Fluid Mechanics and Fluid PowerIntroduction and ContextFluid mechanics is the study of fluids at rest and in motion. A fluid is a substance that deforms continuously under any applied shear stress; liquids and gases are therefore treated differently from solids. In mechatronics, fluid mechanics connects mechanical energy, sensing, control, and actuation. Hydraulic systems transmit force through nearly incompressible liquids, while pneumatic systems use compressible gases for rapid, clean, and relatively lightweight motion. A mechatronics engineer must be able to determine pressure and flow requirements, estimate losses in pipes and components, select pumps and compressors, size actuators, and integrate valves with sensors and controllers. The analysis begins with conservation of mass, momentum, and energy, supported by experimentally established models of internal flow. Learning ObjectivesBy the end of this chapter, a student should be able to: - Define important fluid properties and use consistent SI units.
- Calculate hydrostatic pressure and forces on immersed surfaces.
- Apply continuity, Bernoulli’s equation, and the mechanical-energy equation.
- Determine frictional and minor pressure losses in internal flow.
- Use Reynolds number and dimensional reasoning to select appropriate flow models.
- Estimate flow rates, pump power, and compressor requirements.
- Select and analyze hydraulic and pneumatic actuators, valves, and piping.
- Recognize the safety, efficiency, control, and environmental limitations of fluid-power systems.
1. Fluid Properties and Fundamental Quantities1.1 Density, specific weight, and specific gravityDensity is mass per unit volume: ρ = m/V Here, ρ is density in kg/m³, m is mass in kg, and V is volume in m³. The specific weight is weight per unit volume: γ = ρg where γ is in N/m³ and g is gravitational acceleration, approximately 9.81 m/s². Specific gravity is the ratio of a fluid’s density to the density of a reference fluid, usually water at standard conditions: SG = ρ/ρwater Specific gravity is dimensionless. Temperature must be stated because density and viscosity vary with temperature. 1.2 ViscosityDynamic viscosity μ measures resistance to shearing motion. For a Newtonian fluid, the shear stress is proportional to the velocity gradient: τ = μ(du/dy) τ is shear stress in Pa, u is velocity parallel to a surface, y is the normal coordinate, and μ is dynamic viscosity in Pa·s. Kinematic viscosity is ν = μ/ρ with units m²/s. Water has relatively low viscosity, whereas hydraulic oils are selected partly for their controlled viscosity and lubricating ability. The Newtonian relation is applicable when viscosity is approximately independent of shear rate. Some paints, polymer solutions, and biological fluids are non-Newtonian and require more complex constitutive models. 1.3 Pressure and compressibilityPressure is normal force per unit area: p = F/A Absolute pressure is measured relative to a perfect vacuum. Gauge pressure is measured relative to local atmospheric pressure: pabs = pgauge + patm A negative gauge pressure indicates pressure below atmospheric pressure. Vapor pressure is important because if local absolute pressure falls below the fluid’s vapor pressure, cavitation may occur. Liquids are often modeled as incompressible, but this is an approximation. Gases are strongly compressible, particularly when pressure changes are significant. Bulk modulus describes liquid resistance to compression: K = −V(dp/dV) where K is bulk modulus in Pa. A large K indicates small volume change for a given pressure change. 1.4 Surface tension and capillaritySurface tension becomes important in small channels, droplets, and microfluidic devices. It is generally less important in conventional hydraulic cylinders and industrial pipes. Capillary effects can nevertheless influence sensors and small pneumatic or fluidic passages. 2. HydrostaticsHydrostatics concerns fluids at rest. For a fluid of constant density in a gravitational field, pressure increases with depth: p = p0 + ρgh p₀ is pressure at a reference free surface, h is vertical depth below that surface, and ρgh is the pressure increase. The equation assumes the fluid is stationary, density is constant, and gravitational acceleration is uniform. 2.1 Pascal’s lawPascal’s law states that a pressure change applied to a confined fluid is transmitted throughout the fluid. In an ideal hydraulic press, equal pressure acts on two pistons: F1/A1 = F2/A2 Thus, a small input force can produce a larger output force when the output piston has a larger area. Energy is not created: the larger force moves through a proportionally smaller distance in an ideal system. 