Advanced Fluid Mechanics

Chapter 2
Fluid Kinematics and Conservation Laws

Post Graduate Program in Mechanical Engineering
Advanced Fluid Mechanics   •   Post Graduate

Fluid Kinematics and Conservation Laws

Introduction

Fluid mechanics is commonly divided into fluid statics, fluid kinematics, and fluid dynamics. Fluid statics concerns fluids at rest; fluid dynamics relates motion to forces; fluid kinematics describes motion without initially asking what forces cause it. Kinematics supplies the language needed to formulate the conservation of mass, momentum, and energy in a fluid.

At postgraduate level, fluid kinematics is important because industrial flows are rarely steady, one-dimensional, or inviscid. Turbomachinery passages, reacting flows, atmospheric motion, microfluidic devices, and computational fluid dynamics (CFD) all require a precise distinction between local and convective changes, material and control-volume descriptions, and Eulerian and Lagrangian viewpoints.

The conservation laws provide the bridge between a moving continuum and engineering predictions. Their integral forms are particularly useful for control-volume analysis, while their differential forms are central to field equations and numerical simulation.

Learning Objectives

After studying this chapter, the reader should be able to:

  1. Distinguish Lagrangian and Eulerian descriptions of fluid motion.
  2. Calculate velocity, acceleration, deformation, rotation, and vorticity from a velocity field.
  3. Interpret streamlines, pathlines, streaklines, and stream surfaces.
  4. Derive and apply the continuity equation.
  5. Formulate linear-momentum and angular-momentum equations for a control volume.
  6. Apply the first law of thermodynamics to flowing fluids.
  7. Identify assumptions behind steady-flow, incompressible, inviscid, and one-dimensional models.
  8. Evaluate the limitations of conservation-law models in real engineering systems.

1. Describing Fluid Motion

1.1 The continuum assumption

A fluid is treated as a continuum when molecular-scale fluctuations are replaced by smooth fields such as density, pressure, temperature, and velocity. The assumption is appropriate when the characteristic length of the system is much larger than the molecular mean free path. Its validity is often assessed using the Knudsen number,

Kn = λm / L

where λm is the molecular mean free path and L is a characteristic length. Continuum descriptions are generally reliable for Kn ≪ 1. Rarefied-gas flows require kinetic theory or hybrid continuum–molecular methods.

A velocity field is written as

V(x,y,z,t) = u i + v j + w k

where u, v, and w are velocity components in m/s, i, j, and k are Cartesian unit vectors, and t is time in seconds.

1.2 Lagrangian and Eulerian descriptions

In the Lagrangian description, an individual fluid particle is followed. Its position is represented as

x = x(a,b,c,t), y = y(a,b,c,t), z = z(a,b,c,t)

where (a,b,c) labels the particle. This description is natural for particle tracking and free-surface problems, but it becomes difficult when a very large number of particles are involved.

In the Eulerian description, properties are specified at fixed locations:

V = V(x,y,z,t), ρ = ρ(x,y,z,t), p = p(x,y,z,t)

Most analytical fluid mechanics and CFD uses the Eulerian description. The two descriptions are connected by the material derivative.

1.3 Material derivative

For any scalar field φ(x,y,z,t), the rate of change experienced by a fluid particle is

Dφ/Dt = ∂φ/∂t + V · ∇φ

or, in Cartesian coordinates,

Dφ/Dt = ∂φ/∂t + u ∂φ/∂x + v ∂φ/∂y + w ∂φ/∂z

The first term is the local derivative, representing change at a fixed point. The remaining terms form the convective derivative, representing change caused by the particle moving through spatial gradients. The same operator applies to velocity, temperature, density, and other transported quantities.

For velocity, the material acceleration is

a = DV/Dt = ∂V/∂t + (V · ∇)V

In Cartesian components,

ax = ∂u/∂t + u ∂u/∂x + v ∂u/∂y + w ∂u/∂z

with analogous expressions for ay and az. Acceleration may therefore exist even in a steady flow, because convective acceleration can be nonzero.

2. Kinematic Structure of a Flow

2.1 Streamlines, pathlines, and streaklines

A streamline is a curve everywhere tangent to the instantaneous velocity vector. In Cartesian coordinates,

dx/u = dy/v = dz/w

where the velocities are evaluated at the same time. Streamlines are instantaneous geometric objects.

