Analog & Digital Electronics

Chapter 3
Diodes and Application Circuits

Bachelors Program in Electrical Engineering
Analog & Digital Electronics   •   Bachelor

Diodes and Application Circuits

Introduction

A diode is a two-terminal semiconductor device that conducts preferentially in one direction. This apparently simple property enables the conversion of alternating current (AC) to direct current (DC), waveform shaping, voltage regulation, optical emission and detection, and protection against abnormal voltages. In practical engineering, diode circuits must be evaluated not only for their ideal function but also for forward voltage, reverse leakage, reverse breakdown, switching speed, power dissipation, ripple, temperature and component tolerances.

This chapter develops diode models and applies them to rectifiers, filters, clippers, clampers, voltage multipliers, Zener regulators, optoelectronic devices and protection circuits.

Learning Objectives

By the end of this chapter, the reader should be able to:

  1. Explain diode operation and select an appropriate diode model.
  2. Analyze half-wave, full-wave and bridge rectifiers.
  3. Calculate ripple, efficiency, peak inverse voltage and filter requirements.
  4. Design clipper, clamper and voltage-multiplier circuits.
  5. Design a Zener shunt regulator subject to line, load and thermal limits.
  6. Explain the operating principles and applications of LEDs and photodiodes.
  7. Select diode protection networks for inductive loads and transient voltages.
  8. Account for switching behavior, breakdown and temperature in practical designs.

1. Semiconductor Diode Fundamentals

A p–n junction is formed by joining p-type and n-type semiconductor regions. Carrier diffusion near the junction creates a depletion region and an internal electric field. With forward bias, the depletion barrier is reduced and substantial current flows. With reverse bias, the depletion region widens and only a small leakage current flows until breakdown occurs.

The ideal diode has zero voltage drop when forward-biased and zero current when reverse-biased. A more useful constant-voltage model represents a silicon diode by a forward drop of approximately 0.7 V at moderate current. This value is an approximation, not a universal constant; power diodes, Schottky diodes and LEDs have different forward voltages.

The exponential diode equation is

ID = IS [eVD/(nVT) − 1]

where ID is diode current in amperes, IS is reverse saturation current, VD is diode voltage, n is the emission coefficient (approximately 1 to 2), and VT is thermal voltage. At temperature T,

VT = kT/q

where k is Boltzmann’s constant and q is electronic charge. At room temperature, VT is approximately 25.9 mV. The equation applies to a junction in the appropriate exponential operating region and neglects high-level injection, series resistance and breakdown.

The small-signal or dynamic resistance at a specified operating point is

rd ≈ nVT/ID

where ID is the DC operating current. Thus, a diode’s incremental resistance decreases as its forward current increases.

Reverse Breakdown

If reverse voltage exceeds the breakdown voltage, current rises sharply. Zener breakdown is dominant at lower breakdown voltages, whereas avalanche breakdown is associated with carrier multiplication at higher voltages. Breakdown is not necessarily destructive if current is limited and power remains within the rated value. The maximum reverse voltage that a diode can repeatedly withstand is specified by its peak repetitive reverse voltage or maximum reverse voltage rating.

Temperature and Thermal Limits

Forward voltage generally decreases with increasing junction temperature for ordinary silicon diodes, while leakage current increases strongly. Device power is

PD = VD ID

and the junction temperature can be estimated by

TJ = TA + PD θJA

where TJ is junction temperature, TA is ambient temperature, and θJA is junction-to-ambient thermal resistance in °C/W. The estimate assumes steady-state operation and a known thermal environment. Safe design requires TJ to remain below the manufacturer’s maximum rating, with appropriate derating.

2. Rectifier Circuits

A rectifier converts AC into unidirectional, pulsating voltage. A capacitor or other filter can then reduce the alternating component.

Half-Wave Rectifier

A half-wave rectifier uses one diode and conducts during one half-cycle. For an ideal diode and sinusoidal input with peak value Vm, the average output is

VDC = Vm/π

The root-mean-square output is

Vrms = Vm/2

The rectification efficiency, defined as DC load power divided by AC input power, has an ideal maximum of approximately 40.6%. The ripple frequency equals the source frequency f. A practical silicon diode reduces the output peak approximately to Vm − VF, where VF is the forward drop.

