Machine Tool Design

Chapter 3
Machining Mechanics, Forces and Power Requirements

Bachelors Program in Machine Technology
Machine Tool Design   •   Bachelor

Machining Mechanics, Forces and Power Requirements

Introduction

Machine tools must remove material at a controlled rate while maintaining accuracy, surface integrity, productivity, and safe operation. The cutting tool, workpiece, machine structure, spindle, feed drive, and coolant system form a coupled mechanical system. Cutting forces generated in the chip-formation zone determine spindle torque, motor power, structural deflection, bearing loads, vibration, tool wear, and ultimately dimensional accuracy.

This chapter develops practical methods for estimating machining forces, torque, speed, power, specific energy, duty cycle, machinability, and tool life. The relationships are engineering models rather than exact descriptions of every cutting process. Their reliability depends on material data, tool geometry, cutting conditions, and the validity of assumptions such as steady cutting and uniform material removal.

Learning Objectives

After completing this chapter, a student should be able to:

  1. Explain chip formation and the principal force components in machining.
  2. Calculate cutting speed, spindle speed, material-removal rate, torque, and power.
  3. Resolve forces in orthogonal cutting and interpret their effects on machine-tool design.
  4. Estimate power requirements for turning, milling, and drilling.
  5. Distinguish cutting power from total machine input power and account for efficiency.
  6. Calculate duty cycle and energy consumption for intermittent operations.
  7. Apply machinability criteria and Taylor tool-life relationships.
  8. Select a spindle or drive system using force, torque, power, speed, and stiffness considerations.

1. Mechanics of Material Removal

1.1 Chip formation

In cutting, the tool advances relative to the workpiece and produces a chip by severe plastic deformation. In an idealized orthogonal-cutting model, the cutting edge is perpendicular to the cutting velocity and the chip flows normal to the edge. Oblique cutting, which is more common in practice, includes a chip-flow angle and three-dimensional force components.

The work material ahead of the tool is subjected to compression, shear, friction, and heat. A primary shear zone forms where material changes from workpiece to chip. A secondary deformation zone occurs along the tool–chip interface, and a tertiary zone may occur where the tool flank rubs against the newly machined surface.

The undeformed chip thickness is denoted by t1, and the deformed chip thickness by t2. The chip-thickness ratio is:

r = t1/t2

where r is dimensionless. Since chips generally thicken during cutting, t2 > t1 and therefore r < 1. For orthogonal cutting with rake angle α, the shear-plane angle φ is related to the chip ratio by:

tan φ = (r cos α)/(1 − r sin α)

This geometric relation assumes a continuous chip and a well-defined shear plane. It becomes less reliable for segmented chips, built-up edges, highly elastic materials, or strongly three-dimensional cutting.

1.2 Cutting-force components

The principal force in a turning operation is the tangential or cutting force, Fc. It acts approximately in the direction opposite to cutting velocity and determines most of the cutting power. The feed force, Ff, acts in the feed direction. The radial or passive force, Fp, acts approximately normal to the machined surface and can cause tool deflection and workpiece error.

A useful engineering model is:

Fc = kc Ac

where kc is the specific cutting force in N/mm² and Ac is the uncut chip cross-sectional area in mm². For turning:

Ac = f ap

where f is feed per revolution in mm/rev and ap is depth of cut in mm. Thus:

Fc = kc f ap

This equation is a first-order estimate. Specific cutting force varies with workpiece material, chip thickness, rake angle, tool wear, cutting speed, and lubrication. Thin cuts often show a higher apparent specific force because of size effects and edge-radius effects.

The other force components may be estimated using experimentally determined ratios:

Ff = Kf Fc, Fp = Kp Fc

where Kf and Kp are dimensionless coefficients. These coefficients must be obtained from tests, tooling data, or a validated process model; they should not be assumed universal.

1.3 Merchant force analysis

For orthogonal cutting, the measured resultant force R can be resolved into a friction force F along the tool–chip interface and a normal force N. If Fc is the cutting force and Ft is the thrust force, then:

R = √(Fc² + Ft²)

For rake angle α and shear angle φ, the shear force along the shear plane and the normal force on that plane are:

Fs = Fc cos φ − Ft sin φ
Fn = Fc sin φ + Ft cos φ

The friction force and normal force at the tool–chip interface are:

F = Fc sin α + Ft cos α
N = Fc cos α − Ft sin α

The apparent coefficient of friction is:

μ = F/N

and the friction angle is β = tan-1(μ). These equations assume orthogonal cutting, a stationary tool geometry, and forces measured in a consistent coordinate system. They are valuable for interpreting experiments but do not fully represent ploughing, flank wear, or three-dimensional oblique cutting.

