Fundamentals of Electrical Engineering

Chapter 5
Transient and Dynamic Circuit Behavior

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Transient and Dynamic Circuit Behavior

Introduction

Electrical circuits do not generally move instantaneously from one operating state to another. When a switch changes position, a source is applied or removed, or a fault occurs, capacitors and inductors exchange stored energy with the rest of the circuit. The resulting time-dependent behavior is called a transient. After the transient decays, the circuit may reach a new steady state.

Transient analysis is essential in power supplies, motor drives, communication circuits, protection systems, sensor interfaces, and digital electronics. Incorrect transient design can produce excessive voltage, current, electromagnetic interference, contact arcing, or component failure.

This chapter assumes lumped, linear, time-invariant circuits unless stated otherwise. Ideal switching is used for analysis, although practical limitations are considered later.

Learning Objectives

After studying this chapter, students should be able to:

  • determine capacitor-voltage and inductor-current initial conditions;
  • calculate final values using DC steady-state equivalents;
  • derive and apply first-order RC and RL transient equations;
  • distinguish natural, forced, transient, and complete responses;
  • analyze underdamped, critically damped, and overdamped RLC circuits;
  • calculate damping factors, resonant frequencies, overshoot, and settling behavior;
  • formulate second-order step responses quantitatively;
  • interpret energy storage and dissipation during switching; and
  • select practical transient-suppression techniques.

1. Dynamic Elements and Switching Conditions

1.1 Capacitors

For a capacitor using the passive sign convention, current enters the terminal marked positive for capacitor voltage vC. Its constitutive relation is

iC(t) = C\frac{dvC(t)}{dt}

where iC is in amperes, C is capacitance in farads, and vC is in volts.

A finite current cannot change capacitor voltage instantaneously. Integrating across a switching instant gives

vC(0^+) = vC(0^-)

This continuity rule assumes there is no ideal impulse current. An ideal voltage source connected directly across an inconsistently charged ideal capacitor violates the ordinary finite-current model and implies an impulse.

The energy stored in a capacitor is

wC = \frac{1}{2}CvC2

where wC is measured in joules.

1.2 Inductors

For an inductor under the passive sign convention,

vL(t) = L\frac{diL(t)}{dt}

where L is inductance in henries. A finite voltage cannot change inductor current instantaneously, so

iL(0^+) = iL(0^-)

unless an ideal voltage impulse is present.

The stored magnetic energy is

wL = \frac{1}{2}LiL2

A zero instantaneous inductor current does not imply zero inductor voltage. If current is changing at that instant, vL=L\,diL/dt can be nonzero.

1.3 Initial and Final Conditions

A reliable switching-analysis procedure is:

  1. Analyze the circuit for t<0 to obtain vC(0^-) and iL(0^-).
  2. Apply continuity to obtain vC(0^+) and iL(0^+).
  3. Analyze the post-switch circuit to obtain derivatives and the complete response.
  4. Find the final value from the post-switch steady state, if it exists.

For a DC circuit in steady state:

  • an ideal capacitor behaves as an open circuit because dvC/dt=0;
  • an ideal inductor behaves as a short circuit because diL/dt=0.

These substitutions apply only to steady DC conditions, not generally at the switching instant.

2. First-Order Circuits

A circuit containing one independent energy-storage state is first order. Its governing equation can usually be written as

\tau\frac{dx(t)}{dt} + x(t) = x(\infty)

Here x is the state variable and \tau is the time constant in seconds. For constant post-switch sources, the solution is

x(t) = x(\infty) + [x(0^+) - x(\infty)]e-t/\tau, \qquad t \ge 0

The exponential term is the transient or natural component. The final-value term is the steady forced component.

After one time constant, the difference from the final value is e-1\approx36.8\% of its initial value. After five time constants, it is approximately 0.674\%, so engineers often treat the response as practically settled.