A pathline is the trajectory of one fluid particle through time. A streakline is the locus at one instant of all particles that have previously passed through a specified point, such as dye released continuously from an injector.

In steady flow, streamlines, pathlines, and streaklines coincide. In unsteady flow they generally differ. This distinction is essential when interpreting flow-visualization images: a dye photograph may show a streakline, not a streamline.

A stream surface is formed by streamlines passing through a prescribed curve. If the curve is closed, the resulting surface can act as a boundary of a streamtube. For an impermeable streamtube, fluid does not cross the lateral surface.

2.2 Acceleration in a converging passage

Consider steady one-dimensional flow through a converging duct. Although ∂V/∂t = 0, the velocity increases downstream as the area decreases. The acceleration is

as = V dV/ds

where s is distance along the streamline. Thus, “steady” means that properties at a fixed point do not vary with time; it does not mean that particles have zero acceleration.

2.3 Deformation and rotation

The velocity-gradient tensor is

∇V = [∂Vi/∂xj]

It can be decomposed into a symmetric strain-rate tensor and an antisymmetric rotation tensor:

∂Vi/∂xj = eij + Ωij

where

eij = 1/2 (∂Vi/∂xj + ∂Vj/∂xi)

and

Ωij = 1/2 (∂Vi/∂xj − ∂Vj/∂xi)

The tensor eij describes local deformation: extension, compression, and shear. Ωij describes rigid-body rotation of a small fluid element. The assumptions are local and continuum-based; these quantities do not describe the finite rotation of a large identifiable blob of fluid.

The divergence of velocity is

∇ · V = ∂u/∂x + ∂v/∂y + ∂w/∂z

It measures volumetric expansion rate per unit volume. For a material volume δV,

(1/δV) D(δV)/Dt = ∇ · V

Consequently, an incompressible motion satisfies ∇ · V = 0, even if the density field formulation requires care in variable-temperature or multiphase flows.

Vorticity is defined by

ω = ∇ × V

and the local angular velocity of a fluid element is one-half the vorticity,

Ωparticle = 1/2 ∇ × V

where the latter symbol denotes angular velocity, not the rotation tensor. A flow may have nonzero vorticity without every large-scale particle trajectory being a simple rigid-body rotation.

2.4 Irrotational flow and circulation

A flow is irrotational in a region if

∇ × V = 0

If the region is simply connected, an irrotational velocity field can be expressed using a velocity potential Φ:

V = ∇Φ

For incompressible irrotational flow, continuity gives

∇²Φ = 0

This is Laplace’s equation. It is powerful for idealized external-flow analysis, but real flows can contain viscous boundary layers, wakes, and separated regions where the assumptions fail.

The circulation around a closed curve C is

Γ = ∮C V · dr

Stokes’ theorem relates circulation to vorticity through any surface S bounded by C:

Γ = ∬S (∇ × V) · n dA

The relation assumes sufficient smoothness of the field and consistent orientation of the curve and surface normal.

3. Conservation of Mass

3.1 System and control volume

A system, or material volume, contains the same matter at all times. A control volume is a specified region in space through which mass may flow. Engineering devices such as pumps, turbines, nozzles, compressors, and heat exchangers are most conveniently analyzed as control volumes.

The Reynolds transport theorem converts a system balance into a control-volume balance. For any extensive property B with intensive counterpart b = B/m,

dBsystem/dt = d/dt ∫CV ρb dV + ∮CS ρb (V · n) dA

Here ρ is density in kg/m³, dV is a differential volume, n is the outward unit normal, and V · n is outward normal velocity. The control volume may be fixed or moving; for a moving control volume, relative flux velocity must be used.

3.2 Integral continuity equation

Applying the theorem to mass, for which B = m and b = 1, gives

d/dt ∫CV ρ dV + ∮CS ρ(V · n) dA = 0

This states that accumulation of mass inside the control volume plus net outward mass flow is zero. For discrete inlets and outlets,

dmCV/dt + ∑out ṁ − ∑in ṁ = 0

The mass flow rate through a section is

ṁ = ∫A ρ(V · n) dA

If density and normal velocity are approximately uniform,

ṁ ≈ ρAVn

where A is area in m² and Vn is average normal velocity in m/s. The units are kg/(m³) × m² × m = kg/s.

For steady flow through a control volume,

∑out ṁ = ∑in ṁ

For a steady, single-inlet, single-outlet streamtube,

ρ1 A1 V1 = ρ2 A2 V2

For constant-density flow this reduces to A1V1 = A2V2. This reduction is not valid for compressible flow unless density changes are negligible.

