Chapter 4
Network Theorems and Engineering Decisions
Bachelors Program in Electrical Engineering
Fundamentals of Electrical Engineering
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Bachelor
Network Theorems and Engineering Decisions
Introduction
Electrical networks encountered in power supplies, instrumentation, communication systems and embedded hardware may contain many sources and components. Direct application of Kirchhoff’s laws is always possible for a lumped network, but it is not always the most efficient engineering approach. Network theorems reduce a complex linear circuit to simpler forms while preserving the terminal behavior relevant to a design decision.
This chapter develops linearity, superposition, source transformation, Thévenin and Norton equivalents, and maximum-power-transfer principles. Particular attention is given to theorem conditions, dependent sources, stored energy, simulation, and the distinction between a mathematically correct result and an appropriate engineering decision.
Learning Objectives
After studying this chapter, a student should be able to:
determine whether a circuit satisfies the conditions for linear analysis;
apply superposition to voltages and currents;
transform practical voltage and current sources without changing terminal behavior;
construct Thévenin and Norton equivalents, including networks with dependent sources;
correctly use test sources and incremental resistance;
determine loads for maximum power transfer in DC and AC networks;
compare hand analysis with circuit simulation; and
select an efficient and defensible solution method for a practical network.
1. Linearity and Network Response
A network is linear when its output satisfies additivity and homogeneity. If excitation x1 produces response y1 and excitation x2 produces response y2, then
y(a x1 + b x2)=a y(x1)+b y(x2)
where a and b are constants. The excitation may be a voltage or current source, while the response may be any branch voltage or current.
Ideal resistors with constant resistance are linear because v=Ri. Ideal inductors and capacitors are described by
vL=L\frac{diL}{dt}, \qquad iC=C\frac{dvC}{dt}
where L is inductance in henries, C is capacitance in farads, vL is in volts, and iC is in amperes. These elements support linear analysis when their parameters are constant.
For circuits containing inductors or capacitors, linear response with respect to the applied independent sources normally assumes zero initial conditions. If an inductor has initial current or a capacitor has initial voltage, the stored energy must be represented as an additional excitation. Holding a nonzero initial condition fixed while varying only the external sources generally produces an affine response—an offset plus a linear response—not a homogeneous one.
Linear dependent sources remain active during linear analysis, provided their controlling relationship is linear. Diodes, transistors over large signal ranges, saturating inductors and temperature-dependent resistors are generally nonlinear. They may nevertheless be replaced by linearized small-signal models around a specified operating point.
2. Superposition Theorem
2.1 Statement and conditions
In a linear network containing multiple independent sources, any branch voltage or current equals the algebraic sum of the responses caused by each independent source acting separately.
When one independent source is considered:
replace every other ideal voltage source by a short circuit;
replace every other ideal current source by an open circuit;
retain all dependent sources;
retain passive impedances.
A nonideal source must not be removed together with its internal resistance. For example, deactivating a practical voltage source sets its ideal source voltage to zero but leaves its series resistance in the circuit.
Superposition applies directly to voltages and currents, not to power, because power is nonlinear in these quantities:
P=VI=I2R=\frac{V2}{R}
Power must therefore be calculated from the total voltage or current after all component responses have been summed.
2.2 Worked example: node voltage by superposition
A node is connected to a 12 V source through 4 kΩ, to a 6 V source through 6 kΩ, and to ground through 3 kΩ. Both source voltages are referenced to ground. Determine the node voltage V.
With only the 12 V source active, the 6 V source is short-circuited:
V12=\frac{12/4}{1/4+1/6+1/3}=4.00\ \text{V}
The resistance values may be entered in kilohms because the common scale cancels.
Superposition is especially useful when an engineer needs to identify the contribution of noise, bias, interference or several supplies. It becomes inefficient when a circuit contains many independent sources because one subproblem is required for each source. In such cases, nodal analysis or simulation may be faster.
3. Source Transformation
A practical voltage source consisting of an ideal voltage source Vs in series with resistance Rs is terminally equivalent to an ideal current source Is in parallel with the same resistance, where
Is=\frac{Vs}{Rs}
Conversely,
Vs=IsRs
Here Vs is in volts, Is is in amperes, and Rs is in ohms. The current-source arrow must be oriented so that the open-circuit voltage has the same polarity as the original voltage source.