1.4 Shear-plane area and shear stress

If the width of cut is b and the uncut chip thickness is t1, the shear-plane area is:

As = (b t1)/(sin φ)

The average shear stress on the shear plane is:

τs = Fs/As

where τs is in N/mm² when force is in N and area is in mm². The calculated value is an average, because the actual stress distribution is nonuniform. It is influenced by strain hardening, strain rate, temperature, and hydrostatic pressure.

2. Speed, Feed, and Material Removal Rate

2.1 Cutting speed and spindle speed

For turning, the cutting speed at workpiece diameter D is:

V = π D N/1000

when D is in mm, N is in rev/min, and V is in m/min. Therefore:

N = 1000V/(πD)

For milling, if D is the cutter diameter, the same relation applies approximately at the cutter periphery. In drilling, the drill diameter is used.

In turning, feed speed is:

vf = fN

where vf is in mm/min if f is in mm/rev and N is in rev/min.

2.2 Material-removal rate

For turning with a cylindrical workpiece, a practical approximation is:

Q = π Dm ap f N

where Q is in mm³/min and Dm is the mean diameter during the cut. This assumes a constant depth of cut and feed.

For milling:

Q = ap ae vf

where ap is axial depth of cut, ae is radial width of cut, and vf is table feed. For drilling, the approximate removal rate is:

Q = (πD²/4) fN

These expressions describe geometric volume removal. Engagement variations, tool entry and exit, interrupted cutting, and chip evacuation can make the actual average rate different.

3. Torque and Power Requirements

3.1 Cutting power

Mechanical cutting power is the product of the force component in the velocity direction and the velocity:

Pc = Fc V

If Fc is in newtons and V is in m/s, Pc is in watts. With force in newtons and cutting speed in m/min:

Pc(kW) = Fc V/60000

The same power can be expressed using torque T and angular speed ω:

Pc = Tω

where ω = 2πN/60 in rad/s when N is in rev/min. Torque is therefore:

T = 9550 Pc/N

when torque is in N·m, power is in kW, and speed is in rev/min.

The motor input power must exceed cutting power because of transmission, bearing, drive, and motor losses:

Pmotor = Pc/ηtotal

where ηtotal is the overall efficiency between motor input and cutting action. A design must also consider acceleration, overload capacity, peak torque, and thermal duty rather than only average power.

3.2 Specific cutting energy

Specific cutting energy is the energy required to remove a unit volume of material:

u = Pc/Q

Use consistent units. If power is in N·mm/min and removal rate is in mm³/min, u is in N/mm², equivalent to J/mm³ because 1 N·mm = 1 J. Specific energy includes plastic deformation, friction, and sometimes rubbing losses, depending on how it is measured.

A useful power estimate is:

Pc = uQ

This approach is especially convenient for milling and drilling, where instantaneous force changes with engagement.

Worked Example 1: Turning power and torque

A steel shaft is turned at a cutting speed of 120 m/min, feed 0.25 mm/rev, and depth of cut 2 mm. The specific cutting force is estimated as 2,000 N/mm². The workpiece diameter during cutting is 80 mm. Determine cutting force, spindle speed, cutting power, and torque.

The uncut chip area is:

Ac = fap = 0.25 × 2 = 0.50 mm²

Therefore:

Fc = 2000 × 0.50 = 1000 N

Spindle speed is:

N = 1000(120)/(π × 80) ≈ 477.5 rev/min

Cutting power is:

Pc = (1000 × 120)/60000 = 2.00 kW

Torque is:

T = 9550(2.00)/477.5 ≈ 40.0 N·m

If total efficiency is 0.80, the required motor input power is 2.00/0.80 = 2.50 kW. A practical selection would include a margin for tool wear, transient engagement, and uncertain material data.