2.1 RC Circuits

Consider a capacitor connected through a Thevenin-equivalent resistance Rth to a constant Thevenin voltage Vth. Kirchhoff’s voltage law and iC=C\,dvC/dt give

RthC\frac{dvC}{dt} + vC = Vth

Therefore,

\tauRC = RthC

and

vC(t) = Vth + [vC(0^+) - Vth]e^{-t/(RthC)}

Resistance must be the resistance seen by the capacitor in the post-switch circuit with independent voltage sources replaced by shorts and independent current sources replaced by opens. Dependent sources remain active; a test source may be required to find Rth.

Worked Example 1: RC Charging

A 5\ \mu F capacitor initially has zero voltage. At t=0, it is connected through 2\ k\Omega to a 12\ V source.

The time constant is

\tau = RC = (2\times103)(5\times10-6) = 0.010\ s = 10\ ms

The capacitor voltage is

vC(t) = 12(1-e-t/0.010)\ V

The current is

iC(t) = \frac{12}{2000}e-t/0.010 = 6e-t/0.010\ mA

At t=10\ ms, vC=12(1-e-1)\approx7.59\ V. The final stored energy is

wC(\infty)=\frac{1}{2}(5\times10-6)(12)2=0.360\ mJ

2.2 RL Circuits

For a series resistance Req, inductance L, and constant equivalent source Veq, KVL gives

L\frac{diL}{dt}+ReqiL=Veq

Thus,

\tauRL=\frac{L}{Req}

and

iL(t)=iL(\infty)+[iL(0^+)-iL(\infty)]e^{-tReq/L}

Worked Example 2: RL Energization

A 0.4\ H inductor with negligible winding resistance is connected in series with 20\ \Omega across a 40\ V DC source. Initially, its current is zero.

\tau=\frac{L}{R}=\frac{0.4}{20}=0.020\ s=20\ ms

The final current is 40/20=2\ A, so

iL(t)=2(1-e-t/0.020)\ A

The inductor voltage is

vL(t)=40e-t/0.020\ V

Initially, the entire source voltage appears across the inductor. At steady state, the ideal inductor voltage is zero.

3. Natural, Forced, and Complete Responses

The natural response is produced by energy initially stored in capacitors and inductors after independent sources are set to zero. Its form is determined by the circuit poles.

The zero-state response is caused by applied sources when initial stored energy is zero. In a linear circuit, it represents the forced effect of the input.

The complete response can be expressed as either

\text{complete response}=\text{natural response}+\text{particular response}

or

\text{complete response}=\text{zero-input response}+\text{zero-state response}

These decompositions are related but should not be confused. The particular solution depends on the form of the input, whereas the zero-state response includes both transient and steady components generated by that input.

4. Second-Order RLC Circuits

A circuit with two independent energy-storage states is generally second order. A capacitor and inductor do not always produce second-order behavior: topology or constraints may make their states dependent.

4.1 Source-Free Series RLC Circuit

Define loop current i so that it enters the positive terminal of the capacitor. Therefore,

i=C\frac{dvC}{dt}

For a source-free series RLC loop, KVL gives

L\frac{di}{dt}+Ri+vC=0

Substitution produces

LC\frac{d2vC}{dt2}+RC\frac{dvC}{dt}+vC=0

The characteristic equation is

s2+2\alpha s+\omega02=0

where

\alpha=\frac{R}{2L}, \qquad \omega0=\frac{1}{\sqrt{LC}}

Both \alpha and \omega0 have units of radians per second, conventionally treated dimensionally as s-1. The damping ratio is

\zeta=\frac{\alpha}{\omega0}=\frac{R}{2}\sqrt{\frac{C}{L}}

The roots are

s1,2=-\alpha\pm\sqrt{\alpha2-\omega02}
ConditionClassificationNatural-response form
\alpha<\omega0Underdampede-\alpha t(A\cos\omegadt+B\sin\omegadt)
\alpha=\omega0Critically damped(A+Bt)e-\alpha t
\alpha>\omega0OverdampedAes1t+Bes2t

For the underdamped case,

\omegad=\sqrt{\omega02-\alpha2}

is the damped natural frequency.

Worked Example 3: Consistent Signs and Nonzero Inductor Voltage

A source-free series circuit has R=20\ \Omega, L=0.1\ H, and C=100\ \mu F. Define current to enter the capacitor’s positive terminal. Initially, vC(0^+)=5\ V and i(0^+)=0.