Equivalent practical voltage and current sources
Figure: Equivalent practical voltage and current sources
Figure: Terminal equivalence of a practical voltage source and a practical current source.
For example, a 10 V source in series with 5 Ω is equivalent to a 2 A source in parallel with 5 Ω. Source transformation preserves external terminal voltage and current for every connected load. It does not necessarily preserve internal branch currents or the power assigned to individual ideal elements.
The transformation extends to sinusoidal steady-state circuits by replacing resistance with impedance:
\underline{I}s=\frac{\underline{V}s}{Zs}
where phasors are normally RMS quantities and Zs is measured in ohms.
4. Thévenin and Norton Theorems
4.1 Thévenin equivalent
Any linear two-terminal network can be represented at its port by an ideal voltage source Vth in series with an equivalent resistance or impedance Rth or Zth. For a resistive network,
v=Vth-Rthi
where i is defined as current delivered by the equivalent network to the load. The open-circuit terminal voltage is
Vth=Voc
4.2 Norton equivalent
The same network can be represented by a current source IN in parallel with RN. For ordinary finite equivalents,
RN=Rth, \qquad IN=\frac{Vth}{Rth}
If Isc is defined as the short-circuit current delivered by the network, then
IN=Isc, \qquad Rth=\frac{Voc}{Isc}
The last expression requires a linear one-port, consistent reference directions, and finite nonzero quantities. Degenerate ideal-source cases must be handled separately.
4.3 Derivation from the terminal relation
The voltage–current characteristic of a linear resistive one-port containing independent sources is affine. Using delivered current,
v=Voc-Rthi
At open circuit, i=0, so v=Voc. At short circuit, v=0, giving Isc=Voc/Rth. Thus the Thévenin and Norton models describe the same straight-line terminal characteristic.
4.4 Methods for finding equivalent resistance
#### Method 1: deactivate independent sources
Set independent voltage sources to zero by replacing them with short circuits and set independent current sources to zero by replacing them with open circuits. Keep dependent sources active. Determine the resistance viewed from the port.
This method is convenient when the remaining resistor network can be simplified directly.
#### Method 2: apply a test source
After deactivating independent sources, apply a test voltage Vt and calculate the entering current It, or apply a test current and calculate the voltage. Then
Rth=\frac{Vt}{It}
This form applies because the deactivated network passes through the origin of its port characteristic. Dependent sources must remain active.
#### Method 3: incremental test with independent sources active
If independent sources remain active, the port relation generally contains an offset. Therefore, Vt/It is not generally equal to Rth. Instead, use two operating points:
Rth=\frac{\Delta Vt}{\Delta It}
with current defined as entering the network. In differential form,
Rth=\frac{dVt}{dIt}
This is the slope of the port characteristic. For a linear network the slope is constant; for a nonlinear network it is a local small-signal resistance at the operating point.
As an illustration, suppose a port contains a 10 Ω resistor and a voltage-controlled current source of transconductance 0.2 S, both drawing current from the port node to ground, plus a 1 A independent source directed from ground to the port. With port current entering the network,
The ratio Vt/It varies with the test level because of the 1 A offset and is therefore not the equivalent resistance. If the independent source is first deactivated, the relation becomes It=0.3Vt, and the ordinary ratio gives 3.333 Ω.
4.5 Worked example: Thévenin and Norton models
A 24 V ideal source supplies a 6 Ω resistor in series with a node. A 12 Ω resistor connects that node to ground. Find the equivalent seen between the node and ground.
The open-circuit voltage is the divider voltage:
Vth=24\left(\frac{12}{6+12}\right)=16\ \text{V}
After deactivating the 24 V source, the 6 Ω and 12 Ω resistors appear in parallel:
The Norton model gives identical terminal results.
5. Maximum Power Transfer
5.1 Resistive DC networks
For a Thévenin source supplying a resistive load RL,
PL=\left(\frac{Vth}{Rth+RL}\right)2RL
where Vth is in volts, resistances are in ohms, and power is in watts. This formula assumes Rth>0 and a purely resistive load.