4. Process-Specific Force and Power Models

4.1 Turning

Turning forces are commonly estimated from chip area and specific cutting force. The tangential force controls spindle power, while radial force strongly affects workpiece deflection. For a slender shaft, even a moderate radial force may cause taper, chatter, or dimensional error. Machine-tool design must therefore consider stiffness as well as motor rating.

The bending deflection of a simplified cantilever workpiece under an end load can be estimated by:

δ = F L³/(3EI)

where F is transverse force, L is overhang length, E is Young’s modulus, and I is the second moment of area. For a solid circular shaft of diameter d, I = πd⁴/64. This idealization neglects support compliance, distributed loading, and dynamic effects, but it demonstrates why overhang and diameter are critical.

4.2 Milling

Milling is intermittent. Each tooth enters and leaves the workpiece, so instantaneous force and power fluctuate. If there are z teeth and the feed per tooth is fz, table feed is:

vf = z fz N

The average material-removal rate is approximately Q = ap ae vf. Power may be estimated from specific energy, but peak tooth force must be checked separately because it determines tooth strength, spindle torque ripple, and vibration.

For a simplified tooth, instantaneous tangential force can be represented as:

Ft(θ) = Kt ap h(θ) + Kteap

where Kt is a cutting coefficient, h(θ) is instantaneous chip thickness, and Kte represents edge or ploughing effects. The equation is a mechanistic model whose coefficients must be identified for a particular tool–workpiece pair. It should not be used without accounting for tooth engagement angles.

4.3 Drilling

Drilling produces both torque and thrust. Torque is associated mainly with material removal at the lips and friction along the margins; thrust includes deformation at the chisel edge and cutting action at the lips. A common engineering form is:

T = KT D² f
Fz = KF D f

where D is drill diameter, f is feed per revolution, and KT and KF are experimentally determined constants with process-dependent units. Since these coefficients depend strongly on drill geometry and material, catalog data or tests should be preferred.

Drilling power is:

Pc = 2πNT/60

when N is in rev/min and T is in N·m, producing watts. Peck drilling, coolant pressure, hole depth, and chip evacuation can cause peak loads that exceed steady-state estimates.

5. Duty Cycle, Energy, and Thermal Loading

Machine tools rarely cut continuously at maximum power. A duty cycle represents the fraction of a time interval during which a specified operating condition occurs:

Dc = ton/(ton + toff)

For multiple operating states, average power is:

Pavg = (Σ Pi ti)/(Σ ti)

The energy consumed over the cycle is:

E = Σ Pi ti

If power is in kW and time in hours, energy is in kWh. Motor selection must distinguish continuous thermal rating from short-duration overload rating. A spindle may deliver high power briefly but overheat if the average thermal load is excessive.

Worked Example 2: Milling duty cycle

A milling cycle contains 30 s of cutting at 6 kW, 10 s of rapid motion at 1 kW, and 20 s of loading at 0.2 kW. The total cycle time is 60 s. The average power is:

Pavg = (6×30 + 1×10 + 0.2×20)/60 = 3.57 kW

The cutting duty cycle is 30/60 = 0.50, or 50%. Energy per cycle is 3.57 kW × 60/3600 h = approximately 0.0595 kWh. Although average power is moderate, the drive must still tolerate the 6 kW cutting interval and its associated peak torque.

6. Machinability and Tool Life

Machinability is the ease with which a material can be machined to the required surface finish, dimensional accuracy, tool life, and production rate. It is not a single intrinsic material constant. Important indicators include cutting force, power consumption, tool wear rate, achievable speed, surface roughness, chip control, and susceptibility to built-up edge.

Material properties influencing machinability include hardness, ductility, strain hardening, thermal conductivity, abrasiveness, and chemical affinity for the tool. A soft, ductile alloy may produce long, tangled chips, whereas a harder material may produce high forces and rapid flank wear.

6.1 Taylor tool-life equation

The classical Taylor relationship is:

V Tn = C

where V is cutting speed, T is tool life, n is the tool-life exponent, and C is the Taylor constant for a specified tool–workpiece combination, tool geometry, and wear criterion. The equation applies over a limited range of stable cutting conditions. It does not automatically account for feed, depth of cut, coolant, intermittent engagement, or changing tool geometry.

