.

Fatigue: Failure caused by repeated or fluctuating stress.

Spring buckling: Lateral instability of a slender compression spring.

Hysteresis: Difference between loading and unloading paths caused by friction or damping.

Rim stress: Centrifugal stress developed in a rotating flywheel rim.

Review Questions

Short Answer Questions

  1. What is meant by spring rate, and how does it differ from stored energy?
  2. Define spring index and explain why it matters in helical-spring design.
  3. Why is a Wahl factor used for a compression spring?
  4. What is the function of a flywheel in a cyclic machine?
  5. Distinguish between a spring that stores energy and a damper that dissipates energy.

Long Answer Questions

  1. Explain the design procedure for a helical compression spring, including stiffness, stress, geometry, fatigue and stability checks.
  2. Compare helical, leaf, disc and torsion-bar springs in terms of loading, applications and principal limitations.
  3. Derive the relationship between flywheel inertia, energy fluctuation and coefficient of speed fluctuation for small speed variations.
  4. Discuss fatigue design of springs, including mean stress, alternating stress, surface finish, shot peening and corrosion.
  5. Explain how disc springs may be arranged in parallel and series, and discuss the effects of friction and nonlinear force–deflection behaviour.

Analytical / Application Questions

  1. A compression spring must deliver a specified force over a specified stroke. Propose a design sequence and identify at least five checks needed before release for manufacture.
  2. A press has a measured torque–angle diagram and a permitted speed fluctuation. Describe how you would calculate the required flywheel inertia and verify the flywheel’s mechanical safety.
  3. Select an energy-storage element for a compact clutch mechanism requiring high preload, limited axial space and millions of cycles. Justify the selection and identify the data that must be obtained from a supplier or test program.

Multiple Choice Questions with Answers

Question 1

For a linear spring, the stored energy is given by which expression?

A. U = F/δ

B. U = ½Fδ

C. U = F + δ

D. U = 2Fδ

Correct Answer: B. U = ½Fδ

Question 2

The spring index of a round-wire helical spring is defined as:

A. Wire diameter divided by coil count

B. Free length divided by wire diameter

C. Mean coil diameter divided by wire diameter

D. Outside diameter divided by active coil count

Correct Answer: C. Mean coil diameter divided by wire diameter

Question 3

Which factor corrects the basic helical-spring shear-stress equation for curvature and direct shear?

A. Poisson factor

B. Wahl factor

C. Shape factor for beams

D. Load distribution factor

Correct Answer: B. Wahl factor

Question 4

If the active-coil count of a helical compression spring is increased while all other parameters remain constant, its stiffness will:

A. Increase proportionally

B. Remain unchanged

C. Decrease

D. Become zero

Correct Answer: C. Decrease

Question 5

A flywheel stores energy primarily as:

A. Elastic strain energy

B. Chemical energy

C. Rotational kinetic energy

D. Thermal conduction energy

Correct Answer: C. Rotational kinetic energy

Question 6

For small speed fluctuations, required flywheel inertia is proportional to energy fluctuation and inversely proportional to:

A. Mean speed squared multiplied by coefficient of speed fluctuation

B. Mean torque only

C. Flywheel radius only

D. Cycle time multiplied by mass

Correct Answer: A. Mean speed squared multiplied by coefficient of speed fluctuation

Question 7

Discs nested in the same direction in a Belleville-spring stack primarily increase:

A. The force capacity at approximately the same deflection

B. The material density

C. The flywheel inertia

D. The natural frequency without changing force

Correct Answer: A. The force capacity at approximately the same deflection

Question 8

Which condition is most directly associated with surge in a compression spring?

A. Slow static loading only

B. Operation near a spring natural frequency

C. A large flywheel radius

D. Low material density in a leaf spring

Correct Answer: B. Operation near a spring natural frequency

Question 9

A torsion bar stores energy through which principal deformation?

A. Axial crushing

B. Elastic twist in torsion

C. Uniform thermal expansion

D. Plastic buckling only

Correct Answer: B. Elastic twist in torsion

Question 10

Which statement best describes a damper compared with an ideal steel spring?

A. A damper primarily dissipates energy, while an ideal spring returns it

B. A damper stores all energy permanently

C. A damper cannot experience fatigue

D. A damper always has a linear force–deflection curve

Correct Answer: A. A damper primarily dissipates energy, while an ideal spring returns it

Mechanical Systems Design
Chapter 9 of 15