Differentiating with respect to RL gives
\frac{dPL}{dRL}=Vth2\frac{Rth-RL}{(Rth+RL)3}
The stationary point is a maximum when
RL=Rth
and the maximum load power is
PL,max=\frac{Vth2}{4Rth}
At this operating point, equal power is dissipated in Rth and RL, so the source-to-load efficiency of this simple model is only 50%. Maximum power transfer is therefore important in communication interfaces, sensing and impedance matching, but it is usually undesirable in bulk power distribution, where high efficiency and voltage regulation dominate.
5.2 AC networks
Let the Thévenin impedance be
Zth=Rth+jXth
and the load impedance be ZL=RL+jXL. For RMS phasors, average load power is
PL=\frac{|\underline{V}th|2RL}{|Zth+ZL|2}
Maximum average power occurs under conjugate matching:
ZL=Zth*=Rth-jXth
This requires an adjustable complex load and Rth>0. If the load must be purely resistive, the optimum is instead
RL=|Zth|=\sqrt{Rth2+Xth2}
These two conditions must not be confused.
6. Choosing an Efficient Solution Method
Network feature
Usually efficient method
Reason
One dominant essential node
Nodal analysis
Few unknown voltages
Several series loops
Mesh analysis
Few loop-current equations
Need each source’s contribution
Superposition
Separates source effects
Repeated changes of one load
Thévenin or Norton
Network solved once
Mixed series voltage and parallel current sources
Source transformation
Reveals simpler topology
Dependent sources at a port
Test-source method
Preserves controlled-source action
Large or tolerance-sensitive circuit
Simulation plus analytical checks
Rapid sweeps and verification
Maximum load power required
Thévenin impedance and matching
Direct design criterion
An efficient engineer defines the required output before selecting a method. Finding every branch variable is unnecessary when only load voltage is required. Conversely, a terminal equivalent cannot answer questions about internal component stress unless the original network is revisited.
7. Analytical Methods and Circuit Simulation
Circuit simulators based on SPICE can perform operating-point, transient, AC, noise, sensitivity and Monte Carlo analyses. They are particularly valuable for networks containing many components, frequency dependence, tolerances or realistic nonlinear device models.
Analytical methods remain essential because they:
reveal parameter dependence and limiting behavior;
expose sign, topology and unit errors;
provide independent checks on simulation;
clarify assumptions hidden inside device models; and
support design decisions without relying on a single software implementation.
A robust workflow is:
define the port, reference directions and required quantities;
identify whether the network is linear and whether initial energy is present;
estimate expected magnitudes and limiting cases;
select a theorem or systematic equation method;
calculate analytically where practical;
construct the simulation with explicit ground and source definitions;
compare results, power balance and limiting cases; and
investigate discrepancies rather than selecting the preferred answer.
Simulation results are not automatically correct. Frequent errors include omitted grounds, wrong source polarity, incorrect AC magnitude, peak-versus-RMS confusion, unrealistic ideal models and unintended initial conditions. AI-assisted schematic generation may accelerate model creation, but generated netlists and component assumptions require expert verification.
An illustrative engineering team is designing an emergency beacon supplied by a battery and cable assembly. Measurements at the beacon connector produce a 12 V open-circuit voltage and an 8 A short-circuit current.
Problem
The beacon requires at least 9 V and 15 W during activation. The team initially proposes matching the load for maximum power transfer.
Maximum power transfer requires RL=1.5\ \text{Ω}. The resulting load voltage and power are
VL=12\frac{1.5}{1.5+1.5}=6\ \text{V}
PL=\frac{122}{4(1.5)}=24\ \text{W}
Although power is maximized, the 6 V terminal voltage violates the 9 V requirement.
At nominal conditions, a 4.5 Ω load gives
VL=12\frac{4.5}{1.5+4.5}=9\ \text{V}
PL=\frac{92}{4.5}=18\ \text{W}
This appears acceptable, but battery and cable tolerances must be considered. Suppose Vth may fall to 11.4 V and Rth may rise to 1.8 Ω. The worst-case voltage becomes
VL=11.4\frac{4.5}{1.8+4.5}=8.14\ \text{V}
The requirement is no longer met.