The parameters are

\alpha=\frac{20}{2(0.1)}=100\ s-1
\omega0=\frac{1}{\sqrt{(0.1)(100\times10-6)}}=316.23\ rad/s
\omegad=\sqrt{316.232-1002}=300\ rad/s

Thus,

vC(t)=e-100t[A\cos(300t)+B\sin(300t)]

Since vC(0)=5, A=5. Because i=C\,dvC/dt and i(0)=0, dvC(0)/dt=0. Therefore,

-100A+300B=0 \quad\Rightarrow\quad B=\frac{5}{3}

The response is

vC(t)=e-100t\left[5\cos(300t)+1.667\sin(300t)\right]\ V

At the switching instant, KVL gives

L\frac{di(0^+)}{dt}+Ri(0^+)+vC(0^+)=0

Hence,

\frac{di(0^+)}{dt}=-\frac{5}{0.1}=-50\ A/s

and vL(0^+)=L\,di/dt=-5\ V under the selected passive voltage reference. This demonstrates that an inductor may have zero current and nonzero voltage at the same instant.

4.2 Parallel RLC Natural Response

For an ideal source-free parallel RLC circuit, applying KCL and differentiating gives the voltage equation

\frac{d2v}{dt2}+\frac{1}{RC}\frac{dv}{dt}+\frac{1}{LC}v=0

Therefore,

\alpha=\frac{1}{2RC}, \qquad \omega0=\frac{1}{\sqrt{LC}}

The series and parallel circuits have the same general response classifications but different expressions for damping. Consequently, increasing resistance increases damping in a series RLC circuit but decreases damping in an ideal parallel RLC circuit.

5. Quantitative Forced and Step Responses

5.1 Series RLC Driven by a Voltage Step

For a series RLC circuit driven by constant voltage Vs for t\ge0, with capacitor voltage as the output,

LC\frac{d2vC}{dt2}+RC\frac{dvC}{dt}+vC=Vs

The transfer function under zero initial conditions is

H(s)=\frac{VC(s)}{Vs(s)}=\frac{1}{LCs2+RCs+1}=\frac{\omega02}{s2+2\alpha s+\omega02}

For a stable circuit with R>0, the final capacitor voltage is Vs. The complete response is the constant particular solution plus the natural response.

For arbitrary initial conditions in the underdamped case,

vC(t)=Vs+e-\alpha t[A\cos(\omegadt)+B\sin(\omegadt)]

where

A=vC(0^+)-Vs

and, because i(0^+)=C\,dvC(0^+)/dt,

B=\frac{i(0^+)/C+\alpha A}{\omegad}

These equations explicitly account for both capacitor voltage and inductor current initial conditions.

For zero initial energy and a step of magnitude Vs, the underdamped capacitor response becomes

vC(t)=Vs\left[1-e-\alpha t\left(\cos\omegadt+\frac{\alpha}{\omegad}\sin\omegadt\right)\right]

The series current is

i(t)=\frac{Vs}{L\omegad}e-\alpha t\sin(\omegadt)

For a normalized underdamped second-order system, the fractional peak overshoot and time to first peak are

Mp=e^{-\pi\zeta/\sqrt{1-\zeta2}}=e-\pi\alpha/\omegad, \qquad tp=\frac{\pi}{\omegad}

These overshoot formulas apply to the zero-initial-condition step response of the standard second-order low-pass form, not to every RLC output or arbitrary initial condition.

For critical damping and zero initial energy,

vC(t)=Vs[1-(1+\omega0t)e-\omega0t]

For overdamping, the response has the form

vC(t)=Vs+A es1t+B es2t

The constants A and B must be found from initial voltage and initial derivative; they should not be inferred from the underdamped formula.

Worked Example 4: Underdamped Step Response

Use R=20\ \Omega, L=0.1\ H, and C=100\ \mu F, but now apply a 10\ V step with zero initial energy.

