Electrical Drives & Control

Chapter 6
Induction Motor Drives and Scalar Control

Bachelors Program in Electrical Engineering
Electrical Drives & Control   •   Bachelor

Induction Motor Drives and Scalar Control

Introduction and context

Induction motors are the dominant electromechanical converters in industrial drives because they are rugged, relatively inexpensive, efficient, and require little maintenance. Their speed is not independently imposed by the supply frequency: it is established by the interaction between the rotating magnetic field and the rotor. This interaction makes the machine simple mechanically but nonlinear from a control perspective.

A drive system combines the motor, power converter, control system, sensors, protection, and mechanical load. For induction motors, the most widely used introductory control method is scalar control, particularly constant volts-per-hertz control. Scalar control regulates the magnitudes of voltage, frequency, and slip-related quantities rather than directly controlling the instantaneous space vectors of flux and current. It is less dynamic than vector control, but it is robust, economical, and suitable for pumps, fans, compressors, conveyors, and many general-purpose machines.

This chapter develops the steady-state and dynamic models needed to understand induction-motor drives, explains slip and torque production, and applies voltage-frequency control, slip compensation, soft starting, and variable-frequency-drive configuration.

Learning objectives

After studying this chapter, the reader should be able to:

  1. Explain the rotating-field principle and define synchronous speed, rotor speed, and slip.
  2. Develop the per-phase equivalent circuit and interpret its parameters.
  3. Relate slip, rotor frequency, torque, power flow, and efficiency.
  4. Identify the assumptions and limitations of steady-state and dynamic models.
  5. Explain constant V/f control, low-speed voltage boost, field weakening, and slip compensation.
  6. Select and configure a basic variable-frequency drive (VFD) for an induction motor.
  7. Evaluate starting, braking, protection, thermal, harmonic, and application issues.

1. Rotating magnetic field and induction-motor operation

For a balanced three-phase stator supply of frequency f1 and a machine with P poles, the synchronous mechanical speed is

ns = 120 f1 / P

where ns is in revolutions per minute, f1 is in hertz, and P is the number of poles. In angular form,

ωs = 2π f1 / p

where p = P/2 is the number of pole pairs and ωs is in radians per second.

The stator’s rotating magnetic field induces rotor currents. The rotor field interacts with the stator field and produces electromagnetic torque. If the rotor reached synchronous speed exactly, there would be no relative motion between the rotating field and rotor conductors, no induced rotor voltage, and therefore no torque. Consequently, motoring operation requires rotor speed nm to be below synchronous speed.

Slip is defined by

s = (ns - nm) / ns = (ωs - ωm) / ωs

where ωm is rotor mechanical angular speed. For normal motoring, 0 < s < 1. The rotor electrical frequency is

f2 = s f1

and the rotor copper-loss fraction of the air-gap power is equal to slip. Negative slip corresponds to generating operation, while slip greater than unity can occur in certain transient or plugging conditions, although those are not normal steady-state motoring modes.

Torque production and power flow

The air-gap power Pag is transferred electromagnetically from stator to rotor. In the conventional equivalent circuit,

Pr,cu = s Pag

is rotor copper loss, and the mechanical power developed internally is

Pmech,dev = (1 - s) Pag

These relations neglect mechanical losses in the second equation. Electromagnetic torque is

Te = Pag / ωs = Pmech,dev / ωm

because ωm = (1-s)ωs. The torque unit is newton-metres when power is in watts and angular speed is in radians per second.

At steady state, the developed electromagnetic torque balances load torque plus friction and windage torque. Acceleration occurs when the net torque is positive:

J dωm/dt = Te - TL - Tloss

where J is the combined inertia in kilogram-metres squared, TL is load torque, and Tloss represents mechanical loss torque. This equation is the basic mechanical dynamic model.

