Analog & Digital Electronics

Chapter 1
Electronic Circuit Foundations and Engineering Practice

Bachelors Program in Electrical Engineering
Analog & Digital Electronics   •   Bachelor

Electronic Circuit Foundations and Engineering Practice

Introduction and Context

Analog and digital electronics are built from the same physical foundations: electric charge, voltage, current, energy, and power. Whether the circuit is a sensor amplifier, a microcontroller interface, a power converter, or a communication receiver, successful engineering requires the ability to predict circuit behavior, select suitable components, measure safely, and judge whether a result is credible.

This chapter develops the essential analytical and laboratory skills used throughout electrical engineering. It begins with circuit quantities and Kirchhoff’s laws, then introduces network reduction, Thévenin and Norton equivalents, impedance and phasors, loading, decibels, tolerances, uncertainty, and measurement practice.

Learning Objectives

By the end of this chapter, a student should be able to:

  1. Define voltage, current, charge, power, and energy with correct units and sign conventions.
  2. Apply Kirchhoff’s current and voltage laws to resistive circuits.
  3. Use series, parallel, voltage-divider, current-divider, Thévenin, Norton, and superposition methods under their applicability conditions.
  4. Analyze sinusoidal circuits using complex impedance and phasors.
  5. Predict loading effects and design voltage sources for specified loads.
  6. Convert voltage and power ratios to decibels.
  7. Distinguish component tolerance from measurement uncertainty and combine uncertainties appropriately.
  8. Use a digital multimeter, oscilloscope, function generator, and laboratory power supply safely and correctly.
  9. Recognize nonideal instruments, grounding constraints, bandwidth limitations, and measurement errors.

1. Electrical Quantities and Sign Conventions

Electric charge is measured in coulombs (C). Current is the rate of flow of charge:

i(t) = \frac{dq(t)}{dt}

where i(t) is current in amperes (A), q(t) is charge in coulombs, and t is time in seconds. Conventional current is defined as the motion of positive charge, even though conduction in metals is primarily due to electrons.

Voltage is energy transferred per unit charge:

v = \frac{dw}{dq}

where v is voltage in volts (V), w is energy in joules (J), and q is charge in coulombs. A voltage of 1 V corresponds to 1 J/C.

The instantaneous power absorbed by an element, using the passive sign convention, is:

p(t) = v(t)i(t)

The passive sign convention places the positive voltage reference at the terminal where the reference current enters. If p > 0, the element absorbs power; if p < 0, it delivers power. Energy transferred over an interval is:

W = \intt1t2 p(t)\,dt

For constant voltage and current, W = Pt. A resistor converts electrical energy mainly into heat. For a resistor of resistance R:

v = iR

and therefore:

p = vi = i2R = \frac{v2}{R}

These equations apply to an ideal ohmic resistor or to a resistor operating in a range where its resistance is approximately constant.

Worked Example 1: Power and Energy

A 12 V supply drives a 240 Ω resistor. The current is:

I = V/R = 12/240 = 0.050 A = 50 mA

The resistor power is:

P = V2/R = 122/240 = 0.60 W

If it operates for 10 minutes, the energy converted is:

W = Pt = 0.60 × 600 = 360 J

A resistor rated at 0.25 W would be unsuitable because its nominal dissipation exceeds its rating; a 0.5 W part would also have inadequate margin for reliable design. A 1 W part would provide a more appropriate rating, subject to temperature and derating requirements.

2. Circuit Laws and Basic Networks

Kirchhoff’s Current Law

Kirchhoff’s current law (KCL) follows from conservation of charge. At any node, the algebraic sum of currents is zero:

\sumk ik = 0

Equivalently, total current entering a node equals total current leaving it. KCL is applied at a physical connection between circuit elements. At very high frequencies, distributed electromagnetic effects may require a field-based model, but KCL is highly effective for ordinary lumped circuits.

Kirchhoff’s Voltage Law

Kirchhoff’s voltage law (KVL) follows from conservation of energy in a lumped circuit:

\sumk vk = 0

The signed sum of voltage rises and drops around any closed path is zero. The reference polarity chosen for each element must be maintained consistently.