3.3 Differential continuity equation

Applying the divergence theorem to the integral equation yields the local form

∂ρ/∂t + ∇ · (ρV) = 0

Using the product rule,

Dρ/Dt + ρ ∇ · V = 0

For constant density following each particle, Dρ/Dt = 0, and therefore

∇ · V = 0

This is the incompressibility condition. It can be used for liquids under many conditions, but “liquid” and “incompressible” are not mathematically identical: pressure, temperature, dissolved gas, and phase change may produce significant density variation.

4. Conservation of Linear Momentum

4.1 General control-volume equation

Newton’s second law for a system is converted using the Reynolds transport theorem:

∑F = d/dt ∫CV ρV dV + ∮CS ρV(V · n) dA

The left side includes all external forces acting on the contents of the control volume. These may include pressure forces, viscous surface forces, body forces such as gravity, electromagnetic forces, and forces transmitted through supports.

For a steady control volume with uniform one-dimensional inlet and outlet sections,

∑F = ∑out ṁV − ∑in ṁV

The equation is vectorial. Applying it separately in each coordinate direction is usually necessary.

Pressure forces should not be omitted or double-counted. If pressure is atmospheric at all exposed sections and a gauge-pressure formulation is used, atmospheric contributions may cancel. Otherwise, absolute or gauge pressures must be treated consistently.

4.2 Momentum correction factor

When velocity is nonuniform across a section, the momentum flux is not exactly ṁVaverage. A momentum correction factor is sometimes introduced:

β = (1/(A V̄²)) ∫A V² dA

for constant density and predominantly one-dimensional flow. Here V̄ is the area-average velocity. The momentum flux is then β ρ A V̄². For a uniform profile, β = 1. In laminar fully developed pipe flow, β is larger than one; using unity without justification can introduce force errors.

4.3 Moving and accelerating control volumes

For a control volume translating with velocity VCV, the flux term uses relative velocity:

Vrel = V − VCV

A general moving-control-volume formulation also requires the acceleration of the control-volume reference frame when interpreting forces and momentum. This is important in rotating machinery, rocket propulsion, vehicle aerodynamics, and devices mounted on moving platforms.

5. Conservation of Angular Momentum

Taking moments about a fixed origin gives

∑MO = d/dt ∫CV r × ρV dV + ∮CS r × ρV(V · n) dA

where r is the position vector from the origin and MO is the moment about that origin. For steady one-dimensional flow,

∑MO = ∑out ṁ(r × V) − ∑in ṁ(r × V)

This equation is central to turbomachinery. The torque transmitted to a rotor is related to the change in angular momentum of the fluid. In cylindrical coordinates, the axial torque associated with swirl is often expressed as

T = ṁ(r2 V_θ2 − r1 V_θ1)

where V_θ is tangential velocity and the signs depend on the selected positive rotation direction. The equation assumes a steady control volume and negligible unsteady angular-momentum storage; shaft and pressure moments must be included if they act on the chosen control volume.

6. Conservation of Energy

6.1 First law for a control volume

The first law states that energy is conserved. For a control volume,

dECV/dt = Q̇ − Ẇ + ∑in ṁ(e + p/ρ + V²/2 + gz) − ∑out ṁ(e + p/ρ + V²/2 + gz)

Here Q̇ is heat transfer into the control volume, Ẇ is work done by the control volume, e is specific internal energy in J/kg, p/ρ is flow work expressed through enthalpy, V²/2 is specific kinetic energy, and gz is specific potential energy. The total specific enthalpy is h = e + p/ρ.

Thus the equation is often written

dECV/dt = Q̇ − Ẇ + ∑in ṁ(h + V²/2 + gz) − ∑out ṁ(h + V²/2 + gz)

The convention here defines Ẇ as work done by the control volume. Some texts define work input as positive; the convention must be stated before calculation.

For steady, single-inlet, single-outlet flow,

Q̇ − Ẇ = ṁ[(h2 − h1) + (V2² − V1²)/2 + g(z2 − z1)]

This is an energy-rate equation, with each term in watts when ṁ is kg/s and specific energies are J/kg.