2. Steady-state per-phase model

The induction motor can be represented by a transformer-like per-phase equivalent circuit. Referred to the stator, the principal parameters are:

SymbolMeaningTypical unit
R1Stator resistance per phaseΩ
X1Stator leakage reactance at rated frequencyΩ
R2'Rotor resistance referred to statorΩ
X2'Rotor leakage reactance referred to statorΩ
XmMagnetizing reactanceΩ
RcCore-loss resistance, if includedΩ
V1Applied stator phase rms voltageV
sSlipdimensionless

The rotor branch is commonly written as R2'/s + jX2'. This form separates the rotor copper-loss effect from the mechanical power conversion effect. An approximate torque expression, using the Thevenin equivalent seen by the rotor branch, is

Te = (3 / ωs) × (|Vth|² (R2'/s)) / ((Rth + R2'/s)² + (Xth + X2')²)

Here Vth, Rth, and Xth are the Thevenin voltage and impedance parameters of the stator and magnetizing network, viewed from the rotor branch. The formula assumes balanced sinusoidal operation, steady state, constant parameters, and an rms per-phase equivalent circuit.

An equivalent form uses rotor resistance as the variable:

Te = (3 |Vth|² / ωs) × (s R2') / ((Rth + sR2')² + (Xth + X2')²)

The second form is obtained by multiplying numerator and denominator by s². Both forms are equivalent; the first is often convenient for circuit calculations, and the second makes the slip dependence more visible.

Torque characteristics

At small slip, torque is approximately proportional to slip, so the motor behaves approximately like a spring with respect to speed deviation. As slip increases, rotor current and torque increase until breakdown or maximum torque is reached. Beyond this point, increased slip causes torque to decrease because leakage-reactance voltage drops dominate.

The approximate slip at maximum torque is

smax ≈ R2' / √(Rth² + (Xth + X2')²)

and, if stator resistance is neglected,

smax ≈ R2' / (X1 + X2')

These expressions show that increasing rotor resistance moves maximum torque to a higher slip, improving starting torque, but does not substantially change the maximum torque in the simplified model. Increased voltage raises torque approximately with the square of voltage:

Te ∝ V1²

This proportionality applies when frequency and machine parameters are fixed and magnetic saturation is not significant. It explains why voltage reduction can cause a severe loss of starting torque.

3. Dynamic induction-machine model

The steady-state equivalent circuit cannot describe transients such as starting, sudden load changes, converter switching, or dynamic braking. A dynamic model expresses stator and rotor voltage equations in a stationary or synchronously rotating two-axis reference frame.

In a synchronously rotating dq frame, a commonly used flux-linkage model is

vds = Rs ids + dψds/dt - ωe ψqs
vqs = Rs iqs + dψqs/dt + ωe ψds
vdr = Rr idr + dψdr/dt - (ωe - ωr) ψqr
vqr = Rr iqr + dψqr/dt + (ωe - ωr) ψdr

For a squirrel-cage rotor, rotor terminal voltages are zero: vdr = vqr = 0. Here Rs and Rr are phase-equivalent resistances, ωe is electrical reference-frame speed, and ωr is rotor electrical speed. The flux-current relations are

ψds = Ls ids + Lm idr
ψqs = Ls iqs + Lm iqr
ψdr = Lm ids + Lr idr
ψqr = Lm iqs + Lr iqr

where Ls and Lr are stator and rotor inductances and Lm is mutual inductance. The electromagnetic torque is

Te = (3/2) p (ψds iqs - ψqs ids)

for peak-valued space-vector quantities under the stated transformation convention. Other conventions may alter the numerical coefficient; therefore the definition of the dq transformation must be kept consistent.

The dynamic model is more informative than the steady-state circuit but requires parameter knowledge, coordinate transformations, initial conditions, and numerical integration. Scalar control generally does not require real-time use of the complete model, whereas vector control uses it more directly.

4. Scalar voltage-frequency control

Constant V/f principle

For sinusoidal steady-state operation, neglecting stator resistance, the stator induced voltage is approximately

E1 ≈ 4.44 kw N1 f1 Φm

where kw is the winding factor, N1 is series turns per phase, and Φm is peak fundamental air-gap flux. Thus, maintaining constant V1/f1 approximately maintains constant flux.

