Chapter 3
Mechanical Properties and Material Behavior
Bachelors Program in Construction Technology
Basic Material Science
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Bachelor
Mechanical Properties and Material Behavior
Introduction
Construction materials are selected not only for appearance, availability, cost, and durability, but also for how they carry and respond to load. A concrete column, steel beam, masonry wall, timber roof member, asphalt pavement, and polymer sealant all experience stresses and deformations during manufacture, construction, service, and sometimes fire or environmental exposure. Understanding mechanical behavior enables engineers and construction technologists to predict deformation, prevent failure, select suitable materials, and interpret test results.
Mechanical properties describe the response of a material to applied forces. Some properties, such as strength and hardness, indicate resistance to particular forms of damage. Others, such as stiffness, ductility, and toughness, describe how a material deforms or absorbs energy. These properties are related but not interchangeable: a material may be strong but brittle, stiff but weak, or hard but not tough.
This chapter focuses on stress, strain, elastic and plastic behavior, strength, stiffness, hardness, toughness, ductility, brittleness, fatigue, creep, and fracture. The discussion uses the tensile test as a central model while recognizing that real construction materials may behave differently in compression, shear, bending, temperature variation, and long-term service.
Learning Objectives
After studying this chapter, a student should be able to:
Define stress and strain and calculate basic tensile and compressive values.
Interpret a typical engineering stress–strain curve.
Distinguish elasticity, plasticity, strength, stiffness, hardness, toughness, ductility, and brittleness.
Apply Hooke’s law within its range of validity.
Explain fatigue, creep, stress relaxation, and fracture.
Relate mechanical properties to construction-material selection and structural safety.
Identify the limitations of laboratory tests and the importance of defects, environment, loading rate, and workmanship.
1. Loads, Stress, and Strain
1.1 External loads and internal resistance
A load is an external force or action applied to a body. Common construction loads include dead load, live load, wind, impact, thermal action, shrinkage, settlement, and earthquake action. The material develops internal resistance so that the body can remain in equilibrium.
Loads may be classified as:
Tension: pulls a member apart.
Compression: pushes a member together.
Shear: causes adjacent planes to slide.
Bending: produces tension and compression across a section.
Torsion: produces twisting and shear stress.
Impact: applies load over a short time.
Repeated or cyclic loading: varies with time and may cause fatigue.
1.2 Normal stress
Average normal stress is the force acting perpendicular to a cross-sectional area divided by that area:
σ = P/A₀
where σ is average normal stress in pascals (Pa), P is axial force in newtons (N), and A₀ is the original cross-sectional area in square metres (m²). In construction calculations, MPa is convenient because 1 MPa = 1 N/mm².
Tensile stress is conventionally positive and compressive stress negative, although some design documents use compression as a positive magnitude. The sign convention must be stated and used consistently.
The formula assumes that the stress is reasonably uniform over the area and that the member is loaded axially. Near holes, abrupt changes in section, cracks, welds, and supports, the local stress may be much higher than the average value.
1.3 Normal strain
Normal strain is the change in length divided by the original length:
ε = ∆L/L₀ = (L − L₀)/L₀
where ε is dimensionless strain, L₀ is original gauge length, L is final length, and ∆L is change in length. Tensile strain is positive and compressive strain is negative under the usual convention. Strain may also be expressed as a percentage by multiplying by 100.
Because strain is a ratio of two lengths, it has no physical unit. For example, ε = 0.002 is equivalent to 0.2% strain.
1.4 Shear stress and shear strain
Average shear stress is:
τ = V/A
where τ is average shear stress, V is shear force, and A is the resisting area. Shear strain, γ, is the angular distortion caused by shear and is measured in radians, which are dimensionless in SI analysis.
For small elastic shear deformation:
τ = Gγ
where G is the shear modulus. This relationship applies only within the linear elastic range for a homogeneous material under appropriate conditions.
1.5 Poisson’s ratio
When a bar is stretched, it usually contracts laterally. Poisson’s ratio is:
ν = −εlateral/εlongitudinal
where ν is Poisson’s ratio. The minus sign makes ν positive for the usual case in which longitudinal extension is accompanied by lateral contraction. Typical values are approximately 0.2–0.3 for ordinary concrete and about 0.3 for many steels, but actual values depend on composition, moisture, stress level, and testing conditions.