6.2 Bernoulli equation as a special case

For steady, inviscid, incompressible flow along a streamline, with no shaft work, negligible heat transfer, and no significant change in internal energy beyond pressure work, the energy equation reduces to

p/ρ + V²/2 + gz = constant

or, in head form,

p/(ρg) + V²/(2g) + z = constant

The three terms represent pressure head, velocity head, and elevation head. Bernoulli’s equation is not a universal statement of energy conservation; it is a restricted mechanical-energy relation. Pumps, turbines, viscous losses, compressibility, heat transfer, and unsteady storage require an expanded equation.

For engineering systems, the extended energy equation is commonly written

p1/(ρg) + α1 V1²/(2g) + z1 + hp − ht = p2/(ρg) + α2 V2²/(2g) + z2 + hL

where hp is pump head added, ht is turbine head extracted, hL is head loss, and α is the kinetic-energy correction factor. This form is mainly applicable to steady, incompressible flow with section-averaged properties. It should not be used blindly for strongly compressible, transient, or multiphase flows.

7. Worked Examples

Example 1: Material acceleration

A two-dimensional steady velocity field is

V = (2x) i + (−2y) j m/s

where x and y are measured in metres. Determine the acceleration at (x,y) = (1,2) m.

Because the flow is steady, local acceleration is zero. The components are

ax = u ∂u/∂x + v ∂u/∂y = (2x)(2) + (−2y)(0) = 4x
ay = u ∂v/∂x + v ∂v/∂y = (2x)(0) + (−2y)(−2) = 4y

At (1,2),

a = 4 i + 8 j m/s²

The nonzero result illustrates convective acceleration in a steady flow. Also, ∇ · V = 2 − 2 = 0, so the field is incompressible.

Example 2: Mass conservation in a nozzle

Air enters a nozzle at ρ1 = 1.20 kg/m³, A1 = 0.010 m², and V1 = 30 m/s. At the exit, ρ2 = 0.90 kg/m³ and A2 = 0.006 m². Find the exit velocity for steady one-dimensional flow.

Continuity gives

ρ1 A1 V1 = ρ2 A2 V2

Therefore,

V2 = (1.20 × 0.010 × 30)/(0.90 × 0.006) = 66.7 m/s

The mass flow rate is ṁ = 1.20 × 0.010 × 30 = 0.360 kg/s. Density variation is essential; using the incompressible relation would give an incorrect result.

Example 3: Force on a reducing bend

Water flows steadily through a horizontal 90° bend. At the inlet, A1 = 0.010 m² and V1 = 4 m/s in the positive x-direction. At the outlet, A2 = 0.005 m² and the velocity is 4 m/s in the positive y-direction. Take ρ = 1000 kg/m³ and neglect pressure and weight effects by assuming gauge pressure is zero at both sections. Determine the force exerted by the fluid on the bend.

The mass flow rate is

ṁ = ρA1V1 = 1000 × 0.010 × 4 = 40 kg/s

The force exerted by the bend on the fluid is

Fbend→fluid = ṁ(V2 − V1) = 40[(0,4) − (4,0)] = (−160,160) N

Therefore, the force exerted by the fluid on the bend is the opposite:

Ffluid→bend = (160,−160) N

Its magnitude is √(160² + 160²) = 226 N. The example is deliberately idealized: real calculations must include pressure forces, bend weight, and nonuniform velocity profiles.

8. Applied Case: Flow Analysis of a Pumped Pipeline

Background

Consider an illustrative industrial water line transporting water from a storage tank to an elevated process vessel. The line contains a pump, a long pipe, valves, and two elbows. The design team must select a pump that delivers Q = 0.050 m³/s while avoiding excessive energy consumption and unreliable predictions of pressure.

Problem

The pipe diameter is 0.20 m, the downstream vessel is 12 m above the source free surface, and the total estimated head loss in the pipe and fittings is 8 m. The pump efficiency is 75 percent. Determine the hydraulic power required and identify the principal modeling decisions.

Analysis

The cross-sectional area is

A = πD²/4 = π(0.20)²/4 = 0.0314 m²

The mean pipe velocity is

V = Q/A = 0.050/0.0314 = 1.59 m/s

For large tanks, free-surface velocities are negligible. Applying the extended mechanical-energy equation between the two free surfaces gives the pump head

hp = (z2 − z1) + hL = 12 + 8 = 20 m

The hydraulic power transferred to the water is

Ph = ρgQhp

Using ρ = 1000 kg/m³ and g = 9.81 m/s²,

Ph = 1000 × 9.81 × 0.050 × 20 = 9810 W

The shaft power required, assuming pump efficiency η = 0.75, is

Pshaft = Ph/η = 9810/0.75 = 13.1 kW

Approach and engineering decisions

The calculation is a control-volume application of mass and energy conservation. The selected diameter determines velocity; velocity and roughness determine friction loss; fittings contribute local losses; and the pump operating point must satisfy both the system curve and the pump characteristic curve. A more refined design would include transient startup, water hammer, cavitation margin, temperature-dependent viscosity, measurement uncertainty, and off-design operation.