Series and Parallel Elements

Elements are in series when they carry the same current and share only a node with no branching connection. For resistors in series:

Req = R1 + R2 + \cdots + Rn

Elements are in parallel when they have the same two terminal voltages. For two resistors in parallel:

Req = \frac{R1R2}{R1 + R2}

More generally, conductances add:

Geq = \sumk Gk, \qquad Gk = \frac{1}{Rk}

Voltage and Current Division

For two series resistors connected to voltage Vs, the voltage across R2 is:

V2 = Vs\frac{R2}{R1+R2}

This formula requires that the two resistors are genuinely in series and that no external load is connected at their junction. If a load is connected, the load must be included in the equivalent resistance.

For two parallel resistors carrying total current Is, the current through R1 is:

I1 = Is\frac{R2}{R1+R2}

The opposite resistor appears in the numerator because the lower-resistance branch carries more current.

Worked Example 2: Loaded Voltage Divider

A 10 V source feeds R1 = 4.7\,kΩ and R2 = 2.2\,kΩ in series. A 10 kΩ input is connected across R2. The effective lower resistance is:

R2,eff = 2.2\,kΩ \parallel 10\,kΩ = (2.2×10)/(2.2+10)\,kΩ = 1.803\,kΩ

Thus the actual output is:

Vo = 10 × 1.803/(4.7+1.803) = 2.773\,V

The unloaded prediction would be 10×2.2/(4.7+2.2) = 3.188\,V. The difference is loading error. A divider should therefore be designed with sufficiently low Thévenin resistance relative to its load, or followed by a buffer amplifier.

3. Network Theorems

Thévenin’s Theorem

Any linear two-terminal network containing sources and impedances can, at a specified frequency, be replaced at its terminals by an ideal voltage source Vth in series with an impedance Zth. For a purely resistive network, Zth becomes Rth.

To determine the equivalent:

  1. Find the open-circuit terminal voltage: Vth = Voc.
  2. Deactivate independent sources and find the resistance or impedance seen at the terminals. An ideal voltage source is short-circuited; an ideal current source is open-circuited.
  3. Alternatively, use Zth = Voc/Isc when short-circuit current is safely and meaningfully obtainable.

Dependent sources must remain active. In such cases, a test source is applied at the terminals and Zth = Vtest/Itest.

With a load ZL, the terminal voltage is:

VL = Vth\frac{ZL}{Zth+ZL}

Maximum average power transfer in a sinusoidal linear network occurs when:

ZL = Zth^*

where the asterisk denotes complex conjugate. In a purely resistive circuit this reduces to RL = Rth. Maximum power transfer is not the same as maximum efficiency; at the maximum-power condition, an ideal resistive source-load system has 50% efficiency.

Norton’s Theorem

The Norton equivalent is a current source IN in parallel with ZN, where:

IN = Isc, \qquad ZN = Zth

The two equivalents are related by:

Vth = INZN

Superposition

In a linear circuit with multiple independent sources, the response is the algebraic sum of responses caused by each source acting alone. When one source is considered, other independent voltage sources are replaced by shorts and independent current sources by opens. Dependent sources remain active. Superposition applies to voltage and current, but power cannot be directly superposed because power is nonlinear in voltage and current.

4. Impedance and Frequency-Domain Analysis

Sinusoidal steady-state analysis replaces differential relationships with algebraic relationships involving phasors. A sinusoid may be represented as:

v(t) = Vm cos(ωt + θ)

where Vm is peak amplitude, ω = 2πf is angular frequency in rad/s, f is frequency in hertz, and θ is phase. Phasors conventionally use RMS magnitudes unless stated otherwise. For a sinusoid, Vrms = Vm/√2.

Impedance is the frequency-dependent ratio of phasor voltage to phasor current:

Z = \frac{\underline{V}}{\underline{I}}

The ideal impedances are:

ElementImpedancePhase relation
ResistorZR = RVoltage and current in phase
InductorZL = jωLVoltage leads current by 90°
CapacitorZC = 1/(jωC)Voltage lags current by 90°

Here j = √{-1}, L is inductance in henrys, and C is capacitance in farads. Impedance calculations use the same series and parallel rules as resistance, but with complex numbers.