For isotropic linear elastic materials, the elastic constants are related by:
E = 2G(1 + ν)
where E is Young’s modulus and G is the shear modulus. This relation should not be applied to anisotropic materials such as timber without suitable directional definitions.
2. The Engineering Stress–Strain Curve
A tensile test records force and elongation. These readings are converted into engineering stress and engineering strain using the original dimensions. A typical ductile-metal curve contains an elastic region, yielding, plastic flow, strain hardening, ultimate tensile strength, necking, and fracture.
Typical engineering stress strain curve for a ductile material
Figure: Typical engineering stress strain curve for a ductile material
Figure: Schematic engineering stress–strain curve for a ductile material; exact shape varies with material and test conditions.
The initial approximately straight portion represents proportional behavior. Its slope is Young’s modulus, E. The material returns approximately to its original dimensions when the load is removed, provided the stress has not exceeded the elastic limit.
The yield point marks the beginning of significant permanent deformation. Some steels show a distinct upper and lower yield point; other materials do not. For materials without a clear yield point, engineers often use the 0.2% proof stress. This is the stress corresponding to a permanent strain of 0.2% after unloading.
During plastic deformation, strain increases without complete recovery. In many metals, the stress rises again after yielding because of strain hardening. The maximum engineering stress is the ultimate tensile strength, calculated as:
σu = Pmax/A₀
where P_max is the maximum recorded force and A₀ is the original area. After the maximum load, localized necking may occur. Because engineering stress still uses A₀, it may decrease even while the true local stress in the neck increases.
The area under the stress–strain curve represents energy per unit volume absorbed during deformation. The area up to the elastic limit is the modulus of resilience; the total area up to fracture is commonly associated with toughness for a tensile specimen.
3. Elasticity, Plasticity, Strength, and Stiffness
3.1 Elasticity
Elasticity is the ability to recover original shape after removal of load. Elastic deformation is generally small and reversible, although perfect recovery is an idealization. Temperature, time, microstructure, and loading rate can affect elastic response.
For linear elastic uniaxial loading, Hooke’s law is:
σ = Eε
E is Young’s modulus in Pa, σ is normal stress in Pa, and ε is strain. The equation is valid only in the linear elastic range. It must not be used to predict plastic deformation, cracking concrete, or long-term creep without an appropriate constitutive model.
The axial extension of a uniform prismatic bar follows from the same relation:
∆L = PL₀/(AE)
This equation assumes axial loading, constant area, uniform material, small deformation, and elastic behavior. If area or material changes along the member, the member should be divided into segments or integrated using the corresponding stiffness.
Worked Example 1: Elastic extension
A steel tie has length 2.0 m, cross-sectional area 600 mm², and carries a tensile force of 60 kN. Take E = 200 GPa. Determine the elastic extension.
Convert consistently: P = 60,000 N, A = 600 mm² = 600 × 10⁻⁶ m², L₀ = 2.0 m, and E = 200 × 10⁹ Pa.
Therefore, ∆L = 1.0 mm. The corresponding stress is 100 MPa and the strain is 0.0005, or 0.05%, which is within the assumed elastic range for ordinary structural steel.
3.2 Plasticity
Plasticity is the capacity to undergo permanent deformation without immediate fracture. Plastic deformation is important because it can redistribute stress and provide warning before collapse. However, excessive plastic strain may make a member unusable, cause unacceptable deflection, or reduce stability.
Metals commonly exhibit plasticity through dislocation movement. Concrete behaves differently: it is relatively brittle in tension but can show nonlinear crushing and limited plastic-like behavior in compression. Timber is orthotropic and may yield or crush differently parallel and perpendicular to grain. Polymers may show strong rate- and temperature-dependent plasticity.
3.3 Strength
Strength is the ability to resist an applied action without unacceptable failure. It must always be qualified: tensile strength, compressive strength, shear strength, yield strength, fatigue strength, and fracture strength are different properties.
A material’s nominal strength is not automatically a safe design stress. Design values incorporate partial safety factors, load combinations, material variability, workmanship, deterioration, and consequences of failure. Standardized test strength also depends on specimen size, shape, curing, moisture, loading rate, and test method.