The previously calculated parameters are \alpha=100\ s-1, \omega0=316.23\ rad/s, and \omegad=300\ rad/s. Also,

\zeta=\frac{100}{316.23}=0.316

The capacitor voltage is

vC(t)=10\left[1-e-100t\left(\cos300t+\frac{1}{3}\sin300t\right)\right]\ V

The current is

i(t)=\frac{10}{(0.1)(300)}e-100t\sin300t
=0.333e-100t\sin300t\ A

The first peak occurs at

tp=\frac{\pi}{300}=10.47\ ms

The fractional overshoot is

Mp=e-\pi(100)/300=0.351

Thus the first peak voltage is

vC,peak=10(1+0.351)=13.51\ V

Although the source is only 10\ V, energy exchange between the inductor and capacitor causes the capacitor voltage to exceed the source temporarily.

Second-order step-response classifications t Output Final value Underdamped Critically damped Overdamped
Qualitative comparison of underdamped, critically damped, and overdamped step responses
Figure: Qualitative comparison of underdamped, critically damped, and overdamped step responses

Figure: Qualitative second-order step responses. Exact shapes depend on circuit parameters and selected output.

6. Laplace-Domain Interpretation

In the Laplace domain, poles determine natural modes. For a stable first-order circuit, the pole is at s=-1/\tau. For a second-order circuit, poles are the roots of the characteristic equation.

Initial energy appears in transformed element equations. For example,

VL(s)=sLIL(s)-LiL(0^-)

and

IC(s)=sCVC(s)-CvC(0^-)

Laplace methods are especially useful for piecewise inputs, impulses, repeated switching, and higher-order networks. However, physical continuity and sign conventions should be established before algebraic manipulation.

7. Energy Exchange and Dissipation

In a lossless ideal LC circuit, total stored energy is constant:

w(t)=\frac{1}{2}CvC2(t)+\frac{1}{2}LiL2(t)

Energy oscillates between the capacitor’s electric field and the inductor’s magnetic field. Resistance dissipates energy as heat at the rate

pR=i2R=\frac{vR2}{R}

Thus a passive RLC circuit with positive resistance eventually loses its initially stored energy. Negative resistance or active feedback can instead sustain or increase oscillations, so stability cannot be assumed merely because a circuit contains R, L, and C.

8. Applied Case: Protecting a DC Contactor Coil

Background

This is an illustrative engineering case. A 20\ V DC contactor coil is modeled by L=0.4\ H and R=20\ \Omega. At steady state, the coil current is I0=1\ A, and its magnetic energy is

wL=\frac{1}{2}(0.4)(1)2=0.20\ J

Problem

When a transistor opens the coil circuit, current cannot stop instantaneously. Without a controlled path, the inductor generates whatever voltage is necessary—limited in practice by parasitic capacitance, arcing, avalanche breakdown, and insulation failure—to maintain current.

Analysis and Solution

A flyback diode placed across the coil provides a current path. Approximating its forward drop by VD=0.7\ V, the decay equation is

L\frac{di}{dt}+Ri+VD=0

while i>0. Its solution is

i(t)=\left(I0+\frac{VD}{R}\right)e-Rt/L-\frac{VD}{R}

The time until the current reaches zero is

t0=\frac{L}{R}\ln\left(1+\frac{RI0}{VD}\right)

For this coil,

t0=0.020\ln\left(1+\frac{20}{0.7}\right)=67.7\ ms

The diode strongly limits switch voltage but produces a relatively slow magnetic-field collapse. If rapid contact release is required, a properly rated transient-voltage suppressor or Zener clamp can allow a higher controlled voltage and faster decay. For an ideal 60\ V clamp opposing the current,

t0=\frac{0.4}{20}\ln\left(1+\frac{20(1)}{60}\right)=5.75\ ms

Outcome

The protection choice involves a trade-off among switch-voltage rating, release time, electromagnetic interference, thermal loading, and component lifetime. The suppressor must safely absorb or redirect approximately 0.20\ J per operation, with allowance for repetition rate and tolerances.

Learning Points

  • Stored magnetic energy must have a controlled discharge path.
  • A lower clamp voltage usually gives slower current decay.
  • Suppressor energy and peak-power ratings are both important.
  • Coil resistance, temperature, parasitic capacitance, and switch avalanche behavior affect practical results.