Worked Example 3: Series RC Phasor Calculation

A 10 V RMS, 1 kHz source drives a series circuit with R = 1.0\,kΩ and C = 100\,nF. The capacitor reactance is:

XC = -1/(2πfC) = -1/[2π(1000)(100×10-9)] = -1591.5\,Ω

Therefore:

Z = 1000 - j1591.5\,Ω

Its magnitude and phase are:

|Z| = √(10002+1591.52) = 1879.5\,Ω

∠Z = tan-1(-1591.5/1000) = -57.9°

The RMS current phasor is:

\underline{I} = 10∠0° / 1879.5∠(-57.9°) = 5.32\,mA∠57.9°

Thus current leads the source voltage by approximately 57.9°. The resistor voltage is \underline{VR = IR = 5.32\,V∠57.9°]. The capacitor voltage magnitude is |VC| = |I||XC| = 8.47\,V, with phase 57.9°−90° = −32.1°. The phasor sum of resistor and capacitor voltages equals the 10 V source, subject to rounding.

Frequency-domain methods apply to linear time-invariant circuits in sinusoidal steady state. They do not directly describe startup transients, nonlinear distortion, or arbitrary waveforms without additional methods such as Fourier analysis or numerical simulation.

5. Loading and Source Design

A practical voltage source is modeled as an ideal source followed by a source resistance or impedance. Connecting a load produces:

VL = Voc\frac{RL}{Rs+RL}

for a resistive source. The fractional voltage retained by the load is:

\frac{VL}{Voc} = \frac{1}{1+Rs/RL}

If the allowable fractional droop is ε, then:

Rs \leq \frac{ε}{1-ε}RL

For a 1% maximum droop into 10 kΩ:

Rs ≤ (0.01/0.99)(10\,kΩ) = 101\,Ω

Consequently, increasing divider resistances increases source resistance and worsens loading. Smaller divider resistances reduce loading, though they increase source-current consumption. A buffer, such as a voltage follower with adequate input impedance and output-current capability, can provide a high-input-impedance/low-output-impedance interface.

Loading is also relevant to oscilloscopes, probes, ADC inputs, amplifier stages, and sensor interfaces. A 1× oscilloscope probe may present roughly 1 MΩ in parallel with substantial capacitance, while a 10× probe generally presents much lower capacitance and is preferred for higher-frequency measurements. Exact specifications must be checked for the instrument being used.

6. Decibels and Gain

For a power ratio:

GdB = 10\log10\left(\frac{P2}{P1}\right)

For voltage ratios, the familiar expression is:

GdB = 20\log10\left|\frac{V2}{V1}\right|

This voltage formula assumes equal impedances, or more generally that the impedance factor has been accounted for. If impedances differ, power must be calculated explicitly using P = Vrms2/R for a resistance or the appropriate complex-power relationship.

A gain of 0 dB means equal power, not necessarily zero voltage. A voltage ratio of 2 gives approximately 6.02 dB; a ratio of 0.5 gives approximately −6.02 dB. The half-power point corresponds to approximately −3.01 dB.

7. Tolerance, Uncertainty, and Engineering Decisions

Component tolerance describes permissible manufacturing variation from a nominal value. A 1 kΩ resistor with ±1% tolerance may lie between 990 Ω and 1010 Ω. Tolerance is not automatically a standard uncertainty. To convert it into a standard uncertainty, an assumed probability distribution must be stated.

If the actual value is assumed uniformly distributed over ±a, the standard uncertainty is:

u = \frac{a}{√3}

For a 1 kΩ, ±1% resistor, a = 10\,Ω, so:

uR = 10/√3 = 5.77\,Ω

This is a Type B standard uncertainty based on a rectangular distribution assumption. If the manufacturer specifies a different distribution or if calibration data are available, that information should be used instead.

For independent input quantities in a result y = f(x1,x2,...):

uc(y) = √{\sumi\left(\frac{∂f}{∂xi}u(xi)\right)2}

This law of propagation of uncertainty is appropriate when a first-order approximation is adequate and correlations are either negligible or separately included. An expanded uncertainty is often reported as U = kuc, where k is a coverage factor selected for the reporting convention.

Worked Example 4: Divider Uncertainty

Consider Vo = VsR2/(R1+R2), with Vs = 5.00 V, R1 = R2 = 10.0 kΩ. The nominal output is 2.50 V. Suppose each resistor has an independent ±1% tolerance and each tolerance is modeled as uniform. Then each resistance has standard uncertainty 57.7 Ω. Sensitivity to either resistor has magnitude:

|∂Vo/∂R1| = |∂Vo/∂R2| = VsR/(2R)2 = 5/(4R) = 0.000125 V/Ω

The resistance-related standard uncertainty is therefore:

uR(Vo) = √2(0.000125)(57.7) = 0.0102 V

This result is a standard uncertainty under the stated uniform-distribution assumption, not a guaranteed maximum error. Worst-case tolerance analysis would instead evaluate extreme combinations and would give a different result.