Outcome and learning points

The illustrative pump must supply approximately 20 m of head at 0.050 m³/s and approximately 13.1 kW of shaft power under the stated assumptions. The result is not a complete pump specification. Conservation laws establish the required balance, but reliable design also requires constitutive information, empirical loss coefficients, manufacturer data, safety margins, and verification by testing or validated simulation.

9. Limitations, Numerical Practice, and Contemporary Use

Conservation laws are exact statements within the continuum model, but practical predictions depend on closure relations and boundary conditions. Momentum equations require a stress model; energy equations require thermodynamic and heat-transfer models; multiphase systems require interphase exchange laws; and turbulence requires modeling or resolution of fluctuating scales.

In CFD, the differential conservation equations are discretized over finite volumes, finite elements, or finite differences. A sound numerical method should preserve conservation locally, maintain boundedness of transported quantities, and satisfy appropriate stability and convergence requirements. Grid refinement, residual monitoring, integral balance checks, and comparison with analytical or experimental benchmarks are essential. A visually smooth CFD field is not evidence of physical validity.

AI and machine learning are increasingly used for reduced-order models, turbulence closure, flow-field reconstruction, and rapid surrogate prediction. Their use must remain subordinate to physical conservation. A learned model should be tested for dimensional consistency, extrapolation behavior, conservation error, uncertainty, and sensitivity to boundary conditions. In safety-critical applications, traceability and independent validation are necessary.

Professional practice also requires responsible measurement and reporting. Mass, momentum, and energy balances should close within stated uncertainty. Pressure references, sign conventions, coordinate systems, averaging procedures, and assumptions should be documented. Omitting a force or silently switching between gauge and absolute pressure can create apparently plausible but physically incorrect results.

Chapter Summary

Fluid kinematics describes motion through Eulerian fields or Lagrangian particle histories. The material derivative separates local and convective change and gives the acceleration of a fluid particle. Streamlines, pathlines, and streaklines coincide only in steady flow. The velocity-gradient tensor identifies deformation and rotation; divergence measures volumetric expansion, while vorticity measures local rotation.

The Reynolds transport theorem connects system laws to control-volume equations. Conservation of mass produces integral and differential continuity equations. Conservation of linear momentum predicts resultant forces, conservation of angular momentum governs torque and turbomachinery action, and conservation of energy relates heat, work, enthalpy, kinetic energy, and potential energy. Bernoulli’s equation is a restricted special case, not a substitute for the general energy equation.

Engineering application requires careful definition of the control volume, consistent signs and pressure references, appropriate averaging, and recognition of compressibility, viscous losses, unsteadiness, turbulence, and multiphase effects. Modern CFD and AI tools extend analysis but do not replace physical modeling, validation, and conservation checks.

Key Terms

Material derivative: Rate of change experienced by a moving fluid particle.

Local derivative: Time rate of change observed at a fixed spatial location.

Convective derivative: Change caused by movement through spatial gradients.

Eulerian description: Representation of fluid properties at fixed points in space.

Lagrangian description: Representation based on tracking individual fluid particles.

Streamline: Curve everywhere tangent to the instantaneous velocity vector.

Pathline: Trajectory followed by one fluid particle.

Streakline: Locus of particles that have passed through a specified point.

Vorticity: Curl of the velocity field, ∇ × V.

Strain-rate tensor: Symmetric part of the velocity-gradient tensor.

Divergence: Scalar ∇ · V measuring volumetric expansion rate.

Control volume: Selected region in space used for balance analysis.

System: Fixed collection of matter.

Mass flow rate: Rate at which mass crosses a section, measured in kg/s.

Reynolds transport theorem: Relation converting system balances to control-volume balances.

Momentum correction factor: Factor accounting for nonuniform momentum flux.

Circulation: Line integral of velocity around a closed curve.

Bernoulli equation: Restricted mechanical-energy relation for idealized flow.