3.4 Stiffness
Stiffness is resistance to deformation. Material stiffness in uniaxial tension is represented primarily by E, while member stiffness depends on both material and geometry. For a prismatic axial member, axial stiffness is:
k = AE/L₀
where k is force per unit displacement. A large cross-sectional area and high E increase stiffness; a longer member decreases it. Thus strength and stiffness are not synonyms. A high-strength steel and a lower-strength steel may have similar E values, while their yield stresses differ substantially.
4. Hardness, Toughness, Ductility, and Brittleness
4.1 Hardness
Hardness is resistance to localized indentation, scratching, and wear. Common tests include Brinell, Rockwell, and Vickers methods. Hardness can help assess wear resistance and, for some metals, provide an approximate indication of strength. Such correlations are empirical and material-specific; hardness should not replace a required tensile or fracture test.
In construction, hardness is relevant to flooring, aggregates, cutting tools, rails, abrasion-resistant plates, and surface treatments. A hard material may still be brittle and susceptible to sudden fracture.
4.2 Toughness
Toughness is the ability to absorb energy before fracture. It depends on both strength and ductility. The tensile stress–strain curve provides an approximate measure of tensile toughness through its area, but fracture toughness is a different property concerned specifically with crack growth.
A tough material can tolerate impact, stress concentrations, and some crack extension. Toughness is especially important for steel structures exposed to low temperature, impact, seismic action, or welding-related defects.
4.3 Ductility
Ductility is the capacity for significant plastic deformation before fracture. It may be measured by percentage elongation or reduction of area in a tensile test:
Percentage elongation = [(Lf − L₀)/L₀] × 100
Reduction of area = [(A₀ − Af)/A₀] × 100
L_f is the final gauge length and A_f is the minimum final cross-sectional area. These measures depend on specimen geometry and gauge length, so comparisons require the same standard test procedure.
Ductility can provide visible warning through yielding and large deformation. It also permits redistribution of stresses in appropriately detailed structures. Excessive ductility, however, can produce large service deflections and is not a substitute for adequate strength.
4.4 Brittleness
Brittleness is the tendency to fracture with little plastic deformation. Glass, many ceramics, hardened cast irons, and plain concrete in tension are relatively brittle. Brittle fracture may occur suddenly, especially when a sharp crack, low temperature, high loading rate, or tensile residual stress is present.
A material is not simply “ductile” or “brittle” in all circumstances. Temperature, strain rate, thickness, stress state, moisture, defects, and manufacturing history may change its behavior.
5. Fracture and Cracks
Fracture is the separation of a material into two or more parts. It may be ductile, brittle, fatigue-related, environmentally assisted, or a combination of these.
A crack creates a stress concentration because load-carrying paths are forced around its tip. In linear elastic fracture mechanics, the mode-I stress intensity factor for a simplified cracked body is often written:
KI = Yσ√(πa)
where K_I is mode-I stress intensity, Y is a dimensionless geometry factor, σ is nominal tensile stress, and a is a characteristic crack length. The expression assumes small-scale yielding and linear elastic conditions. Fracture is predicted when K_I reaches the material’s critical fracture toughness K_IC under the relevant conditions:
KI ≥ KIC
This simplified relation should not be used without checking crack geometry, specimen thickness, plastic-zone size, loading mode, and applicable testing standards.
Construction defects such as weld discontinuities, honeycombing, poor compaction, unsealed cracks, corrosion pits, and sharp corners can initiate or accelerate fracture. Good detailing reduces stress concentrations; inspection and non-destructive testing can locate critical flaws.
6. Fatigue Under Repeated Loading
Fatigue is progressive damage caused by repeated or fluctuating stress, often at stress levels below the static yield strength. A fatigue failure generally involves crack initiation, crack growth, and final fracture.
Important variables include stress range, mean stress, frequency, number of cycles, surface finish, residual stress, corrosion, temperature, and size. An S–N curve plots stress amplitude or stress range against cycles to failure. Some steels show an approximate endurance limit under particular test conditions, but many materials—including aluminum alloys and concrete—do not possess a sharp endurance limit.
For a constant-amplitude cycle:
σa = (σmax − σmin)/2
σm = (σmax + σmin)/2
where σ_a is stress amplitude, σ_m is mean stress, σ_max is maximum stress, and σ_min is minimum stress. These definitions do not themselves predict life; a suitable fatigue model and material data are required.