Full-Wave Rectifier

A center-tapped full-wave rectifier uses two diodes and a center-tapped transformer. Each diode conducts on alternate half-cycles. An ideal full-wave output has

VDC = 2Vm/π

where Vm is the peak voltage applied to the conducting half-secondary. Its ripple frequency is 2f, and ideal rectification efficiency is approximately 81.2%. The peak inverse voltage (PIV) of each diode is approximately 2Vm for the center-tapped configuration.

Bridge Rectifier

A bridge rectifier uses four diodes. Two conduct during each half-cycle, so the load polarity remains constant without a center-tapped transformer. If the source peak is Vm, the approximate peak load voltage is

Vo,peak ≈ Vm − 2VF

The PIV requirement for each diode is approximately Vm, which is lower than that of the center-tapped circuit for the same transformer secondary peak. The disadvantage is the presence of two forward drops in the conducting path.

Worked Example 1: Bridge Rectifier

A bridge rectifier is supplied by a 12 V rms secondary at 50 Hz. Assume silicon diodes with VF = 0.8 V. Determine the approximate peak output and ripple frequency.

The secondary peak is

Vm = √2 Vrms = 1.414 × 12 = 16.97 V

Two diodes conduct, so

Vo,peak ≈ 16.97 − 1.6 = 15.37 V

The ripple frequency is

fr = 2f = 2 × 50 = 100 Hz

The result is an unloaded or lightly loaded estimate; transformer regulation, diode resistance and capacitor loading will reduce the actual voltage.

3. Capacitor Filters and Ripple

A capacitor-input filter is connected across the rectifier load. The capacitor charges near the input peaks and discharges through the load between peaks. For a full-wave rectifier, the discharge interval is approximately one ripple period, 1/(2f). For relatively small ripple, the peak-to-peak ripple is

Vr(pp) ≈ IL/(fr C)

where IL is load current, C is capacitance, and fr is ripple frequency. For a full-wave rectifier, fr = 2f; for a half-wave rectifier, fr = f. The approximation assumes a large capacitance, small ripple and nearly constant load current.

The rms ripple for an approximately triangular ripple waveform is

Vr(rms) ≈ Vr(pp)/(2√3)

The ripple factor is

r = Vr(rms)/VDC

A larger capacitor, higher ripple frequency or smaller load current reduces ripple. However, a larger capacitor increases charging-current pulses, diode stress, electromagnetic interference and transformer peak current.

Worked Example 2: Filter Capacitor

A full-wave bridge supplies 100 mA from a 60 Hz source. The permitted peak-to-peak ripple is 1.0 V. The required minimum capacitance is

C ≥ IL/(fr Vr(pp)) = 0.1/(120 × 1.0) = 833 μF

A practical design would select the next standard value, such as 1,000 μF, while checking ripple-current rating, voltage rating, inrush current and temperature life.

4. Clippers and Clampers

Clippers

A clipper removes or limits part of a waveform. A series clipper places the diode in series with the load; a shunt clipper places it in parallel with the load. Bias sources can establish a clipping level other than zero.

For a positive shunt clipper using a diode that conducts when the input exceeds a reference, the output is limited approximately to

Vclip ≈ VR + VF

where VR is the bias reference with the correct polarity. Practical clipping levels depend on diode current, dynamic resistance and source resistance. Two-diode arrangements can independently limit positive and negative excursions and are widely used in input protection.

Clampers

A clamper adds a DC level to an AC waveform while ideally preserving its peak-to-peak amplitude. It consists of a diode, capacitor and resistor. During one half-cycle, the diode conducts and charges the capacitor; during the opposite half-cycle, the stored capacitor voltage shifts the waveform.

For satisfactory clamping, the capacitor discharge time constant should be much longer than the signal period:

RL C ≫ T

where RL is the effective discharge resistance and T is signal period. If the input has peak-to-peak amplitude Vpp, the ideal output retains approximately Vpp, but its average level is shifted by the capacitor’s stored voltage. Diode forward drop and load-dependent droop cause practical error.

5. Voltage Multipliers

Voltage multipliers use diode-capacitor networks to obtain a DC voltage greater than the peak of an AC source. A voltage doubler ideally produces approximately 2Vm under light load, although diode drops, capacitor ripple and source resistance reduce this value. Tripler and quadrupler circuits extend the principle.