8. Laboratory Instruments and Safe Measurement

Digital Multimeter

A multimeter measures voltage, current, resistance, and often frequency or capacitance. Voltage is measured in parallel; current is measured in series. Connecting an ammeter directly across a voltage source can produce a short circuit and damage the meter, circuit, or user. Before measuring resistance, remove power from the circuit and discharge capacitors.

Check lead placement, range, category rating, fuse condition, and polarity. A meter’s finite input resistance can load a high-resistance circuit. Auto-ranging is convenient, but manual range selection can improve stability and prevent unexpected range changes.

Oscilloscope

An oscilloscope displays voltage versus time. Important settings include volts/division, seconds/division, coupling, trigger level, probe attenuation, bandwidth limit, and input impedance. DC coupling displays the DC level and AC variation; AC coupling blocks the DC component but can distort very low-frequency signals.

Most bench oscilloscope probe ground clips are connected to protective earth. Never attach the ground clip to a point that is not earth-referenced unless an appropriately rated differential probe or isolated measurement system is used. Grounding an energized mains conductor through a standard probe can cause a short circuit and severe hazard.

The measured rise time is affected by instrument bandwidth. For approximately Gaussian response, a common engineering estimate is:

tr,meas ≈ √{tr,signal2+tr,scope2}

This is an approximation, not a universal identity. Probe capacitance can also alter the circuit being measured.

Function Generator

A function generator supplies waveforms such as sine, square, and triangle signals. Verify amplitude convention: some instruments specify amplitude into 50 Ω, while a high-impedance load may receive approximately twice the displayed voltage if the generator is calibrated for a matched load. Confirm offset, frequency, duty cycle, output termination, and maximum allowable input voltage.

Laboratory Power Supply

Set current limits before connecting the load. Begin with output disabled or voltage at a low value where practical. Confirm polarity and wiring, then increase voltage gradually while monitoring current. A current limit is a protective control, not a substitute for correct circuit design.

A Safe Measurement Sequence

Safe electronic measurement workflow Inspectcircuit and ratings Configurelimits and probes Connectwith power off Power and verifyobserve safely Measurement discipline Record instrument settings, units, uncertainty, and unexpected behavior.
Safe electronic measurement workflow
Figure: Safe electronic measurement workflow

Figure: A safe and repeatable sequence for electronic measurement.

9. Applied Case: Designing a Sensor Interface

Background

An illustrative sensor produces 0–5 V through a resistive divider with 100 kΩ and 100 kΩ resistors. Its output feeds an ADC input modeled as 10 kΩ. The design requirement is to preserve the sensor voltage with less than 1% loading error.

Problem

The initial design uses 100 kΩ resistors. Its Thévenin resistance is:

Rth = 100\,kΩ \parallel 100\,kΩ = 50\,kΩ

With a 10 kΩ ADC input, the retained fraction is:

VL/Voc = 10/(50+10) = 0.1667

The ADC receives only 16.7% of the intended open-circuit voltage, so the design is unacceptable.

Analysis and Solution

One solution is to reduce both divider resistors to 1.0 kΩ. Then:

Rth = 1.0\,kΩ \parallel 1.0\,kΩ = 500 Ω

The retained fraction becomes:

10\,kΩ/(10\,kΩ+0.5\,kΩ) = 0.9524

This still produces a 4.76% error, because the ADC input is not sufficiently large compared with the source resistance. To meet a 1% requirement, the divider’s Thévenin resistance must satisfy approximately 101 Ω or less for a 10 kΩ load. Choosing 100 Ω for each divider resistor gives:

Rth = 50 Ω

and the retained fraction is:

10,000/(10,000+50) = 0.9950

or a 0.50% loading error. However, the divider now draws 5 V/(200 Ω) = 25 mA, which may be excessive for a sensor or battery-powered system.