A generalized form is:

V Tn fm app = C'

where f is feed, ap is depth of cut, and m, p, and C' are experimentally fitted constants. Because fitted exponents depend on the experiment, this equation should be used only with appropriate data.

The two-point method for the classical equation uses two tests:

n = ln(V1/V2)/ln(T2/T1)

and then C = V1T1n.

Worked Example 3: Tool-life estimation

A tool lasts 60 min at 100 m/min and 15 min at 160 m/min. Estimate n and the life at 130 m/min.

Using the two-point equation:

n = ln(100/160)/ln(15/60) = (-0.4700)/(-1.3863) ≈ 0.339

The Taylor constant is approximately:

C = 100(600.339) ≈ 393 m/min·minn

At 130 m/min:

T = (C/V)1/n = (393/130)1/0.339 ≈ 30.9 min

The result is an estimate. Tool life may differ substantially if the tool changes from continuous to interrupted cutting or if the wear criterion changes.

6.2 Wear mechanisms and criteria

Flank wear is commonly measured by average or maximum flank-wear land. Crater wear occurs on the rake face and can weaken the cutting edge. Other mechanisms include abrasive wear, adhesion, diffusion, oxidation, chipping, and thermal cracking. A tool-life test must specify the failure criterion, such as a maximum flank-wear land, unacceptable surface finish, dimensional error, or catastrophic edge failure.

7. Machine-Tool Sizing and Design Implications

A machine-tool system should be sized through a load envelope rather than a single nominal operating point. The envelope includes:

  • maximum cutting force and thrust;
  • continuous and peak spindle power;
  • torque at low and high speed;
  • feed-drive force and acceleration;
  • structural stiffness and natural frequencies;
  • bearing capacity and thermal limits;
  • tool-holding and workholding strength;
  • coolant and chip-removal capability.

7.1 Spindle selection

At low speed, torque may govern; at high speed, power may govern. For a constant-power spindle, available torque decreases approximately as speed increases according to T = 9550P/N. A gearbox or belt range may be necessary when both high torque and high speed are required.

A practical sizing procedure is:

  1. Define the maximum material, tool, depth, feed, and speed combination.
  2. Estimate cutting and passive forces.
  3. Calculate cutting power and spindle torque.
  4. Apply efficiency and design margins.
  5. Check peak and continuous ratings separately.
  6. Verify structural deflection, bearing loads, and vibration stability.
  7. Confirm that the control system can limit overload and protect the tool.

A design margin is not a substitute for accurate process data. Excessive oversizing can increase cost, mass, energy consumption, and acceleration time.

7.2 Stiffness and accuracy

Static deflection can be expressed generally as:

δ = F/k

where k is equivalent stiffness in N/m. The total compliance includes the tool, holder, spindle bearings, machine structure, workholding, and workpiece. Deflection changes the effective depth of cut and may create dimensional error or regenerative chatter.

Dynamic behavior must also be considered. A flexible structure may amplify periodic tooth-passing forces even when its static strength is adequate. Consequently, machine design requires both strength and stiffness, together with modal and stability analysis.

8. Applied Case: Selecting a Turning Spindle

Background

The following is an illustrative engineering case. A production cell must rough-turn medium-carbon steel shafts. The intended operation uses a 3 mm depth of cut, 0.30 mm/rev feed, and 150 m/min cutting speed. The mean diameter is 100 mm, the specific cutting force is estimated as 2,100 N/mm², and total mechanical efficiency is 0.82.

Problem and analysis

The chip area is:

Ac = 0.30 × 3 = 0.90 mm²

Estimated cutting force is:

Fc = 2100 × 0.90 = 1890 N

Spindle speed is:

N = 1000×150/(π×100) ≈ 477.5 rev/min

Cutting power is:

Pc = 1890×150/60000 = 4.725 kW

Required motor input power, excluding any additional design margin, is:

Pmotor = 4.725/0.82 ≈ 5.76 kW

Required spindle torque is:

T = 9550×4.725/477.5 ≈ 94.5 N·m

Approach and solution

A nominal 7.5 kW spindle might satisfy the steady calculation, but the designer must verify that it can deliver at least 94.5 N·m at approximately 478 rev/min and tolerate transient engagement. If a 25% engineering margin is applied to the calculated cutting power, the target cutting-side rating becomes about 5.91 kW, and the corresponding motor-side rating is about 7.21 kW. A 7.5 kW motor may therefore be appropriate, subject to manufacturer torque curves and duty ratings.