Multiplier circuits are useful where current demand is small, such as high-voltage bias supplies, cathode-ray equipment and some sensors. They are unsuitable for high-current loads because output regulation is poor and capacitor charging currents can be substantial. Insulation, creepage, clearance and discharge provisions are essential because a multiplier can retain a dangerous charge after power is removed.

6. Zener Diode Regulators

A Zener diode is operated in reverse breakdown to provide an approximately constant voltage. A simple shunt regulator uses a series resistor to limit current and a Zener connected in parallel with the load.

For a supply VS, series resistor RS, Zener voltage VZ and load current IL, the resistor current is approximately

IS = (VS − VZ)/RS

and the Zener current is

IZ = IS − IL

Regulation requires

IZ,min ≤ IZ ≤ IZ,max

where IZ,min is the minimum current needed to remain in the regulation region and IZ,max is limited by the power rating:

IZ,max = PZ,max/VZ

The resistor must satisfy both line and load extremes. At minimum supply and maximum load, the Zener must still have at least IZ,min. At maximum supply and minimum load, its power must remain below the permitted value.

Worked Example 3: Zener Design

Design a nominal 5.1 V shunt regulator from a 12 V supply for a load varying from 20 mA to 60 mA. Let IZ,min = 5 mA, and select a 0.5 W Zener.

At maximum load, the series current must be at least 65 mA. Therefore,

RS ≤ (12 − 5.1)/(0.065) = 106.2 Ω

Choose 100 Ω. At maximum load,

IS = (12 − 5.1)/100 = 69 mA

and

IZ = 69 − 60 = 9 mA

Thus regulation is maintained under the stated nominal conditions. At 20 mA load,

IZ = 69 − 20 = 49 mA

and Zener power is

PZ = 5.1 × 0.049 = 0.25 W

which is below 0.5 W. A complete design must repeat the calculation for the actual supply tolerance, temperature and Zener tolerance. A linear regulator or switching regulator is usually more efficient when load current is significant because a Zener regulator continuously dissipates excess power.

7. LEDs, Laser Diodes and Photodiodes

Light-Emitting Diodes

An LED emits photons when electrons and holes recombine in a forward-biased semiconductor junction. Its forward voltage depends on semiconductor material, wavelength and current; red LEDs commonly require less forward voltage than blue or white LEDs. An LED must normally be driven with controlled current.

For a supply VS, LED drop VF and desired current IF, a series resistor is approximately

R = (VS − VF)/IF

The resistor dissipates

PR = IF2 R

and the LED dissipates approximately PLED = VF IF. Pulse operation may permit higher current, but only within the manufacturer’s pulse-width and duty-cycle limits. LEDs are used in indicators, displays, communication links, solid-state lighting and isolation devices.

Photodiodes

A photodiode converts incident light into photocurrent. It may operate in photovoltaic mode with no external bias or in photoconductive mode with reverse bias. Reverse bias reduces junction capacitance and improves speed, but increases dark current and noise. In a sensor circuit, the output may be developed across a resistor or converted by a transimpedance amplifier.

Important specifications include responsivity, dark current, junction capacitance, spectral response, noise and maximum reverse voltage. Ambient light shielding, optical filtering and calibration are often necessary for reliable measurement.

8. Switching Behavior and Protection Circuits

A diode is not an instantaneous switch. When a forward-biased diode is suddenly reverse-biased, stored charge must be removed. The resulting reverse-recovery current may cause voltage spikes, electromagnetic interference and switching loss. Fast-recovery, ultrafast or Schottky diodes are selected when switching frequency or efficiency requires them.

A flyback diode is connected across a relay coil, motor winding or solenoid. When the switching transistor turns off, the inductive current continues through the diode rather than forcing a destructive voltage across the transistor. The diode slows current decay, so applications requiring rapid release may use a Zener clamp, TVS diode or diode-Zener combination.

A transient-voltage-suppression (TVS) diode clamps short-duration surges. Selection requires attention to standoff voltage, breakdown voltage, clamping voltage, peak pulse current and pulse power. A diode connected in series can provide reverse-polarity protection, although it causes a forward-voltage loss. A P-channel MOSFET or ideal-diode controller can reduce this loss in efficient systems.

Protection components must be placed physically close to the protected device, with short, low-inductance conductors. Otherwise, wiring inductance can produce a transient before the protection device conducts effectively.