A better practical solution may use moderate resistor values followed by a unity-gain buffer. For example, 10 kΩ and 10 kΩ produce Rth=5 kΩ, but a buffer with sufficiently high input impedance and low output impedance isolates the divider from the ADC. The buffer must be checked for input common-mode range, output swing, stability, bandwidth, supply voltage, and ADC drive requirements.

Outcome and Learning Points

The original high-resistance divider failed because its Thévenin resistance was large relative to the ADC input. Reducing divider resistance reduces loading but increases current consumption. Buffering reduces loading without requiring very low divider resistance, but introduces active-device limitations, power consumption, offset, noise, and possible stability concerns. Loading must therefore be evaluated at the interface, not only in the source circuit.

10. Professional Practice, Limitations, and Contemporary Tools

Engineering calculations should state assumptions, reference directions, units, significant figures, and uncertainty. A result that lacks these details may be numerically correct but professionally weak. Datasheets should be consulted for absolute maximum ratings, operating conditions, input capacitance, bandwidth, accuracy, and calibration information.

Computer algebra, circuit simulators, spreadsheets, and AI-assisted tools can accelerate analysis, but they do not replace physical reasoning. A simulation model may omit parasitic capacitance, temperature dependence, noise, saturation, grounding, or instrument loading. Engineers must independently check polarity, limiting cases, dimensions, and plausibility. AI-generated technical suggestions require verification against authoritative datasheets, standards, and laboratory safety procedures.

Important limitations include:

  • Kirchhoff circuit models assume lumped behavior and may fail when conductor dimensions become electrically large.
  • Ideal sources, switches, capacitors, inductors, and op-amps are approximations.
  • Phasor methods describe sinusoidal steady state, not arbitrary transients.
  • Tolerance limits do not by themselves specify probability distributions.
  • Measurement accuracy depends on calibration, setup, bandwidth, loading, noise, and operator technique.
  • A nominally correct circuit may still be unsafe if energy storage, fault current, insulation, or grounding is neglected.

Chapter Summary

Voltage represents energy per unit charge, current represents charge flow, power is the product of voltage and current, and energy is the time integral of power. KCL and KVL express conservation of charge and energy in lumped circuits. Series and parallel reduction, divider rules, Thévenin and Norton equivalents, and superposition provide efficient methods for linear-network analysis.

Impedance extends resistance to sinusoidal steady-state analysis. Resistors, inductors, and capacitors produce distinct magnitude and phase relationships, and phasor calculations must use consistent RMS or peak conventions. Loading is governed by the ratio of source impedance to load impedance; smaller source resistance or buffering improves voltage transfer. Decibels express ratios logarithmically, with the voltage formula requiring appropriate impedance assumptions.

Tolerance describes component variation, whereas uncertainty quantifies incomplete knowledge. A tolerance becomes a standard uncertainty only after a probability distribution or equivalent interpretation is specified. Safe laboratory practice requires correct instrument connections, awareness of grounding and bandwidth, current limiting, suitable probes, and careful documentation. These foundations support later study of amplifiers, filters, oscillators, digital interfaces, and electronic systems.

Key Terms

Voltage: Energy transferred per unit charge, measured in volts.

Current: Rate of charge flow, measured in amperes.

Power: Rate of energy transfer, measured in watts.

Energy: Accumulated power over time, measured in joules.

Passive sign convention: Reference convention in which current enters the positive-voltage terminal.

KCL: Kirchhoff’s current law; algebraic current sum at a node is zero.

KVL: Kirchhoff’s voltage law; algebraic voltage sum around a closed path is zero.

Impedance: Complex ratio of phasor voltage to phasor current.

Phasor: Complex representation of sinusoidal magnitude and phase.

Reactance: Imaginary component of impedance.

Thévenin equivalent: Voltage source in series with an equivalent impedance.

Norton equivalent: Current source in parallel with an equivalent impedance.

Loading: Change in source output caused by connection of a finite input impedance.

Tolerance: Permitted manufacturing deviation from a nominal component value.

Standard uncertainty: Uncertainty expressed as a standard deviation or equivalent quantity.

Decibel: Logarithmic measure of a power or amplitude ratio.

Bandwidth: Frequency range over which a system or instrument meets specified behavior.

RMS value: Root-mean-square value representing equivalent heating or power for a resistor.

Buffer: Circuit, commonly a voltage follower, that provides high input impedance and low output impedance.