Fatigue is important in bridges, cranes, railways, traffic pavements, rotating equipment, pile-driving systems, and structures exposed to wind or waves. Design practice seeks to reduce stress concentrations, improve surface quality, control welding details, avoid water ingress and corrosion, and inspect critical locations.
7. Creep and Stress Relaxation
Creep is time-dependent deformation under sustained stress. It is significant at elevated temperature and can also be important at ordinary temperatures in concrete, timber, asphalt, polymers, and other viscoelastic materials.
A typical creep curve has primary creep, in which the rate decreases; secondary creep, with an approximately steady rate; and tertiary creep, in which damage accelerates toward failure. Temperature, stress level, moisture, age, mixture composition, and environmental exposure affect creep.
Concrete creep can increase long-term deflection, redistribute forces in composite members, and reduce prestress. Timber creep depends strongly on moisture changes. Asphalt and polymers may deform substantially under sustained load in warm conditions.
Stress relaxation is the reduction in stress with time when strain is held approximately constant. It is relevant to prestressing systems, seals, gaskets, polymer components, and connections. Creep and relaxation are related but not identical: creep is observed under sustained stress, whereas relaxation is observed under sustained strain.
Elastic formulas alone cannot predict long-term response. A time-dependent constitutive law, experimentally determined creep coefficient, or design-code procedure is required.
8. Mechanical Behavior of Common Construction Materials
Material
Typical mechanical behavior
Key construction implication
Structural steel
Ductile, relatively uniform E, yielding before rupture in many grades
Good redistribution and warning; check buckling, fatigue, corrosion, and brittle fracture
Concrete
Strong in compression, weak and cracking in tension, time-dependent
Reinforcement, curing, shrinkage and creep control are essential
Timber
Anisotropic, moisture- and grain-dependent, comparatively light
Orient grain correctly; check knots, connections, moisture and long-term deformation
Masonry
Stronger in compression than tension; joints influence behavior
Workmanship, mortar, slenderness and crack control are important
Glass and ceramics
Hard, stiff, and generally brittle
Avoid tensile stress concentrations; use safety glazing and careful edge treatment
Asphalt and polymers
Viscoelastic and temperature-dependent
Consider loading duration, temperature, creep, fatigue and aging
Composite construction combines materials to exploit different properties. Reinforced concrete uses steel to carry tensile forces while concrete provides compression resistance and protection. Composite steel–concrete floors rely on interaction between materials, requiring attention to slip, bond, differential creep, shrinkage, and thermal movement.
9. Worked Example 2: Stress, Strain, and Ductility
A tensile coupon has an original area of 500 mm² and gauge length of 200 mm. At a particular load, it carries 150 kN and its length is 200.8 mm. At fracture, its final gauge length is 250 mm and its minimum area is 300 mm². Determine the engineering stress and strain at the particular load, percentage elongation, and reduction of area.
Stress:
σ = P/A₀ = 150,000/500 = 300 N/mm² = 300 MPa
Strain at the particular load:
ε = (200.8 − 200)/200 = 0.004 = 0.4%
Percentage elongation:
[(250 − 200)/200] × 100 = 25%
Reduction of area:
[(500 − 300)/500] × 100 = 40%
These values describe engineering behavior based on original dimensions. They do not by themselves establish yield strength, ultimate strength, fatigue life, or fracture toughness.
10. Illustrative Case: Cracking in a Reinforced-Concrete Parking Beam
Background
A reinforced-concrete parking structure develops diagonal cracks near the supports after several years of service. The beam carries vehicle loads and has experienced repeated loading, winter moisture, and de-icing salts.
Problem
The owner must determine whether the cracks are harmless shrinkage cracks, shear-related structural cracks, or evidence of reinforcement corrosion and fatigue-related deterioration.
Analysis
The investigation begins with crack mapping, measurement of crack width and direction, review of drawings and loading history, and inspection of drainage. Diagonal cracks near supports may indicate high shear demand. Rust staining, delamination, and low concrete cover suggest corrosion. Repeated vehicle loading may widen existing cracks, while wet–dry cycles and salts accelerate reinforcement corrosion.
Material tests may include concrete strength cores, carbonation depth, chloride profiling, half-cell potential measurements, and reinforcement location scanning. These tests must be interpreted together; a single test cannot establish structural safety.