9. Design Case: Protected DC Sensor Supply

The following is an illustrative engineering case. A field sensor requires 5 V at 40 mA from an unregulated 9–15 V DC source. The input may be connected backward, and an inductive cable can generate short positive transients.

Problem

A design using only a resistor and Zener must maintain the sensor voltage, prevent damage during reverse connection and absorb input transients without exceeding thermal limits.

Analysis

A 5.1 V Zener shunt regulator would dissipate substantial power at high input voltage. At 15 V, even with a 40 mA load, the resistor and Zener must absorb the excess voltage. A simple series diode protects against reverse polarity but wastes approximately 0.7 V and may dissipate significant power.

Approach

A robust solution uses a low-loss reverse-polarity MOSFET arrangement, a TVS diode selected for a standoff voltage above 15 V, input filtering, and a 5 V integrated regulator. The regulator’s input-voltage and thermal ratings are checked at the maximum clamped voltage. If a Zener shunt is used instead, the resistor is selected from the minimum input and maximum load condition, then verified at maximum input and minimum load for Zener power.

Outcome

The protected design provides better efficiency and more predictable transient performance than an unqualified Zener circuit. The TVS must be coordinated with the source impedance and fuse or current limiter; a TVS alone is not a substitute for overcurrent protection.

Learning Points

Protection design is a system problem. The diode’s voltage, current and energy ratings, layout inductance, thermal path, source impedance and failure mode must all be considered. A component that survives a nominal calculation may still fail under repetitive pulses or poor cooling.

10. Design Practice, Limitations and Contemporary Developments

Good diode design begins with worst-case conditions rather than nominal values. Verify forward current, reverse voltage, surge current, leakage, switching frequency, power, junction temperature and physical spacing. Use manufacturer curves instead of assuming a fixed forward voltage when accuracy matters. Include tolerance, aging and temperature in safety margins.

Schottky diodes provide low forward voltage and fast switching but generally have higher reverse leakage and lower reverse-voltage ratings than comparable silicon junction diodes. Silicon-carbide Schottky diodes support high voltage, high temperature and high-frequency power conversion with negligible reverse recovery, although their cost is higher. Wide-bandgap devices are increasingly important in electric vehicles, renewable-energy converters and high-density power supplies.

In safety-critical products, protection circuits should be analyzed for open-circuit and short-circuit failures. Compliance may involve insulation, creepage, clearance, electromagnetic compatibility and product-specific standards. Engineers must not rely on a diode’s typical specification where a maximum or minimum rating is required.

Chapter Summary

Diodes are nonlinear semiconductor devices whose controlled conduction enables rectification, waveform shaping, regulation, optical conversion and protection. The exponential diode equation describes junction behavior, while constant-voltage and piecewise-linear models simplify circuit analysis. Half-wave, full-wave and bridge rectifiers differ in average output, ripple frequency, efficiency and PIV. Capacitor filters reduce ripple according to load current, capacitance and ripple frequency, but increase charging-current stress.

Clippers limit waveform amplitude, whereas clampers shift its DC level. Voltage multipliers generate high voltage at low current and require careful insulation and discharge design. Zener regulators maintain approximate voltage by diverting current, but their resistor, current and thermal limits must be checked at worst-case supply and load conditions. LEDs require current control, and photodiodes convert light into current with a trade-off among speed, sensitivity, capacitance and noise. Fast-recovery diodes, flyback paths and TVS devices protect switching circuits, provided that their transient, thermal and layout requirements are satisfied.

Key Terms

Diode: Two-terminal semiconductor device that conducts preferentially in one direction.

P–N junction: Interface between p-type and n-type semiconductor regions.

Forward bias: Bias condition that promotes diode conduction.

Reverse bias: Bias condition that suppresses normal diode conduction.

Depletion region: Carrier-depleted region surrounding a p–n junction.

Breakdown: Region of sharp reverse-current increase.

PIV: Peak inverse voltage a diode must withstand in reverse bias.

Rectifier: Circuit that converts AC into unidirectional output.

Ripple: AC component remaining in a rectified DC waveform.

Clipper: Circuit that limits part of a waveform.

Clamper: Circuit that shifts a waveform’s DC level.

Voltage multiplier: Diode-capacitor network producing voltage above the AC peak.

Zener diode: Diode designed to operate in controlled reverse breakdown.

LED: Light-emitting diode that converts electrical energy into light.