9. Transient Protection and Engineering Practice

Common protection methods include:

TechniqueTypical useMain limitation
Flyback diodeDC relay or solenoid coilSlow current decay
Zener or TVS clampControlled inductive overvoltageMust be energy-rated
RC snubberSwitches, transformers, contactsLoss and component optimization
MOVMains and high-energy surgesAging after repeated surges
Gate-resistance controlPower semiconductor switchingIncreases switching loss
Active clampHigh-performance convertersGreater cost and complexity

Good practice includes minimizing high-current loop area, selecting components using worst-case tolerances, checking repetitive energy, measuring with properly rated probes, and verifying both turn-on and turn-off behavior.

Fast wide-bandgap devices based on silicon carbide and gallium nitride can produce very high dv/dt and di/dt. Their efficiency benefits make parasitic inductance, layout, common-mode current, and measurement technique increasingly important. Simulation and automated parameter fitting can support design, but models must be validated against measurements.

10. Limitations, Safety, and Governance

Ideal transient equations may become inaccurate because real capacitors have equivalent series resistance and leakage, inductors saturate, switches have finite transition times, and interconnections contain parasitic inductance and capacitance. Component values also vary with temperature, frequency, voltage, manufacturing tolerance, and aging.

Transient testing can expose personnel and equipment to dangerous voltage and stored energy. Capacitors should be discharged through rated resistors, lockout procedures should be followed, and probes must have suitable voltage, bandwidth, and category ratings. Protection design should comply with applicable product-safety, electromagnetic-compatibility, insulation, and surge-immunity requirements. Engineers have an ethical duty not to bypass protective devices merely to improve short-term performance or reduce cost.

Chapter Summary

Capacitor voltage and inductor current are continuous across ordinary switching events because instantaneous changes would require ideal impulses. First-order RC and RL responses approach their final values exponentially with time constants RC and L/R, respectively. A complete response combines effects of stored energy and applied sources.

Second-order RLC behavior is governed by the damping factor, undamped natural frequency, and damping ratio. Underdamped circuits oscillate with decaying amplitude, critically damped circuits provide the fastest nonoscillatory response, and overdamped circuits contain two decaying real modes. Step responses may overshoot because energy is exchanged between inductance and capacitance. Correct analysis requires explicit current directions, voltage polarities, initial conditions, and post-switch topology.

Practical transient design must also address stored energy, parasitic components, insulation, semiconductor limits, electromagnetic interference, repetitive stress, and safety. Suppression devices control transient voltage but introduce trade-offs in release time, power dissipation, and system performance.

Key Terms

Capacitor-voltage continuity: The requirement that capacitor voltage cannot change instantaneously without an impulse current.

Inductor-current continuity: The requirement that inductor current cannot change instantaneously without an impulse voltage.

Transient response: The time-varying component that follows a switching event or disturbance.

Steady-state response: Circuit behavior after decaying transient modes have become negligible.

Natural response: Response produced by initially stored energy with independent sources removed.

Forced response: Response associated with an applied input or source.

Complete response: Total response satisfying both the differential equation and initial conditions.

Time constant: Parameter determining the exponential rate of a first-order response.

Characteristic equation: Polynomial whose roots determine a circuit’s natural modes.

Pole: A complex frequency at which a system transfer function becomes unbounded.

Damping factor: Exponential decay parameter \alpha in a second-order response.

Damping ratio: Dimensionless ratio \zeta=\alpha/\omega0.

Underdamped response: Decaying oscillatory response with \zeta<1.

Critical damping: Boundary case \zeta=1 producing the fastest standard nonoscillatory response.

Overdamped response: Nonoscillatory response with two distinct real decaying modes.

Natural frequency: Frequency \omega0 of the corresponding undamped second-order system.

Damped natural frequency: Oscillation frequency \omegad of an underdamped response.

Overshoot: Amount by which a transient response exceeds its final value.

Flyback diode: Diode providing a safe current path when a DC inductive load is switched off.