Head loss: Mechanical-energy loss per unit weight, usually associated with dissipation.

Continuum assumption: Modeling matter as continuously distributed fields.

Review Questions

Short Answer Questions

  1. Distinguish between Eulerian and Lagrangian descriptions of fluid motion.
  2. Why can a steady flow have nonzero acceleration?
  3. Define vorticity and state its relation to local angular velocity.
  4. State the integral continuity equation for a fixed control volume.
  5. List the principal assumptions required for the elementary Bernoulli equation.

Long Answer Questions

  1. Derive the material derivative for a scalar field and explain the physical meaning of its local and convective terms.
  2. Explain streamlines, pathlines, and streaklines, including the condition under which they coincide.
  3. Derive the differential continuity equation from the integral control-volume equation.
  4. Develop the linear-momentum equation for a steady control volume and discuss pressure, body, and surface forces.
  5. Explain the control-volume energy equation and derive the extended mechanical-energy equation for steady incompressible flow.

Analytical / Application Questions

  1. For the velocity field V = (3x) i + (−2y) j + (z) k, determine ∇ · V, ∇ × V, and the material acceleration at (x,y,z) = (1,2,3) m. Interpret the result.
  2. Water flows through a horizontal reducer from a 0.10 m diameter pipe at 2 m/s to a 0.05 m diameter pipe. Assuming steady incompressible flow, determine the downstream velocity and mass flow rate. State which assumptions would fail if cavitation occurred.
  3. Design a control-volume analysis for a centrifugal pump installation. Specify the control-volume boundaries, required measurements, governing conservation laws, likely uncertainty sources, and validation checks before approving the installation.

Multiple Choice Questions with Answers

Question 1

Which expression gives the material derivative of a scalar field φ?

A. ∂φ/∂t only

B. ∂φ/∂t + V · ∇φ

C. ∇ × φ

D. ∇ · V

Correct Answer: B. ∂φ/∂t + V · ∇φ

Question 2

In a steady converging duct, fluid acceleration can be nonzero because of

A. local acceleration only

B. zero density everywhere

C. convective acceleration

D. absence of pressure gradients

Correct Answer: C. convective acceleration

Question 3

For steady one-inlet, one-outlet flow, the mass continuity relation is

A. ρ1 A1 V1 = ρ2 A2 V2

B. A1/V1 = A2/V2

C. ρ1 + A1 + V1 = ρ2 + A2 + V2

D. ρ1 A1 = ρ2 V2

Correct Answer: A. ρ1 A1 V1 = ρ2 A2 V2

Question 4

The differential continuity equation for a compressible fluid is

A. ∇ × V = 0

B. ∂ρ/∂t + ∇ · (ρV) = 0

C. ∇ · V = 1

D. Dρ/Dt = ρ∇ · V

Correct Answer: B. ∂ρ/∂t + ∇ · (ρV) = 0

Question 5

Vorticity is defined as

A. ∇ · V

B. ∇²V

C. ∇ × V

D. V · ∇V

Correct Answer: C. ∇ × V

Question 6

A uniform velocity profile has a momentum correction factor equal to

A. 0

B. 0.5

C. 1

D. 2

Correct Answer: C. 1

Question 7

The control-volume form of linear momentum equates the net external force to

A. the heat-transfer rate

B. the rate of change and flux of momentum

C. the mass accumulation only

D. the circulation around the boundary

Correct Answer: B. the rate of change and flux of momentum

Question 8

For the stated convention in this chapter, the steady-flow energy equation contains work as

A. Q̇ + Ẇ on the left side

B. Q̇ − Ẇ on the left side

C. Ẇ − Q̇ on the right side only

D. work is always zero

Correct Answer: B. Q̇ − Ẇ on the left side

Question 9

A pump adds 20 m of head to water flowing at 0.050 m3/s. Taking ρ = 1000 kg/m3 and g = 9.81 m/s2, the hydraulic power is approximately

A. 0.981 kW

B. 4.91 kW

C. 9.81 kW

D. 19.6 kW

Correct Answer: C. 9.81 kW

Question 10

The elementary Bernoulli equation is most directly applicable to

A. steady, inviscid, incompressible flow along a streamline without shaft work

B. all turbulent flows through pumps

C. unsteady multiphase flow with heat addition

D. compressible flow with arbitrary shocks and losses

Correct Answer: A. steady, inviscid, incompressible flow along a streamline without shaft work

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