2.2 Hydrostatic force on a plane surfaceFor a plane surface submerged in a liquid, the resultant hydrostatic force is FR = ρg hc A where h_c is the vertical depth of the surface centroid and A is the surface area. The force acts at the center of pressure, which is below the centroid for a vertical or inclined plane because pressure increases with depth. For a plane surface inclined at angle θ to the horizontal: yR = yc + IG sin²θ/(yc A) Here y_R is center-of-pressure distance measured along the plane, y_c is centroid distance, I_G is the second moment of area about the centroidal axis parallel to the free surface, and θ is the inclination. This relation assumes a plane surface and a liquid of constant density. Worked Example 1: Hydrostatic forceA vertical rectangular gate 0.80 m wide and 1.20 m high has its top edge 2.0 m below the water surface. Determine the resultant force and the depth of its line of action. The area is A = 0.80 × 1.20 = 0.96 m². The centroid depth is h_c = 2.0 + 1.20/2 = 2.60 m. Therefore, FR = ρghcA = (1000)(9.81)(2.60)(0.96) = 24,460 N ≈ 24.5 kN For a vertical rectangle, I_G = bh³/12 = (0.80)(1.20³)/12 = 0.1152 m⁴. The center-of-pressure depth is hR = hc + IG/(hcA) = 2.60 + 0.1152/(2.60 × 0.96) = 2.646 m The force acts approximately 2.65 m below the free surface. 3. Conservation Laws for Fluid Flow3.1 System and control-volume viewpointsA system follows a fixed quantity of fluid. A control volume is a selected region through which fluid may flow. Engineering devices such as valves, pumps, turbines, nozzles, and cylinders are most conveniently analyzed as control volumes. 3.2 Conservation of massFor steady flow, the mass flow rate is ṁ = ρAV where ṁ is mass flow rate in kg/s, A is cross-sectional area, and V is mean velocity normal to the area. For steady flow with constant density between two sections: A1V1 = A2V2 = Q Q is volumetric flow rate in m³/s. For compressible flow, density must generally remain in the mass-flow equation. 3.3 Bernoulli’s equationFor steady, incompressible, inviscid flow along a streamline with no pump or turbine and negligible heat transfer effects, Bernoulli’s equation is p/(ρg) + V²/(2g) + z = constant The three terms are pressure head, velocity head, and elevation head. The equation is an ideal energy balance. Real internal flows require loss terms and often pump or turbine terms. 3.4 Mechanical-energy equationA practical form between sections 1 and 2 is p1/(ρg) + α1V1²/(2g) + z1 + hp = p2/(ρg) + α2V2²/(2g) + z2 + ht + hL h_p is pump head added, h_t is turbine head removed, h_L is total head loss, and α is the kinetic-energy correction factor. For fully developed turbulent flow, α is often close to 1; for laminar pipe flow, α = 2. The equation assumes steady flow and uses mean velocity at each section. The total loss is commonly separated into major and minor losses: hL = hf + ∑hm 4. Dimensional Analysis and Internal Flow4.1 Reynolds numberThe Reynolds number compares inertial and viscous effects: Re = ρVD/μ = VD/ν For circular pipe flow, D is pipe diameter and V is mean velocity. In a long, smooth circular pipe, flow is generally considered laminar for Re < approximately 2300, transitional for approximately 2300–4000, and turbulent above approximately 4000. These limits are guidelines, not universal discontinuities. Dimensional analysis is useful because it identifies governing nondimensional groups and reduces experimental data. Other important groups include the Froude number for free-surface effects and the Mach number for compressible flow: Fr = V/√(gL) Ma = V/a L is a characteristic length and a is the speed of sound. Compressibility becomes especially important in gases when Mach number is not small or when pressure changes are large. 4.2 Laminar pipe flowFor fully developed, steady, incompressible, laminar flow in a circular pipe, the Hagen–Poiseuille relation is Q = πD⁴∆p/(128μL) where ∆p is pressure drop and L is pipe length. The strong D⁴ dependence shows why small passages cause large resistance. The corresponding Darcy friction factor is f = 64/Re This f is the Darcy friction factor, not the Fanning friction factor, which is one quarter as large. 4.3 Turbulent pipe flow and Darcy–Weisbach lossFor fully developed flow in a constant-diameter pipe, the Darcy–Weisbach equation is hf = f(L/D)(V²/(2g)) The pressure loss is ∆p_f = ρgh_f. The Darcy friction factor f depends on Reynolds number and relative roughness ε/D, where ε is absolute roughness. For turbulent flow it may be obtained from a Moody chart or an explicit approximation such as Swamee–Jain: f ≈ 0.25/[log₁₀(ε/(3.7D) + 5.74/Re⁰·⁹)]² This approximation is intended for turbulent flow and engineering estimation; the Colebrook equation or validated software may be preferred for precision. 