For a passive resistor to maintain at least 9 V under this worst case,
RL\geq\frac{9(1.8)}{11.4-9}=6.75\ \text{Ω}
Yet delivering 15 W at 9 V would require an effective resistance no greater than
RL=\frac{92}{15}=5.4\ \text{Ω}
The two conditions are incompatible for a fixed resistive load.
Approach and outcome
The team selects a regulated DC–DC converter rather than a fixed resistor interface. At the worst-case source condition, the maximum available source power is
Pmax=\frac{11.42}{4(1.8)}=18.05\ \text{W}
A converter delivering 15 W would therefore require efficiency above approximately 15/18.05=83.1\%, together with suitable input-voltage and current ratings. The final design must also include startup-current analysis, thermal margins, cable protection and battery-discharge testing.
Learning points
Maximum power is not synonymous with correct design. Voltage regulation, efficiency, tolerances, thermal limits, reliability and safety can dominate the decision. A Thévenin equivalent efficiently establishes feasibility, while simulation and testing validate converter dynamics and component stresses.
9. Limitations, Safety and Professional Practice
Network theorems are only as valid as their models. Important limitations include:
nonlinear or time-varying components;
temperature-dependent parameters;
magnetic saturation and semiconductor limits;
distributed effects at high frequency;
unknown initial energy in reactive components;
negative incremental resistance and potentially unstable active networks; and
measurement loading that alters the circuit being characterized.
Maximum-power-transfer calculations do not override current, voltage, thermal or insulation ratings. Short-circuit testing may be unsafe on batteries, power converters and mains-connected equipment; Isc should often be inferred from controlled tests rather than measured directly.
Professional practice requires traceable assumptions, appropriate uncertainty margins, validated simulation models, safe laboratory procedures and compliance with relevant electrical, electromagnetic-compatibility and product-safety standards. Engineers should report whether values are nominal, worst-case, measured or simulated.
Chapter Summary
Linearity permits complex responses to be decomposed and recombined. For reactive circuits, zero initial conditions are required for homogeneous response with respect to external sources; otherwise stored energy must be included as an excitation. Superposition applies to voltages and currents but not directly to power.
Source transformations preserve terminal behavior and lead naturally to Thévenin and Norton equivalents. Thévenin voltage is the open-circuit voltage, while Norton current is the delivered short-circuit current. Independent sources are deactivated when resistance is determined by direct inspection or a simple test-source ratio, while dependent sources remain active. If independent sources remain active, resistance must be obtained from \Delta V/\Delta I or the differential slope—not generally from V/I.
Maximum power occurs at resistance matching in resistive circuits and conjugate impedance matching in AC circuits. This condition may conflict with efficiency, voltage regulation and safety. Analytical methods provide insight and verification; simulation handles complexity and variation. Sound engineering combines both approaches with testing, tolerance analysis and documented assumptions.
Key Terms
Affine response: A response consisting of a constant offset plus a linear function of the excitation.
Conjugate matching: Selection of a load impedance equal to the complex conjugate of the source impedance.
Dependent source: A source controlled by another voltage or current in the circuit.
Equivalent resistance: The resistance representing a network’s terminal voltage–current slope.
Independent source: A voltage or current source whose specified value does not depend on another circuit variable.
Incremental resistance: The ratio \Delta V/\Delta I or derivative dV/dI at a port.
Linearity: Satisfaction of additivity and homogeneity.
Maximum power transfer: Operation at the load condition that maximizes delivered power.
Norton equivalent: A current source in parallel with an equivalent resistance or impedance.
Open-circuit voltage: Terminal voltage measured when port current is zero.
Port: A pair of terminals through which a network interacts with another system.
Short-circuit current: Current delivered when terminal voltage is zero.
Small-signal model: A linearized model valid for perturbations around an operating point.
Source transformation: Conversion between terminally equivalent practical voltage and current sources.
Superposition: Addition of individual source responses in a linear network.
Test source: An imposed port voltage or current used to determine terminal characteristics.
Thévenin equivalent: A voltage source in series with an equivalent resistance or impedance.
Zero initial conditions: Absence of initial capacitor voltage and inductor current before an excitation is applied.
Review Questions
Short Answer Questions
State the superposition theorem and explain how ideal independent sources are deactivated.