Approach and solution
The engineer first checks current loads and member capacity using the applicable structural code. Temporary load restrictions are imposed if required. Drainage is repaired, chloride-contaminated concrete is removed where appropriate, reinforcement is cleaned or supplemented, and the repair material is selected for compatibility. If shear capacity is inadequate, strengthening may involve externally bonded fiber-reinforced polymer, steel plates, added concrete, or other engineered measures. Monitoring gauges can determine whether cracks are active.
Outcome
Assume the investigation finds stable fine shrinkage cracks in some areas but active diagonal cracks and corrosion near two supports. Cosmetic sealing alone would not address the structural mechanism. The beams are repaired and strengthened, drainage is improved, and a periodic inspection plan is established.
Learning points
A visible crack is a symptom, not automatically a diagnosis.
Static strength does not fully describe fatigue, corrosion, or fracture risk.
Moisture, chemicals, workmanship, and detailing strongly influence mechanical behavior.
Repair decisions require structural analysis, material testing, code compliance, and professional judgment.
Monitoring and prevention are often more economical than late-stage intervention.
11. Limitations, Safety, and Professional Practice
Laboratory values should not be transferred directly to a structure without considering scale, variability, boundary conditions, defects, restraint, environmental exposure, and construction quality. Engineering stress may differ substantially from local stress. Nominal strength may conceal unstable crack growth. Material properties may change with age, temperature, moisture, fire, chemical exposure, and repeated loading.
Construction professionals should use recognized standards for sampling and testing, maintain traceability of materials, document curing and storage conditions, calibrate testing equipment, and report uncertainty. A test result must include specimen identification, dimensions, loading rate, failure mode, and relevant environmental conditions.
Safety factors and design codes address uncertainty but do not eliminate the need for inspection and judgment. Ethical practice requires reporting defects honestly, avoiding unsupported extrapolation, protecting public safety, and obtaining competent specialist advice when failure could be serious. Artificial intelligence can assist with crack-image classification, sensor-data analysis, and predictive maintenance, but model outputs require verified data, human review, explainable decision criteria, and protection against false negatives.
12. Best Practices for Material Selection and Assessment
Define the actual loading type, duration, temperature, environment, and required service life.
Distinguish strength, stiffness, toughness, hardness, and durability requirements.
Use test methods appropriate to the material and intended application.
Consider defects, joints, connections, surface condition, and stress concentrations.
Check both short-term and long-term deformation.
Assess fatigue where loads repeat or fluctuate.
Provide inspection, maintenance, drainage, corrosion protection, and repair access.
Use conservative, code-compliant design values rather than isolated laboratory maxima.
Record assumptions and verify units in every calculation.
Chapter Summary
Mechanical behavior describes how materials resist forces, deform, absorb energy, deteriorate, and fracture. Normal stress is force divided by original area, while normal strain is change in length divided by original length. Within the linear elastic range, Hooke’s law relates stress and strain through Young’s modulus. Elastic deformation is recoverable; plastic deformation is permanent.
Strength describes resistance to a specified failure mode, whereas stiffness describes resistance to deformation. Hardness concerns localized indentation and wear. Toughness is energy absorption before fracture, ductility is plastic deformation before rupture, and brittleness is fracture with little plastic deformation. The engineering stress–strain curve provides yield strength, ultimate tensile strength, ductility, and approximate energy measures, but its interpretation depends on test conditions.
Cracks and defects concentrate stress and can cause brittle or fatigue fracture. Repeated loading may cause fatigue even below static strength. Sustained loading may produce creep, while fixed deformation may produce stress relaxation. Construction materials differ greatly: steel is generally ductile, concrete is strong in compression but weak in tension, timber is directional, masonry is joint-sensitive, and polymers are often time- and temperature-dependent.
Safe construction practice requires appropriate testing, code-based design, attention to defects and environment, and recognition that laboratory properties do not fully describe structural performance.
Key Terms
Stress: Internal force per unit area developed in a material.
Strain: Deformation divided by original dimension.
Elasticity: Ability to recover shape after unloading.
Plasticity: Capacity for permanent deformation.
Young’s modulus: Slope of the linear elastic stress–strain relationship.
Stiffness: Resistance of a material or member to deformation.
Strength: Capacity to resist a specified failure mode.