A VFD therefore changes voltage and frequency together:

V1/f1 = constant

up to rated frequency. Since torque capability is approximately proportional to the square of flux for a given current capability, constant flux supports approximately constant maximum torque over the base-speed region.

At low frequency, the stator resistive drop I1R1 is a significant fraction of applied voltage. Pure constant V/f would then produce insufficient air-gap flux. Drives compensate with a low-speed voltage boost, either as a fixed boost or a current-dependent boost. Excessive boost causes saturation, high current, and heating.

Above rated frequency, the inverter cannot normally increase voltage beyond its dc-link and insulation limits. Voltage is then approximately constant while frequency increases, so flux decreases:

Φm ∝ V1/f1

This is the field-weakening region. Torque capability generally decreases approximately inversely with speed, while power can remain approximately constant, subject to current, voltage, and mechanical limits.

Frequency and speed control

The approximate speed command is selected from the desired synchronous speed:

f1 = P ns / 120

The actual rotor speed is lower by the slip speed. Without feedback, scalar control is open loop: changes in load cause slip changes and therefore speed error. Slip compensation improves regulation by adding an estimated slip-frequency command to the frequency associated with desired rotor speed.

A practical command is

f1^* = fslip^* + (P nm^*/120)

where nm^* is the desired mechanical speed and fslip^* is estimated from torque-producing current or a motor model. In sensorless drives, speed and slip are estimated from measured currents, voltage, and motor parameters. Parameter errors, especially rotor resistance variation with temperature, limit accuracy.

VFD power stage and configuration

A conventional VFD consists of:

  1. A rectifier that converts ac supply to a dc voltage.
  2. A dc-link capacitor, sometimes with a dc reactor or braking chopper.
  3. A voltage-source inverter using semiconductor switches such as IGBTs or MOSFETs.
  4. A controller that generates switching commands through sinusoidal PWM or space-vector PWM.
  5. Protection and interface functions for overcurrent, overvoltage, thermal overload, ground fault, and loss of phase.

The user typically enters motor nameplate voltage, current, frequency, rated speed, power, power factor, and sometimes efficiency. The drive uses these values to establish base frequency, current limits, thermal models, and slip compensation. Motor auto-tuning may estimate resistance and inductance; it must be performed according to the manufacturer’s safety procedure.

A basic commissioning sequence is:

  • Verify motor and drive voltage, current, power, and frequency compatibility.
  • Confirm the motor connection, such as wye or delta, at the selected voltage.
  • Enter accurate nameplate data.
  • Set minimum and maximum frequency, acceleration and deceleration times, current limit, and stopping mode.
  • Check rotation direction at low speed with the load safe.
  • Test unloaded and then progressively increase load while observing current, temperature, and fault history.

5. Starting, stopping, and braking

Direct-on-line starting applies rated frequency and voltage immediately. Starting current may be five to eight times rated current, depending on motor design, while starting torque is limited by the motor’s characteristic and supply voltage.

A VFD starts at low frequency and proportionally low voltage. This limits inrush current and permits controlled acceleration. The acceleration ramp must be long enough that motor torque exceeds load torque without exceeding current or thermal limits. A very short ramp can force the drive into current limiting or cause a stall fault.

Soft starters use thyristors to reduce the applied rms voltage during starting, generally at fixed supply frequency. They reduce current and mechanical shock but do not provide continuous speed control. Because torque approximately follows voltage squared, excessive voltage reduction can prevent acceleration, especially for constant-torque loads.

Stopping methods include:

  • Coast stop: inverter output is removed and the load decelerates naturally.
  • Ramp stop: frequency is reduced under control.
  • Dynamic braking: regenerative energy is dissipated in a braking resistor through a chopper.
  • Regenerative braking: energy is returned to the dc link and, with a suitable active front end, to the supply.
  • DC injection braking: direct-current stator excitation creates a stationary field and braking torque; it is effective at low speed but produces rotor heating and does not return energy to the supply.