4.4 Minor lossesFittings, entrances, exits, bends, tees, filters, and valves cause local losses: hm = K(V²/(2g)) K is a dimensionless loss coefficient associated with the component and operating condition. A valve that is partly closed may have a much larger K than a fully open valve. For accurate design, manufacturer data should replace generic tabulated values. Worked Example 2: Pipe pressure loss and pump headWater flows at Q = 0.010 m³/s through a 50 mm internal-diameter pipe of length 30 m. Assume mean velocity is based on the full area, Darcy friction factor f = 0.020, and the total minor-loss coefficient is K = 2.5. Find the total head loss. The area is A = πD²/4 = π(0.050)²/4 = 0.001963 m² Mean velocity is V = Q/A = 0.010/0.001963 = 5.09 m/s. The velocity head is V²/(2g) = 5.09²/(19.62) = 1.32 m. Major loss: hf = 0.020(30/0.050)(1.32) = 15.84 m Minor loss: hm = 2.5(1.32) = 3.30 m Thus h_L = 15.84 + 3.30 = 19.14 m of water. The associated pressure loss is ρgh_L = 1000 × 9.81 × 19.14 ≈ 188 kPa. If the pump must supply this loss with no elevation change and no turbine, its required theoretical head is at least 19.14 m, before allowing for pump inefficiency and control margin. 5. Pumps, Compressors, and System Selection5.1 Pump head and powerA pump increases the fluid’s mechanical energy. Hydraulic power delivered to the fluid is Ph = ρgQhp If pump efficiency is η_p, shaft power is Pshaft = ρgQhp/ηp Efficiency includes hydraulic, volumetric, and mechanical effects in aggregate. A pump should be selected from its manufacturer’s head–flow curve, efficiency map, allowable operating region, and net positive suction head requirements—not from nominal maximum flow alone. Cavitation occurs when pressure falls sufficiently for vapor bubbles to form and collapse. A practical check compares available and required net positive suction head: NPSHA > NPSHR with an engineering safety margin. NPSH values depend on absolute pressure, temperature, suction losses, and pump operating point. 5.2 Positive-displacement and dynamic pumpsCentrifugal pumps are dynamic pumps suited to continuous flow and moderate-to-high flow rates. Their flow decreases as system head rises. Positive-displacement pumps, including gear, vane, piston, and screw pumps, trap and displace a nearly fixed volume per cycle. They are suitable for high pressure and controlled flow but require a relief path because dead-heading can produce dangerous pressure. 5.3 Compressors and pneumatic powerCompressors raise gas pressure. Unlike hydraulic liquids, gases store substantial elastic energy, so pneumatic systems can be spring-like and less position-stiff. Compressor selection considers free-air delivery, pressure range, duty cycle, receiver capacity, moisture control, noise, and efficiency. For an ideal gas, the equation of state is pV = mRsT where p is absolute pressure, V is volume, m is mass, R_s is the gas-specific constant, and T is absolute temperature in kelvin. Gauge pressure must not be used directly in this equation. For steady adiabatic compression, a simplified ideal-gas relation is pVk = constant where k is the ratio of specific heats. Real compressors require efficiency and heat-transfer corrections, so manufacturer maps are essential for final design. 6. Fluid Power: Hydraulic and Pneumatic Actuation6.1 Hydraulic cylinders and motorsThe ideal force of a hydraulic cylinder is F = pA where p is pressure above the return-side pressure and A is effective piston area. For a cylinder of bore diameter D, A = πD²/4 The ideal flow required for extension at velocity v is Q = Av Actual force is reduced by friction and leakage. During retraction, the effective area is the annular area because the rod occupies part of the cylinder: Aannulus = π(D² − d²)/4 where d is rod diameter. Hydraulic motors convert fluid power into torque and speed. Their displacement, pressure difference, volumetric efficiency, and mechanical efficiency determine output performance. 6.2 Pneumatic cylindersPneumatic cylinders follow F = pA approximately, but compressibility, friction, supply pressure variation, and exhaust back pressure produce less rigid motion. Pneumatics are attractive where low mass, rapid cycling, cleanliness, and moderate force are important. Hydraulics are preferred for high force density, stiffness, and controlled low-speed motion. 6.3 Valves and circuit functionsValves perform four principal functions: - Directional control valves route flow to extend, retract, or stop an actuator.