Review Questions

Short Answer Questions

  1. Define voltage, current, power, and energy, including their SI units.
  2. State Kirchhoff’s current law and explain the conservation principle behind it.
  3. Under what conditions may the simple two-resistor voltage-divider equation be used?
  4. What is the difference between component tolerance and standard uncertainty?
  5. Why can an oscilloscope ground clip create a hazard in a mains-referenced circuit?

Long Answer Questions

  1. Derive the loaded voltage-divider equation using a Thévenin equivalent and discuss the design trade-off between divider current and loading error.
  2. Explain Thévenin’s and Norton’s theorems, including source deactivation rules and the treatment of dependent sources.
  3. Develop the impedance expressions for an ideal resistor, inductor, and capacitor, and explain their phase relationships.
  4. Explain decibel voltage and power ratios, including the conditions under which 20 log₁₀ voltage ratio is valid.
  5. Describe a complete laboratory procedure for measuring the output of a function-generator-driven RC circuit with a multimeter and oscilloscope.

Analytical / Application Questions

  1. A 12 V source has a 150 Ω source resistance and drives a 1.0 kΩ load. Calculate the load voltage, source current, and load power. Determine the percentage voltage droop relative to the open-circuit voltage.
  2. A 5 V, 2 kHz RMS source drives a series circuit containing 2.0 kΩ and 47 nF. Calculate the capacitor reactance, total impedance in rectangular form, RMS current magnitude, and current phase relative to the source.
  3. Design a resistive divider for a 10 kΩ ADC input with no more than 1% loading error. State a suitable maximum Thévenin resistance, discuss at least two resistor choices, and evaluate the current-consumption trade-off.

Multiple Choice Questions with Answers

Question 1

A 12 V source is connected to a 240 Ω resistor. What is the resistor power?

A. 0.05 W

B. 0.60 W

C. 2.88 W

D. 50 W

Correct Answer: B. 0.60 W

Question 2

Which action deactivates an ideal independent voltage source for finding Thévenin resistance?

A. Replace it with an open circuit

B. Replace it with a resistor equal to its voltage

C. Replace it with a short circuit

D. Remove all dependent sources

Correct Answer: C. Replace it with a short circuit

Question 3

A 10 kΩ load is connected to a source with 100 Ω series resistance. What fraction of the open-circuit voltage appears across the load?

A. 0.010

B. 0.500

C. 0.990

D. 1.010

Correct Answer: C. 0.990

Question 4

For a capacitor, the ideal impedance is:

A. jωC

B. 1/(jωC)

C. R + jωC

D. ω/C

Correct Answer: B. 1/(jωC)

Question 5

In the series RC example with R=1.0\,kΩ, C=100\,nF, and f=1\,kHz, the approximate impedance phase is:

A. +57.9°

B. −57.9°

C. +32.1°

D. −32.1°

Correct Answer: B. −57.9°

Question 6

A 1 kΩ resistor has a ±1% tolerance modeled as a uniform distribution. Its standard uncertainty is approximately:

A. ±10 Ω

B. 5.77 Ω

C. 1 Ω

D. 17.3 Ω

Correct Answer: B. 5.77 Ω

Question 7

Which instrument connection is normally correct for measuring current through a component?

A. Connect the ammeter in parallel with the supply

B. Connect the ammeter in series with the component

C. Connect the voltmeter in series with the component

D. Connect the resistance range across a powered circuit

Correct Answer: B. Connect the ammeter in series with the component

Question 8

The voltage-gain expression 20log10|V2/V1| is directly valid when:

A. The two voltages have equal phase only

B. The circuit contains no capacitors

C. The relevant impedances are equal or their effect is otherwise accounted for

D. The output voltage is always larger than the input

Correct Answer: C. The relevant impedances are equal or their effect is otherwise accounted for

Question 9

For maximum average power transfer from a network with Thévenin impedance Zth, the load impedance should be:

A. Zth

B. −Zth

C. Zth^*

D. Zero

Correct Answer: C. Zth^*

Question 10

Why is a voltage buffer useful between a divider and a 10 kΩ ADC input?

A. It increases the divider’s Thévenin resistance

B. It isolates the divider by providing high input impedance and low output impedance

C. It guarantees zero measurement uncertainty

D. It converts every analog signal into a digital signal

Correct Answer: B. It isolates the divider by providing high input impedance and low output impedance

Analog & Digital Electronics
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