Snubber: Network used to limit switching voltage, current, or rate of change.

Review Questions

Short Answer Questions

  1. Why is capacitor voltage normally continuous at a switching instant?
  2. What DC steady-state equivalents are used for ideal capacitors and inductors?
  3. Distinguish natural response from forced response.
  4. What physical behavior characterizes an underdamped RLC circuit?
  5. Why can an inductor have zero current but nonzero voltage?

Long Answer Questions

  1. Derive the complete response of a first-order RC circuit connected to a constant Thevenin source.
  2. Explain how initial and final conditions are determined in a switched circuit containing capacitors and inductors.
  3. Derive the characteristic equation of a source-free series RLC circuit and classify its possible roots.
  4. Derive the zero-initial-condition capacitor-voltage response of an underdamped series RLC circuit driven by a voltage step.
  5. Discuss the engineering trade-offs among flyback diodes, TVS clamps, MOVs, and RC snubbers.

Analytical / Application Questions

  1. A 10\ \mu F capacitor initially charged to 15\ V discharges through 5\ k\Omega. Determine its voltage and resistor current after 40\ ms.
  2. A series RLC circuit has R=30\ \Omega, L=0.2\ H, and C=50\ \mu F. Determine its damping classification, poles, and damped frequency if applicable.
  3. Design a suppression strategy for a DC solenoid with known inductance, resistance, operating current, required release time, and switch-voltage limit. Explain how energy and component tolerances affect the design.

Multiple Choice Questions with Answers

Question 1

Which state variable must remain continuous across an ordinary switching event when no impulse current is present?

A. Resistor voltage

B. Capacitor voltage

C. Resistor current

D. Source power

Correct Answer: B. Capacitor voltage

Question 2

A 5\ \mu F capacitor sees a post-switch resistance of 2\ k\Omega. What is its time constant?

A. 2.5 ms

B. 10 ms

C. 40 ms

D. 100 ms

Correct Answer: B. 10 ms

Question 3

Approximately what percentage of the initial difference from the final value remains after three time constants in a first-order circuit?

A. 1.8%

B. 5.0%

C. 36.8%

D. 95.0%

Correct Answer: B. 5.0%

Question 4

In DC steady state, an ideal capacitor is represented by which equivalent?

A. A short circuit

B. A voltage source

C. An open circuit

D. A current source

Correct Answer: C. An open circuit

Question 5

An inductor of 0.4\ H sees a series resistance of 20\ \Omega. What is the RL time constant?

A. 20 ms

B. 50 ms

C. 80 ms

D. 8 s

Correct Answer: A. 20 ms

Question 6

A series RLC circuit is underdamped when which condition holds?

A. \alpha<\omega0

B. \alpha=\omega0

C. \alpha>\omega0

D. \alpha=0 only

Correct Answer: A. \alpha<\omega0

Question 7

For the zero-initial-condition RLC step example with R=20\ \Omega, L=0.1\ H, C=100\ \mu F, and Vs=10\ V, what is the approximate first capacitor-voltage peak?

A. 10.00 V

B. 11.05 V

C. 13.51 V

D. 20.00 V

Correct Answer: C. 13.51 V

Question 8

An inductor current is zero at a particular instant. Which statement is correct?

A. Its voltage must also be zero.

B. Its stored energy must be negative.

C. Its voltage can be nonzero if its current is changing.

D. Its inductance must be zero.

Correct Answer: C. Its voltage can be nonzero if its current is changing.

Question 9

Compared with a low-voltage flyback diode, a higher-voltage TVS clamp across a DC coil generally produces which effect?

A. Slower current decay and lower switch voltage

B. Faster current decay and higher controlled switch voltage

C. No change in decay time

D. Infinite coil current

Correct Answer: B. Faster current decay and higher controlled switch voltage

Question 10

In a series RLC circuit, current enters the capacitor’s positive terminal. If i(0^+)=0, what is dvC(0^+)/dt?

A. Zero

B. vC(0^+)/L

C. -vC(0^+)/R

D. Infinite

Correct Answer: A. Zero

Fundamentals of Electrical Engineering
Chapter 5 of 15