The braking resistor must be selected for both peak braking power and average thermal duty. An overvoltage trip occurs if regenerated energy raises dc-link voltage beyond the drive limit.

6. Worked example: speed, slip, and power flow

A four-pole, 50 Hz induction motor runs at 1,440 r/min and has an air-gap power of 30 kW. Find synchronous speed, slip, rotor frequency, rotor copper loss, developed mechanical power, and electromagnetic torque. Neglect mechanical losses.

Synchronous speed:

ns = 120 × 50 / 4 = 1500 r/min

Slip:

s = (1500 - 1440)/1500 = 0.04 = 4%

Rotor frequency:

f2 = s f1 = 0.04 × 50 = 2 Hz

Rotor copper loss:

Pr,cu = sPag = 0.04 × 30 = 1.2 kW

Developed mechanical power:

Pmech,dev = (1-s)Pag = 0.96 × 30 = 28.8 kW

Synchronous angular speed is

ωs = 2π × 50 / 2 = 157.08 rad/s

Therefore electromagnetic torque is

Te = Pag/ωs = 30000/157.08 ≈ 191 N·m

The same result follows from developed power divided by rotor angular speed, ωm = 2π(1440/60) ≈ 150.80 rad/s, giving approximately 191 N·m.

7. Applied case: VFD retrofit for a conveyor

Background

This illustrative case concerns a 15 kW, 400 V, 50 Hz, four-pole squirrel-cage motor driving a conveyor. The conveyor requires nearly constant torque over its normal speed range. The original system used direct-on-line starting, causing mechanical shock and supply-voltage disturbances.

Problem

The plant wants adjustable speed from 25 to 50 Hz, reduced starting current, controlled stopping, and adequate low-speed torque. The conveyor must not unexpectedly restart after a power interruption.

Analysis

The base synchronous speed is 1,500 r/min. A command of 25 Hz gives a base synchronous speed of 750 r/min. Actual speed will be slightly lower because of slip. Since the load is approximately constant torque, the drive must maintain current and flux capability throughout the 25–50 Hz range. A fan-oriented quadratic torque profile would be inappropriate because it could under-excite the motor at low speed.

Approach and solution

A correctly rated voltage-source VFD is selected with continuous output current at least equal to the motor’s nameplate current and overload capacity appropriate for conveyor duty. The motor nameplate data are entered, constant-torque mode is selected, and acceleration and deceleration ramps are initially set conservatively. Low-speed voltage boost is enabled only to the extent required by measured starting performance.

A braking resistor is considered because the conveyor has significant rotating and translating inertia. If the conveyor must stop quickly, resistor duty is calculated from the expected kinetic energy and stopping frequency. A normally closed permissive circuit, emergency-stop function, and controlled restart inhibit are implemented. The drive is tested first without product, then with incremental load.

Outcome

The retrofit reduces starting current and mechanical shock, permits production-rate adjustment, and provides repeatable ramp stopping. The final settings are validated by measuring motor current, acceleration time, motor temperature, and dc-link behavior during stopping. The system is not accepted merely because it runs: protection, restart behavior, braking resistance, enclosure cooling, and electromagnetic compatibility are also verified.

Learning points

The correct control mode depends on load torque. Nameplate configuration is essential. Low-speed operation may be thermally restricted because the motor’s shaft-mounted fan produces less cooling. Finally, a VFD is a safety-relevant power system: software settings must be supported by hardwired protective functions and risk assessment.

8. Limitations, hazards, and best practices

Scalar control has important limitations. It provides weaker transient torque control than field-oriented control, has speed error under load unless slip compensation or feedback is used, and is sensitive to parameter changes. At very low speed, voltage-drop compensation and inverter dead time affect flux accuracy. At high speed, voltage limitation causes field weakening and reduced torque.