Photodiode: Semiconductor device that converts light into photocurrent.

Reverse recovery: Time required for a conducting diode to stop conducting after reverse bias is applied.

TVS diode: Diode designed to clamp short-duration voltage transients.

Thermal resistance: Temperature rise per unit dissipated power, measured in °C/W.

Review Questions

Short Answer Questions

  1. Why does a bridge rectifier require two diode forward drops during conduction?
  2. Define peak inverse voltage and explain its importance in rectifier design.
  3. State the assumptions behind the capacitor-filter ripple approximation.
  4. Why must an LED normally be operated with current limiting?
  5. What is the purpose of a flyback diode across an inductive load?

Long Answer Questions

  1. Compare half-wave, center-tapped full-wave and bridge rectifiers in terms of conduction, ripple frequency, efficiency and PIV.
  2. Explain the operation of a biased clipper and a clamper, including the role of the capacitor time constant.
  3. Derive the design inequalities for a Zener shunt regulator under minimum-input maximum-load and maximum-input minimum-load conditions.
  4. Discuss photodiode photovoltaic and photoconductive modes, including speed, bias, noise and capacitance.
  5. Explain diode switching behavior and compare ordinary, fast-recovery, Schottky and TVS diodes in practical applications.

Analytical / Application Questions

  1. A 24 V rms transformer feeds a bridge rectifier and capacitor filter supplying 0.20 A at 100 Hz. Estimate the capacitor required for 2 V peak-to-peak ripple, ignoring diode drops, and state two practical checks that must follow.
  2. Design a 9.1 V Zener regulator from a 15 V nominal source for a 25–75 mA load, assuming a specified minimum Zener current of 5 mA. Explain how source tolerance and Zener power could change the resistor selection.
  3. A microcontroller drives a relay from a transistor. Analyze the failure mechanism that may occur when the transistor turns off and propose a protection circuit for both ordinary slow release and rapid release requirements.

Multiple Choice Questions with Answers

Question 1

For an ideal full-wave rectifier supplied by a sinusoid of peak voltage Vm, the average output voltage is:

A. Vm/π

B. 2Vm/π

C. Vm/2

D. πVm/2

Correct Answer: B. 2Vm/π

Question 2

A 60 Hz source is connected to a full-wave bridge rectifier. What is the principal ripple frequency before filtering?

A. 30 Hz

B. 60 Hz

C. 120 Hz

D. 240 Hz

Correct Answer: C. 120 Hz

Question 3

A capacitor-filtered full-wave rectifier supplies 0.10 A at 120 Hz. Approximately what capacitance gives 1 V peak-to-peak ripple?

A. 83 μF

B. 833 μF

C. 1.2 mF

D. 12 mF

Correct Answer: B. 833 μF

Question 4

In a bridge rectifier, how many diodes normally conduct during each half-cycle?

A. One

B. Two

C. Three

D. Four

Correct Answer: B. Two

Question 5

The Zener current in a simple shunt regulator is approximately:

A. IS + IL

B. IL − IS

C. IS − IL

D. VZ/RL only

Correct Answer: C. IS − IL

Question 6

What is the main purpose of a series resistor in an LED circuit?

A. To increase reverse breakdown voltage

B. To limit forward current

C. To convert light into current

D. To eliminate all power dissipation

Correct Answer: B. To limit forward current

Question 7

A clamper primarily performs which function?

A. It increases signal frequency

B. It shifts the waveform’s DC level

C. It converts DC into three-phase AC

D. It removes all harmonics

Correct Answer: B. It shifts the waveform’s DC level

Question 8

Which device is specifically intended to clamp short-duration voltage transients?

A. TVS diode

B. Photodiode

C. Rectifier transformer

D. Thermistor only

Correct Answer: A. TVS diode

Question 9

If a diode carries 0.050 A with a forward voltage of 0.80 V, its approximate power dissipation is:

A. 0.016 W

B. 0.040 W

C. 0.80 W

D. 16 W

Correct Answer: B. 0.040 W

Question 10

Why is a flyback diode connected across a relay coil?

A. To increase coil inductance indefinitely

B. To provide a path for inductive current when switching off

C. To make the coil conduct only in reverse bias

D. To eliminate the need for a transistor

Correct Answer: B. To provide a path for inductive current when switching off

Analog & Digital Electronics
Chapter 3 of 15