The passive force should be estimated independently, because it affects shaft deflection and surface accuracy. Tool wear can increase cutting force, so the process should include tool-condition limits and overload monitoring.

Outcome and learning points

The example demonstrates that spindle power alone is insufficient. Torque at the operating speed, efficiency, peak loading, stiffness, and tool-life changes must all be checked. A reliable design uses measured force data where possible, validates the process during trials, and monitors power or current for abnormal conditions.

9. Limitations, Safety, and Contemporary Practice

Force models based on specific cutting force are convenient but empirical. Their accuracy decreases for very small feeds, sharp edge effects, severe tool wear, high-speed thermal softening, complex tool paths, and difficult-to-machine materials. Finite-element machining simulations can provide richer predictions, but they require validated constitutive laws, friction models, thermal properties, and substantial computational effort.

Modern CNC systems increasingly use spindle-current monitoring, dynamometers, acoustic emission, vibration sensors, and machine-learning methods for tool-wear detection. Artificial intelligence can identify patterns in large process datasets, but it does not remove the need for physical understanding, calibrated sensors, representative training data, and human verification. A model trained on one tool, material, and machine may fail when transferred to another.

Safety is integral to force and power analysis. Workholding must withstand maximum cutting and inertial loads; guards must contain broken tools or workpieces; overload protection must prevent drive and spindle damage; and chip control must prevent entanglement. Engineers should follow applicable machine-tool, electrical, guarding, and occupational-safety standards in their jurisdiction. Conservative assumptions are appropriate when material properties, tool condition, or engagement are uncertain.

Best-Practice Checklist

  • Use consistent units and identify whether speed is cutting speed or spindle speed.
  • Use the force component parallel to velocity for power calculations.
  • Check both continuous power and transient peak torque.
  • Obtain specific cutting-force and tool-life constants from relevant tests or databases.
  • Include tool wear, coolant conditions, and interrupted engagement in validation.
  • Evaluate stiffness and deflection, not merely motor size.
  • Calculate average energy separately from maximum instantaneous load.
  • Verify calculations with trial cuts, force measurement, and machine monitoring.
  • Treat empirical formulas as valid only within their stated calibration range.

Chapter Summary

Machining forces arise from plastic deformation, friction, and tool–workpiece interaction. In orthogonal cutting, force components can be resolved into cutting, thrust, shear, friction, and normal forces. The practical estimate Fc = kcfap relates cutting force to specific cutting force and chip area, while process speed and geometry determine material-removal rate.

Cutting power is the product of force and cutting velocity, and spindle torque follows from T = 9550P/N when power is in kilowatts and speed is in revolutions per minute. Motor input power must account for efficiency. Turning, milling, and drilling require different attention: turning emphasizes tangential and radial forces, milling produces intermittent tooth loads, and drilling requires both torque and thrust.

Duty-cycle calculations distinguish peak load from average thermal demand. Specific cutting energy provides a useful power estimate from removal rate. Machinability includes force, tool wear, surface finish, chip control, and attainable speed. Taylor’s equation provides a limited-range model for tool life and must be calibrated for the tool–workpiece system.

Machine-tool sizing requires a load envelope involving force, torque, power, stiffness, thermal capacity, bearings, workholding, and dynamic stability. Sound design combines analytical estimates, empirical data, safety margins, and experimental validation.

Key Terms

Machining mechanics: Study of forces, deformation, friction, heat, and motion in material removal.

Orthogonal cutting: Idealized cutting in which the cutting edge is perpendicular to cutting velocity.

Oblique cutting: Three-dimensional cutting with angled chip flow.

Specific cutting force: Cutting force required per unit uncut chip area.

Uncut chip area: Cross-sectional area of material removed before deformation.

Cutting force: Force component opposing the cutting velocity.

Thrust force: Force component generally normal to the cutting direction.

Passive force: Radial force that can cause tool or workpiece deflection.

Chip-thickness ratio: Ratio of undeformed chip thickness to deformed chip thickness.

Shear angle: Angle locating the idealized primary shear plane.

Material-removal rate: Volume of material removed per unit time.

Cutting power: Mechanical power used in the cutting action.