PWM produces harmonic currents, acoustic noise, common-mode voltages, and possible bearing-current damage. Long motor cables can create reflected-wave overvoltage at the motor terminals. Suitable cable type, grounding, output filters, dv/dt filters, or sine-wave filters may be required. Motor insulation and bearing protection should be checked for inverter duty.

A motor’s thermal capacity is not determined solely by rms current. Low-speed cooling, repeated acceleration, high ambient temperature, harmonic loss, and frequent braking all influence temperature. The drive’s electronic overload model must be configured correctly, and independent thermal protection may be required by applicable electrical codes and plant standards.

Electrical safety requires isolation, lockout/tagout, discharge time for dc-link capacitors, protective earthing, correct fusing, and guarding of rotating machinery. Emergency-stop design should bring the machine to a safe state; removing a control signal alone may not be equivalent to a certified safety function. Applicable national standards, machinery regulations, and manufacturer instructions must be followed.

9. Contemporary developments

Scalar control remains useful in low-cost drives, but modern products increasingly combine it with sensorless flux estimation, automatic motor identification, adaptive current limiting, and energy optimization. Energy-saving algorithms can reduce flux at light load, particularly in variable-torque applications, but optimization must not compromise stability or required torque.

For demanding applications, field-oriented control and direct torque control provide faster torque response and better low-speed performance. These methods require more computation, parameter estimation, and commissioning effort. The engineering choice should be based on required bandwidth, speed accuracy, regeneration, cost, maintainability, and safety—not on control sophistication alone.

Chapter Summary

An induction motor produces torque because rotor currents induced by relative motion interact with the rotating stator field. Synchronous speed depends on supply frequency and pole number, while slip measures the speed difference required for induction. Rotor frequency equals slip multiplied by stator frequency. Air-gap power divides into rotor copper loss and converted mechanical power, making slip central to the machine’s power flow.

The steady-state equivalent circuit predicts current, torque, losses, and operating characteristics under balanced sinusoidal conditions. The dynamic dq model describes transient voltage, flux, current, and torque behavior. Scalar control varies voltage and frequency together to maintain approximately constant flux below base speed. Above base speed, voltage is limited and the machine operates in field weakening.

VFDs provide controlled starting, speed adjustment, stopping, and braking, but successful application requires correct motor data, load classification, thermal analysis, braking design, electromagnetic compatibility, protection, and safe commissioning. Scalar control is economical and robust, whereas demanding dynamic applications may require vector-based methods.

Key Terms

Synchronous speed: Speed of the rotating stator magnetic field.

Slip: Relative speed difference between synchronous speed and rotor speed, normalized by synchronous speed.

Rotor frequency: Electrical frequency induced in the rotor; equal to slip times stator frequency.

Air-gap power: Electromagnetic power transferred from stator to rotor.

Rotor copper loss: Resistive loss in rotor conductors, equal to slip times air-gap power.

Breakdown torque: Maximum torque available before the torque-speed characteristic declines.

Thevenin equivalent: Reduced voltage-source and impedance representation used to analyze the rotor branch.

Dynamic model: Differential-equation representation of voltage, flux, current, speed, and torque.

dq model: Two-axis model in a stationary or rotating reference frame.

Scalar control: Control of magnitudes such as voltage and frequency rather than instantaneous space vectors.

Constant V/f control: Method that approximately maintains air-gap flux by keeping voltage-to-frequency ratio constant.

Voltage boost: Additional low-frequency voltage used to compensate for stator resistance drop.

Base speed: Speed corresponding approximately to rated voltage and rated frequency.

Field weakening: Operation above base frequency with limited voltage and reduced flux.

Slip compensation: Frequency adjustment intended to offset load-dependent speed error.

Soft starter: Thyristor-based device that controls applied voltage during starting but normally does not provide continuous speed control.

Variable-frequency drive: Power-electronic system that controls motor frequency and voltage.

Dynamic braking: Dissipation of regenerated energy in a braking resistor.