- Pressure-control valves limit, reduce, sequence, or regulate pressure.
- Flow-control valves regulate actuator speed.
- Check valves permit one-way flow and prevent reverse motion or backflow.
A proportional or servo valve enables continuous control of flow or pressure. Solenoid directional valves provide simpler discrete control. Valve sizing must consider rated flow, pressure drop, leakage, response time, contamination tolerance, and fail-safe position. 6.4 Metering and actuator speedFor an incompressible actuator, speed is controlled by Q/A. Excessive throttling converts mechanical energy into heat. In hydraulic systems, a pressure-compensated flow-control valve can maintain approximately constant flow despite load changes. In pneumatic systems, exhaust metering often gives more stable cylinder motion than inlet metering, although the correct choice depends on load and circuit behavior. Worked Example 3: Hydraulic cylinder sizingA hydraulic cylinder must produce 20 kN while operating at a pressure differential of 10 MPa. Neglecting friction, find the minimum bore diameter. If the desired extension speed is 0.20 m/s, find the required flow rate. Required area: A = F/p = 20,000/(10 × 10⁶) = 0.00200 m² Therefore, D = √(4A/π) = √(0.00800/π) = 0.0505 m A nominal 51 mm or larger bore would be required ideally; a practical selection would include a margin for friction, pressure variation, and rated capacity. The flow is Q = Av = 0.00200 × 0.20 = 0.000400 m³/s Thus Q = 0.40 L/s or 24 L/min. The pump and valve must be rated for this flow at the required pressure, with appropriate transient and thermal allowances. 7. Applied Case: Automated Hydraulic Clamping StationBackgroundThis illustrative case concerns a robotic machining cell in which a hydraulic cylinder clamps a workpiece before drilling. The clamp must generate 18 kN, extend 150 mm in 0.75 s, and release reliably when the machine controller commands a cycle change. ProblemThe design must establish cylinder size, flow demand, valve arrangement, pressure protection, and control safeguards. The system must avoid excessive impact at end of stroke and must not release the workpiece during loss of electrical power. AnalysisSuppose the available working pressure is 8 MPa. The ideal piston area is A = F/p = 18,000/(8 × 10⁶) = 0.00225 m² The theoretical bore is D = √(4A/π) = 0.0535 m. Allowing for seal friction and a design margin, a 63 mm bore may be selected. Its piston area is A = π(0.063)²/4 = 0.003117 m². At a target extension speed of 0.20 m/s, the required flow is Q = 0.000623 m³/s, approximately 37.4 L/min. The circuit should include a reservoir, pump, suction strainer, pressure-relief valve, pressure gauge or transducer, directional valve, flow-control valve, cylinder, return filter, and a mechanically or pilot-operated load-holding valve. Pipe diameter should be selected so that velocity and pressure loss remain acceptable. The relief valve protects against blocked flow; it is not a substitute for correct control logic. Approach and solutionA normally controlled directional valve extends the cylinder. A flow-control valve limits extension speed, and a cushioning feature or deceleration command reduces end-of-stroke impact. A pressure switch or transducer verifies that clamp force has been reached. The machine controller permits drilling only when both position and pressure conditions are valid. On power loss, the load-holding valve prevents uncontrolled release, subject to a documented risk assessment. Outcome and learning pointsThe design demonstrates that actuator sizing alone is insufficient. Reliable fluid-power engineering requires coordinated selection of pressure, flow, valves, piping, sensors, control logic, and safety functions. Commissioning should measure actual pressure, flow, cycle time, temperature, leakage, and stopping behavior. Hydraulic cleanliness is also critical: contamination can cause valve sticking, seal damage, and unpredictable motion. 8. Design Practice, Safety, and Limitations8.1 Piping and component selectionPiping should be sized using allowable velocity, pressure loss, acoustic limits, space, cost, and transient behavior. Oversized pipes reduce losses but increase cost and fluid volume; undersized pipes increase loss, heat generation, noise, and actuator delay. Flexible hoses must be rated for pressure, temperature, compatibility, bend radius, and impulse duty. Filters and strainers must be sized for required flow and acceptable pressure drop. Hydraulic oil selection considers viscosity index, oxidation resistance, fire resistance, seal compatibility, and environmental requirements. Pneumatic systems require filtration, regulation, and often lubrication only where specified by component manufacturers. 8.2 Safety and regulatory responsibilitiesStored hydraulic and pneumatic energy can cause unexpected motion after the machine is switched off. Safe systems require isolation, lockout/tagout, pressure release, blocking or mechanical support, guarding, and verification of zero-energy state. Relief devices must discharge safely and be maintained. Designers should apply applicable machinery, pressure-equipment, electrical, and occupational-safety standards in the jurisdiction of use. Fluid injection injuries from hydraulic leaks are medical emergencies. A leak must never be located with a hand. Pneumatic exhaust can propel parts or generate harmful noise. Risk assessment should consider foreseeable misuse, hose rupture, loss of control signal, sensor failure, and maintenance access. 