Spindle torque: Rotational moment required at the spindle.

Specific cutting energy: Energy required to remove a unit volume of material.

Duty cycle: Fraction of a cycle spent in a specified operating state.

Machinability: Overall ease of producing acceptable parts by machining.

Tool life: Useful cutting time before a defined wear or performance limit.

Taylor equation: Empirical relationship between cutting speed and tool life.

Machine stiffness: Resistance of the machine–tool–workpiece system to deflection.

Regenerative chatter: Self-excited vibration caused by interaction between current and previous waviness.

Review Questions

Short Answer Questions

  1. What is the difference between cutting force, feed force, and passive force?
  2. Define specific cutting energy and state its main use.
  3. Why must motor input power exceed cutting power?
  4. What does the Taylor tool-life exponent represent?
  5. Why can a machine with adequate static strength still suffer from chatter?

Long Answer Questions

  1. Explain chip formation in orthogonal cutting and derive the relationship between chip ratio, rake angle, and shear angle.
  2. Discuss the assumptions and limitations of Merchant force analysis.
  3. Compare force and power requirements in turning, milling, and drilling.
  4. Explain how torque, power, stiffness, thermal loading, and duty cycle influence spindle selection.
  5. Describe machinability, tool-wear mechanisms, and the proper use of Taylor’s tool-life equation.

Analytical / Application Questions

  1. A turning operation uses f = 0.20 mm/rev, ap = 2.5 mm, kc = 1,800 N/mm², and V = 100 m/min. Calculate cutting force and cutting power. State the assumptions made.
  2. A milling cycle has different cutting, rapid, and loading powers. Develop a calculation procedure for average power, energy per cycle, and cutting duty cycle, and explain why peak power must also be checked.
  3. A proposed spindle meets the calculated average power but not the required low-speed torque. Analyze the likely production consequences and recommend engineering changes.

Multiple Choice Questions with Answers

Question 1

In a turning operation, which force component primarily determines cutting power?

A. Radial or passive force

B. Tangential cutting force

C. Workholding clamping force

D. Bearing preload force

Correct Answer: B. Tangential cutting force

Question 2

A tool cuts at 120 m/min with a cutting force of 1,000 N. What is the cutting power?

A. 0.20 kW

B. 1.20 kW

C. 2.00 kW

D. 120 kW

Correct Answer: C. 2.00 kW

Question 3

For turning, the uncut chip area is most directly approximated by which expression?

A. πD²/4

B. fa_p

C. D/N

D. a_p/f

Correct Answer: B. fa_p

Question 4

If a spindle delivers 5 kW at 1,000 rev/min, its approximate torque is:

A. 4.78 N·m

B. 47.8 N·m

C. 478 N·m

D. 9,550 N·m

Correct Answer: B. 47.8 N·m

Question 5

Which equation represents the classical Taylor tool-life relationship?

A. F = ma

B. P = Tω

C. VT^n = C

D. Q = a_pa_ev_f

Correct Answer: C. VT^n = C

Question 6

A machine cuts for 30 seconds and is inactive for 30 seconds in each cycle. Its cutting duty cycle is:

A. 25%

B. 40%

C. 50%

D. 75%

Correct Answer: C. 50%

Question 7

Why is milling power generally intermittent?

A. The spindle always stops between teeth

B. Each cutter tooth enters and leaves the workpiece

C. Milling has no cutting force

D. The feed drive operates only at zero speed

Correct Answer: B. Each cutter tooth enters and leaves the workpiece

Question 8

If total transmission efficiency is 0.80 and cutting power is 4 kW, the required motor input power is:

A. 3.2 kW

B. 4.0 kW

C. 4.8 kW

D. 5.0 kW

Correct Answer: D. 5.0 kW

Question 9

Which factor most directly increases workpiece bending deflection in the simplified cantilever model?

A. Reducing overhang length

B. Increasing Young’s modulus

C. Increasing overhang length

D. Increasing shaft diameter

Correct Answer: C. Increasing overhang length

Question 10

Specific cutting energy is defined as:

A. Force multiplied by diameter

B. Power divided by material-removal rate

C. Torque divided by spindle speed

D. Feed divided by cutting speed

Correct Answer: B. Power divided by material-removal rate

Machine Tool Design
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