Why must dependent sources remain active when equivalent resistance is calculated?
What is the relationship between Thévenin and Norton equivalents?
Why cannot powers caused by individual sources generally be superposed?
Distinguish resistance matching from conjugate impedance matching.
Long Answer Questions
Derive the maximum-power-transfer condition for a resistive Thévenin source.
Explain three methods for determining Thévenin resistance and state the conditions for each.
Discuss how nonzero capacitor voltage or inductor current affects the use of linearity and superposition.
Compare analytical circuit methods with SPICE simulation, including their strengths and failure modes.
Explain why maximum power transfer may be inappropriate for an electrical power distribution system.
Analytical / Application Questions
A 30 V source with a 5 Ω series resistor supplies a variable load. Determine the Thévenin and Norton models, the load for maximum power, the maximum load power and the efficiency at that point.
A linear one-port obeys It=0.4Vt-2 with current entering the port. Determine its incremental resistance and explain why a single ratio Vt/It is generally unsuitable.
A source has Vth=20\ \text{V} and Zth=4+j3\ \text{Ω}. Determine the load for maximum average power and compare it with the optimum when the load is restricted to a pure resistance.
Multiple Choice Questions with Answers
Question 1
When applying superposition, how is an ideal independent voltage source deactivated?
A. It is replaced by an open circuit.
B. It is replaced by a short circuit.
C. Its voltage is doubled.
D. It is replaced by its load resistance.
Correct Answer: B. It is replaced by a short circuit.
Question 2
A circuit contains a capacitor with a fixed nonzero initial voltage. Which statement is correct?
A. The response to external sources is necessarily homogeneous.
B. The capacitor must always be replaced by a short circuit.
C. The initial stored energy should be treated as an additional excitation; otherwise the response may be affine.
D. Superposition becomes valid only for power.
Correct Answer: C. The initial stored energy should be treated as an additional excitation; otherwise the response may be affine.
Question 3
A 10 V source in series with 5 Ω is transformed into which Norton source?
A. 0.5 A in parallel with 5 Ω
B. 2 A in parallel with 5 Ω
C. 2 A in series with 5 Ω
D. 50 A in parallel with 2 Ω
Correct Answer: B. 2 A in parallel with 5 Ω
Question 4
A network has Voc=18\ \text{V} and delivers Isc=3\ \text{A}. What is its Thévenin resistance?
A. 6 Ω
B. 15 Ω
C. 21 Ω
D. 54 Ω
Correct Answer: A. 6 Ω
Question 5
When a test source is applied while independent sources remain active, equivalent resistance is generally found from which quantity?
A. VtIt
B. Vt/It at any single operating point
C. \Delta Vt/\Delta It
D. It/\Delta Vt
Correct Answer: C. \Delta Vt/\Delta It
Question 6
A 16 V Thévenin source with Rth=4\ \text{Ω} supplies an 8 Ω load. What is the load current?
A. 0.50 A
B. 1.00 A
C. 1.33 A
D. 4.00 A
Correct Answer: C. 1.33 A
Question 7
For a positive resistive Thévenin source, maximum load power occurs when:
A. RL=0
B. RL=Rth
C. RL=2Rth
D. RL\to\infty
Correct Answer: B. RL=Rth
Question 8
A source has Zth=5+j2\ \text{Ω}. Which adjustable complex load receives maximum average power?
A. 5+j2\ \text{Ω}
B. 2-j5\ \text{Ω}
C. 5-j2\ \text{Ω}
D. 7\ \text{Ω}
Correct Answer: C. 5-j2\ \text{Ω}
Question 9
At maximum power transfer in a simple resistive Thévenin circuit, what is the source-to-load efficiency?
A. 25%
B. 50%
C. 75%
D. 100%
Correct Answer: B. 50%
Question 10
Which task is most directly simplified by constructing a Thévenin equivalent?
A. Calculating responses for many different loads connected to the same port
B. Determining every internal branch current after each component is replaced
C. Superposing power values from independent sources
D. Modeling a strongly nonlinear diode over its entire operating range
Correct Answer: A. Calculating responses for many different loads connected to the same port
Fundamentals of Electrical Engineering
Chapter 4
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