8.3 Efficiency and environmental issuesThrottling is simple but inefficient because pressure energy is dissipated as heat. Variable-displacement pumps, load-sensing circuits, accumulators, regenerative circuits, and efficient electric drives can reduce energy consumption. Leakage control reduces both cost and environmental contamination. Hydraulic fluids must be collected and disposed of according to environmental regulations. 8.4 Modeling limitations and transient effectsSteady-flow equations do not fully predict water hammer, hose expansion, valve switching transients, or pneumatic shock. Rapid valve closure can generate large pressure waves. Compressible pneumatic systems may require dynamic simulation using chamber pressure, mass flow, and thermodynamic energy equations. For high-speed or safety-critical systems, validated simulation and experimental testing are required. 9. Contemporary Developments and Mechatronic IntegrationModern fluid-power systems increasingly use pressure transducers, flow sensors, linear position sensors, and networked proportional valves. Closed-loop control can compensate for load variation and leakage. Digital hydraulic valves and electrohydraulic pumps allow variable displacement and improved energy management. Condition monitoring can infer filter blockage, internal leakage, pump wear, or abnormal temperature from pressure-flow data. Artificial intelligence can assist anomaly detection and predictive maintenance, but it should not replace physical safety devices, relief valves, independent interlocks, or engineering verification. Training data may not include rare failures, and a model’s prediction must be explainable enough for maintenance and safety decisions. A sound architecture keeps emergency shutdown and overpressure protection independent of data-driven optimization. Best-Practice Checklist- Use absolute pressure in gas-law and cavitation calculations.
- State fluid properties and temperature.
- Distinguish gauge pressure from pressure difference.
- Check Reynolds number before selecting a friction model.
- Include both distributed and local losses.
- Use manufacturer curves for pumps, valves, and fittings where available.
- Check pump operating point, efficiency, and NPSH.
- Size actuators for force, speed, friction, and safety margin.
- Provide relief, isolation, load holding, and controlled discharge functions.
- Verify the design experimentally under normal and fault conditions.
Chapter SummaryFluid mechanics supplies the analytical basis for mechatronic fluid-power systems. Density, viscosity, pressure, and compressibility determine how fluids transmit force and resist motion. Hydrostatic pressure varies with depth, and Pascal’s law explains hydraulic force multiplication. Conservation of mass gives the relationship between flow rate, area, and velocity, while the mechanical-energy equation accounts for elevation, pressure, pump work, and losses. Reynolds number distinguishes laminar and turbulent regimes. Laminar flow can be modeled with Hagen–Poiseuille’s relation; practical turbulent pipe losses are commonly estimated with Darcy–Weisbach and a friction factor based on Reynolds number and roughness. Minor losses from valves and fittings may be decisive in compact systems. Pump and compressor selection must consider operating point, efficiency, pressure, flow, temperature, and cavitation or compressibility effects. Hydraulic cylinders provide high force and stiffness, whereas pneumatic actuators offer speed, simplicity, and clean operation but lower positional stiffness. Effective designs integrate actuators with correctly sized valves, piping, sensors, relief devices, control logic, and safety procedures. Energy efficiency, contamination control, transient behavior, regulatory compliance, and independent protective functions are essential professional concerns. Key TermsDensity: Mass per unit volume of a fluid. Viscosity: A fluid’s resistance to shearing motion. Gauge pressure: Pressure measured relative to atmospheric pressure. Absolute pressure: Pressure measured relative to a perfect vacuum. Hydrostatics: Study of fluids at rest. Pascal’s law: Pressure applied to a confined fluid is transmitted throughout the fluid. Continuity equation: Conservation of mass applied to fluid flow. Bernoulli’s equation: Ideal mechanical-energy relation for flowing fluid. Head: Energy per unit weight of fluid, expressed in metres of fluid. Reynolds number: Dimensionless ratio of inertial to viscous effects. Darcy friction factor: Dimensionless factor used in Darcy–Weisbach pipe-loss calculations. Minor loss: Local energy loss caused by fittings, entrances, exits, or valves. Cavitation: Formation and collapse of vapor bubbles due to low absolute pressure. NPSH: Net positive suction head used to assess pump cavitation risk. Positive-displacement pump: Pump that moves trapped fluid volume per cycle. Hydraulic actuator: Actuator powered by pressurized liquid. Pneumatic actuator: Actuator powered by compressed gas. Load-holding valve: Valve that prevents unintended actuator motion under load. Bulk modulus: Measure of a fluid’s resistance to compression. Relative roughness: Absolute pipe roughness divided by pipe diameter. Review QuestionsShort Answer Questions- Distinguish absolute pressure from gauge pressure.
- State the assumptions behind the incompressible continuity relation Q = AV.
- What physical effects are compared by Reynolds number?
- Why does a hydraulic cylinder generally produce more positional stiffness than a pneumatic cylinder?
- Explain the purpose of a pressure-relief valve.
Long Answer Questions- Derive the hydrostatic pressure relation for a constant-density fluid and discuss its engineering applications.
- Explain the mechanical-energy equation, including pump head, turbine head, and major and minor losses.
- Compare centrifugal and positive-displacement pumps in terms of operating characteristics and applications.
- Describe the design and safety requirements of a hydraulic clamping circuit.
- Explain how viscosity, temperature, roughness, and Reynolds number influence pipe pressure loss.
Analytical / Application Questions- Water flows through a 40 mm pipe at 0.006 m³/s. Determine the mean velocity and Reynolds number using μ = 1.0 × 10⁻³ Pa·s and ρ = 1000 kg/m³. Classify the flow using the usual pipe-flow guidelines.
- A cylinder with a 60 mm bore must extend at 0.15 m/s. Determine its ideal flow requirement in L/min and the force produced at a pressure difference of 6 MPa.
- A pump supplies 0.012 m³/s through a system requiring 28 m of head. If pump efficiency is 72%, determine the required shaft power and discuss two methods of reducing operating energy.
Multiple Choice Questions with AnswersQuestion 1Which property is defined as mass per unit volume? A. Dynamic viscosity B. Density C. Specific weight D. Bulk modulus Correct Answer: B. Density Question 2Water is 2.0 m below a free surface open to the atmosphere. What is its gauge pressure approximately? A. 9.81 kPa B. 19.6 kPa C. 98.1 kPa D. 196 kPa Correct Answer: B. 19.6 kPa Question 3For steady incompressible flow in a constant-diameter pipe, if the flow rate doubles, the mean velocity: A. Is unchanged B. Is halved C. Doubles D. Increases fourfold Correct Answer: C. Doubles Question 4The Reynolds number primarily compares: A. Pressure and elevation effects B. Inertial and viscous effects C. Elastic and thermal effects D. Gravity and surface-tension effects Correct Answer: B. Inertial and viscous effects Question 5Which equation is commonly used to estimate frictional head loss in a pipe? A. Darcy–Weisbach equation B. Ideal-gas equation C. Pascal equation D. Archimedes equation Correct Answer: A. Darcy–Weisbach equation Question 6A hydraulic cylinder has an effective area of 0.002 m² and operates at a pressure difference of 5 MPa. Neglecting friction, its force is: A. 1 kN B. 2.5 kN C. 10 kN D. 25 kN Correct Answer: C. 10 kN Question 7Which device protects a positive-displacement hydraulic pump from excessive pressure when flow is blocked? A. Pressure-relief valve B. Check valve only C. Flow diffuser D. Vacuum breaker only Correct Answer: A. Pressure-relief valve Question 8The ideal hydraulic power delivered to fluid is calculated using: A. ρgQh_p B. μQ/L C. pV/m D. ρA/V Correct Answer: A. ρgQh_p Question 9Why is absolute pressure required in the ideal-gas equation? A. Gas volume is always measured at atmospheric pressure B. The equation relates pressure to a vacuum reference C. Gauge pressure has units of velocity D. Absolute pressure eliminates temperature Correct Answer: B. The equation relates pressure to a vacuum reference Question 10A major safety concern specific to stored fluid-power energy is: A. Unexpected actuator motion after shutdown B. Zero pressure during operation C. Elimination of all leakage D. Automatic reduction of noise Correct Answer: A. Unexpected actuator motion after shutdown
|