Regenerative braking: Return of mechanical energy to the dc link or electrical supply.

Inverter-duty motor: Motor designed to tolerate stresses associated with PWM drives.

Review Questions

Short Answer Questions

  1. Why must a motoring induction motor operate below synchronous speed?
  2. Define slip and state its relationship to rotor frequency.
  3. What physical meaning is assigned to the term R2'/s in the equivalent circuit?
  4. Why is low-frequency voltage boost used in scalar control?
  5. Distinguish a soft starter from a variable-frequency drive.

Long Answer Questions

  1. Derive the induction-motor power-flow relationships connecting air-gap power, rotor copper loss, and developed mechanical power.
  2. Explain the steady-state torque-slip characteristic and discuss the effects of voltage and rotor resistance.
  3. Describe the voltage-source VFD power stage and the function of each major component.
  4. Explain constant-flux operation below base speed and field-weakening operation above base speed.
  5. Compare scalar control, sensorless scalar control with slip compensation, and field-oriented control.

Analytical / Application Questions

  1. A six-pole, 50 Hz motor runs at 960 r/min. Calculate synchronous speed, slip, and rotor frequency.
  2. A motor receives 40 kW of air-gap power at 3% slip. Calculate rotor copper loss and developed mechanical power, neglecting mechanical losses.
  3. A conveyor requires constant torque and frequent controlled stops. Recommend a drive configuration and identify the motor, braking, protection, thermal, and safety checks required before commissioning.

Multiple Choice Questions with Answers

Question 1

A four-pole induction motor is supplied at 50 Hz. What is its synchronous speed?

A. 750 r/min

B. 1,000 r/min

C. 1,500 r/min

D. 3,000 r/min

Correct Answer: C. 1,500 r/min

Question 2

A motor has synchronous speed 1,500 r/min and rotor speed 1,440 r/min. What is the slip?

A. 2%

B. 4%

C. 6%

D. 8%

Correct Answer: B. 4%

Question 3

For an induction motor with air-gap power Pag and slip s, rotor copper loss is:

A. (1-s)Pag

B. Pag/s

C. sPag

D. s2Pag

Correct Answer: C. sPag

Question 4

If a motor operates at 50 Hz with 4% slip, what is its rotor electrical frequency?

A. 0.5 Hz

B. 2 Hz

C. 4 Hz

D. 12.5 Hz

Correct Answer: B. 2 Hz

Question 5

The principal purpose of constant V/f control below base speed is to maintain approximately constant:

A. Rotor resistance

B. Air-gap flux

C. Rotor frequency

D. Mechanical loss

Correct Answer: B. Air-gap flux

Question 6

Why is voltage boost needed at very low frequency?

A. To compensate for stator resistive voltage drop

B. To increase the number of poles

C. To eliminate rotor slip

D. To reduce synchronous speed to zero

Correct Answer: A. To compensate for stator resistive voltage drop

Question 7

Above base frequency, a conventional VFD usually operates with approximately constant voltage and:

A. Increasing flux

B. Constant rotor resistance

C. Decreasing flux

D. Zero slip

Correct Answer: C. Decreasing flux

Question 8

Which braking method dissipates regenerated energy in a resistor?

A. Coast stopping

B. Dynamic braking

C. Open-circuit stopping

D. Mechanical freewheeling

Correct Answer: B. Dynamic braking

Question 9

A soft starter normally controls motor:

A. Applied voltage during starting

B. Rotor resistance continuously

C. Pole number during running

D. Air-gap frequency independently of supply frequency

Correct Answer: A. Applied voltage during starting

Question 10

For a constant-torque conveyor, which VFD application setting is generally most appropriate?

A. Quadratic variable-torque profile

B. Constant-torque profile with suitable overload capacity

C. Field-weakening-only profile

D. No current limiting or thermal model

Correct Answer: B. Constant-torque profile with suitable overload capacity

Electrical Drives & Control
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