Yield strength: Stress associated with the onset of significant plastic deformation.
Ultimate tensile strength: Maximum engineering tensile stress in a test.
Hardness: Resistance to indentation, scratching, or wear.
Toughness: Ability to absorb energy before fracture.
Ductility: Capacity for plastic deformation before fracture.
Brittleness: Tendency to fracture with little plastic deformation.
Fatigue: Progressive damage caused by repeated or fluctuating loading.
Creep: Time-dependent deformation under sustained stress.
Stress relaxation: Reduction in stress under approximately constant strain.
Fracture toughness: Resistance to crack growth under specified conditions.
Stress concentration: Local amplification of stress caused by geometry or defects.
Poisson’s ratio: Negative ratio of lateral strain to longitudinal strain.
Engineering stress: Load divided by original cross-sectional area.
Review Questions
Short Answer Questions
Define normal stress and normal strain, including their common units.
What is the difference between elastic and plastic deformation?
Distinguish strength from stiffness.
Why is a material’s toughness not the same as its hardness?
Define creep and stress relaxation.
Long Answer Questions
Explain the principal regions and properties represented on a typical engineering stress–strain curve for a ductile metal.
Discuss how defects, stress concentrations, and environmental conditions influence fracture.
Compare the mechanical behavior of structural steel, concrete, timber, and masonry in construction.
Explain fatigue mechanisms and describe measures used to reduce fatigue risk.
Discuss the limitations of using laboratory mechanical-property values in structural design.
Analytical / Application Questions
A steel tie is 1.5 m long, has an area of 400 mm², carries 40 kN, and has E = 200 GPa. Calculate its elastic extension and state the assumptions used.
A material has σ_max = 120 MPa and σ_min = −40 MPa in a cyclic test. Calculate stress amplitude and mean stress, and explain why these values alone do not determine fatigue life.
A concrete beam develops diagonal cracks near a support in a salty, wet environment. Propose an investigation plan and explain how shear, corrosion, fatigue, and durability could interact.
Multiple Choice Questions with Answers
Question 1
A member carries an axial tensile force of 50 kN over an original area of 250 mm². What is its average engineering stress?
A. 50 MPa
B. 125 MPa
C. 200 MPa
D. 500 MPa
Correct Answer: C. 200 MPa
Question 2
Which property is represented by the slope of the linear elastic portion of a uniaxial stress–strain curve?
A. Young’s modulus
B. Hardness
C. Toughness
D. Fracture toughness
Correct Answer: A. Young’s modulus
Question 3
A bar 1,000 mm long extends by 2 mm. What is its normal strain?
A. 0.0002
B. 0.002
C. 0.02
D. 2.0
Correct Answer: B. 0.002
Question 4
Which statement best describes ductility?
A. Resistance to localized indentation
B. Energy absorbed per unit volume before fracture
C. Ability to undergo plastic deformation before fracture
D. Resistance to elastic deformation
Correct Answer: C. Ability to undergo plastic deformation before fracture
Question 5
Under Hooke’s law, if E = 200 GPa and strain is 0.001, the stress is:
A. 0.2 MPa
B. 2 MPa
C. 20 MPa
D. 200 MPa
Correct Answer: D. 200 MPa
Question 6
What is the principal characteristic of fatigue failure?
A. Failure only above the static ultimate strength
B. Progressive damage under repeated or fluctuating stress
C. Immediate deformation caused by a single short load
D. Time-dependent deformation under constant stress only
Correct Answer: B. Progressive damage under repeated or fluctuating stress
Question 7
Creep is best defined as:
A. Crack growth caused only by impact
B. Reduction in hardness after indentation
C. Time-dependent deformation under sustained stress
D. Permanent deformation occurring only after fracture
Correct Answer: C. Time-dependent deformation under sustained stress
Question 8
Which material is generally strong in compression but comparatively weak and crack-prone in tension?
A. Concrete
B. Structural steel
C. Aluminum sheet
D. Copper wire
Correct Answer: A. Concrete
Question 9
In the simplified relation KI = Yσ√(πa), what does a represent?
A. Elastic modulus
B. Characteristic crack length
C. Cross-sectional area
D. Fatigue cycle frequency
Correct Answer: B. Characteristic crack length
Question 10
A material that fractures with very little plastic deformation is described as: